PYQ Vault
EbooksTutor

Amplitude from the velocity at a given time after passing the mean position

The same question, asked 2 times: 11 May 2023 S1*, 14 May 2026 S2. Every wording below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    11 May 2023 S1

    32
    A particle performing S.H.M. starts from equilibrium position and its time period is 12 second. After 2 seconds its velocity is π\pi m/s. Amplitude of the oscillation is sin⁡30∘=cos⁡60∘=0.5\sin 30^\circ = \cos 60^\circ = 0.5, sin⁡60∘=cos⁡30∘=3/2\sin 60^\circ = \cos 30^\circ = \sqrt{3}/2

    Tap an option to check your answer.

  2. Question 2

    14 May 2026 S2

    120
    A particle executes S.H.M. with time period 1616 s. At time t=2t = 2 s, the particle crosses the mean position while at t=4t = 4 s, velocity is 44 m/s. The amplitude of motion (in m) is (sin⁡45∘=12)\left(\sin 45^\circ = \dfrac{1}{\sqrt{2}}\right)

    Tap an option to check your answer.