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Speed of a pendulum bob from energy conservation

This type of question, asked 2 times: 16 May 2023 S2, 21 Apr 2025 S2. All 2 questions below, oldest first.

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  1. Question 1

    16 May 2023 S2

    6
    The bob of a pendulum of length ll is pulled aside from its equilibrium position through an angle θ\theta and then released. The bob will then pass through its equilibrium position with speed vv, where vv equals (g=g = acceleration due to gravity)

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  2. Question 2

    21 Apr 2025 S2

    45
    A pendulum bob has a speed 4 m/s4\text{ }m/s at its lowest position. The pendulum is 1 m long. When the length of the string makes an angle of 60∘60^{\circ} with the vertical, the speed of the bob at that position is (acceleration due to gravity, g=10 m/s2g = 10\text{ }m/s^{2}, cos⁡60∘=0.5\cos60^{\circ}= 0.5 )

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