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Rod bent into a ring: ratio of the rod's moment of inertia to the ring's about a diameter

The same question, asked 3 times: 21 Apr 2025 S2, 26 Apr 2025 S1, 13 May 2026 S1. Every wording below, oldest first.

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  1. Question 1

    21 Apr 2025 S2

    41
    Moment of inertia of a thin uniform rod rotating about the perpendicular axis passing through its center is 'I'. If the same rod is bent in the form of ring, its moment of inertia about the diameter is ' I1I_{1} '. If I1=xII_{1}=xI, then the value of ' xx ' is

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  2. Question 2

    26 Apr 2025 S1

    41
    Moment of inertia of the rod about an axis passing through the center and perpendicular to its length is ' I1I_{1} '. The same rod is bent into a ring and its moment of inertia about the diameter is ' I2I_{2} '. Then I1/I2I_{1}/I_{2} is

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  3. Question 3

    13 May 2026 S1

    107
    Moment of inertia of a thin uniform rod rotating about the perpendicular axis passing through its centre is I. If the same rod is bent in to a ring and its moment of inertia about its diameter is I1I_1, then the ratio I/I1I/I_1 is

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