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Ratio E1/E2 from balancing lengths with the cells aiding and then opposing

The same question, asked 3 times: 10 May 2023 S1*, 11 May 2024 S1*, 14 May 2024 S2. Every wording below, oldest first.

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  1. Question 1

    10 May 2023 S1

    32
    In potentiometer experiment, cells of e.m.f. E1E_1 and E2E_2 are connected in series (E1>E2)(E_1>E_2), the balancing length is 80 cm of the wire. If the polarity of E2E_2 is reversed, the balancing length becomes 20 cm. The ratio E1E2\frac{E_1}{E_2} is

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  2. Question 2

    11 May 2024 S1

    38
    In potentiometer experiments, two cells of e.m.f. E1E_1 and E2E_2 are connected in series E1>E2E_1 > E_2, the balancing length is 64 cm of the wire. If the polarity of E2E_2 is reversed, the balancing length becomes 32 cm. The ratio E1/E2E_1/E_2 is

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  3. Question 3

    14 May 2024 S2

    49
    In potentiometer experiment, the balancing length is 8 m when two cells E1E_1 and E2E_2 are joined in series. When two cells are connected in opposition the balancing length is 4 m. The ratio of the e.m.f. of the two cells E1E2\frac{E_1}{E_2} is

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