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Relation between alpha and beta of a transistor

This type of question, asked 4 times: 11 May 2024 S2, 14 May 2024 S1, 19 Apr 2025 S1, 26 Apr 2025 S2. All 4 questions below, oldest first.

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  1. Question 1

    11 May 2024 S2

    10
    In the study of transistor as an amplifier if α=ICIE=0.98\alpha = \frac{I_C}{I_E} = 0.98 and β=ICIb=49\beta = \frac{I_C}{I_b} = 49, where IC,IgI_C, I_g and IEI_E are collector, base and emitter current respectively then 1α−1β\frac{1}{\alpha} - \frac{1}{\beta} is equal to

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  2. Question 2

    14 May 2024 S1

    35
    For a common emitter configuration, if 'α\alpha' and 'β\beta' have their usual meanings, the incorrect relation between 'α\alpha' and 'β\beta' is:

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  3. Question 3

    19 Apr 2025 S1

    49
    In the case of constant ' α\alpha ' and ' β\beta ' of a transistor ( α\alpha and β\beta are current ratios)

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  4. Question 4

    26 Apr 2025 S2

    36
    For a transistor, αdc\alpha_{dc} and βdc\beta_{dc} are the current ratios, then the value of βdc−αdcαdc×βdc\frac{\beta_{dc}-\alpha_{dc}}{\alpha_{dc}\times\beta_{dc}}.

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