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Observer moves towards and then away from a stationary source with the same speed and F1/F2 = 2: find V/V1

The same question, asked 4 times: 10 May 2023 S1, 20 Apr 2025 S1, 26 Apr 2025 S2, 16 Apr 2026 S1. Every wording below, oldest first.

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  1. Question 1

    10 May 2023 S1

    29
    When the listener moves towards stationary source with velocity 'V1V_1', the apparent frequency of emitted note is 'F1F_1'. When observer moves away from the source with velocity 'V1V_1', apparent frequency is 'F2F_2'. If V is the velocity of sound in air and F1F2=2\frac{F_1}{F_2}=2, then VV1\frac{V}{V_1} is

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  2. Question 2

    20 Apr 2025 S1

    6
    When an observer moves towards a stationary source with velocity ' V1V_{1} ', the apparent frequency of emitted note is ' F1F_{1} '. When observer moves away from stationary source with velocity ' V1V_{1} ' the apparent frequency is ' F2F_{2} '. If ' v ' is velocity of sound in air and F1 F2=2\frac{F_{1}}{{\text{ }F}_{2}}= 2, then VV1\frac{V}{V_{1}} is equal to

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  3. Question 3

    26 Apr 2025 S2

    17
    When the observer moves towards a stationary source with velocity V1V_{1}, the apparent frequency of emitted note is F1F_{1}. When observer moves away from the source with velocity V1V_{1}, the apparent frequency is F2F_{2}. If VV is the velocity of sound in air and F1/F2=2F_{1}/F_{2}= 2 then V/V1V/V_{1} is equal to

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  4. Question 4

    16 Apr 2026 S1

    123
    When the observer moves towards a stationary source with velocity 'V1V_1', the apparent frequency of the emitted note is 'F1F_1'. When the observer moves away from the source with velocity 'V1V_1', the apparent frequency is 'F2F_2'. If 'V' is the speed of sound in air and F1/F2=2F_1/F_2 = 2, then V/V1=V/V_1 =

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