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Potentiometer: comparing emfs with the cells aiding and opposing (sum and difference method)

This type of question, asked 9 times: 2 May 2023 S2, 10 May 2023 S1, 11 May 2024 S1, 12 May 2024 S1, 14 May 2024 S2, 22 Apr 2025 S2, 18 Apr 2026 S2, 19 Apr 2026 S1, 19 May 2026 S2. All 9 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    2 May 2023 S2

    17
    When a cell of E.M.F. 'E1_1' is connected to a potentiometer wire, the balancing length is l1l_1. Another cell of E.M.F. 'E2_2' (E1>E2E_1 > E_2) is connected so that the two cells oppose each other, then the balancing length is l2l_2. The ratio E1:E2E_1 : E_2 is

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  2. Question 2

    10 May 2023 S1

    32
    In potentiometer experiment, cells of e.m.f. E1E_1 and E2E_2 are connected in series (E1>E2)(E_1>E_2), the balancing length is 80 cm of the wire. If the polarity of E2E_2 is reversed, the balancing length becomes 20 cm. The ratio E1E2\frac{E_1}{E_2} is

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  3. Question 3

    11 May 2024 S1

    38
    In potentiometer experiments, two cells of e.m.f. E1E_1 and E2E_2 are connected in series E1>E2E_1 > E_2, the balancing length is 64 cm of the wire. If the polarity of E2E_2 is reversed, the balancing length becomes 32 cm. The ratio E1/E2E_1/E_2 is

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  4. Question 4

    12 May 2024 S1

    47
    A potentiometer wire has length of 5 m and resistance of 16 Ω16\,\Omega. The driving cell has an e.m.f. of 5 V and an internal resistance of 4 Ω4\,\Omega. When the two cells of e.m.f.s 1.3 V and 1.1 V are connected so as to assist each other and then oppose each other, the balancing lengths are respectively

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  5. Question 5

    14 May 2024 S2

    49
    In potentiometer experiment, the balancing length is 8 m when two cells E1E_1 and E2E_2 are joined in series. When two cells are connected in opposition the balancing length is 4 m. The ratio of the e.m.f. of the two cells E1E2\frac{E_1}{E_2} is

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  6. Question 6

    22 Apr 2025 S2

    16
    When cell of e.m.f. 'E1E_1' is connected to potentiometer wire, the balancing length is 'l1l_1'. Another cell of e.m.f. 'E2E_2' (E1>E2)(E_1 > E_2) is connected so that two cells oppose each other, the balancing length is '[l2][l_2]'. The ratio E1:E2E_1 : E_2 is

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  7. Question 7

    18 Apr 2026 S2

    129
    When cell of E.M.F. 'E1E_1' is connected to potentiometer wire the balancing length is 'l1l_1'. Another cell of E.M.F. 'E2E_2' (E1>E2)(E_1 > E_2) is connected along with E1E_1 so as two cells oppose each other, the balancing length is 'l2l_2'. The ratio E1:E2E_1 : E_2 is

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  8. Question 8

    19 Apr 2026 S1

    128
    In a potentiometer circuit when two cells of e.m.f. 1.51.5 volt and 1.21.2 volt are connected to assist each other, balancing length is 270270 cm. What will be the balancing length in cm when these two cells are connected in opposition?

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  9. Question 9

    19 May 2026 S2

    129
    In a potentiometer circuit when two cells of emf 1.61.6 V and 1.31.3 V are connected to assist each other, the balancing length is 290290 cm. What will be the balancing length in cm when these two cells are connected in opposition?

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