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Composite slab of conductivities K and 2K, thicknesses x and 4x: factor f in the rate of heat flow

The same question, asked 3 times: 12 May 2024 S1, 19 Apr 2025 S2, 17 Apr 2026 S2. Every wording below, oldest first.

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  1. Question 1

    12 May 2024 S1

    31
    A composite slab consists of two materials having coefficient of thermal conductivity KK and 2K2K, thickness xx and 4x4x respectively. The temperature of the two outer surfaces of a composite slab are T2T_{2} and T1T_{1} and T2>T1T_{2}>T_{1}. The rate of heat transfer through the slab in a steady state is A(T2−T1)Kx⋅f\frac{A(T_{2}-T_{1})K}{x}\cdot f where ff is equal to

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  2. Question 2

    19 Apr 2025 S2

    17
    A composite slab consists of two materials having coefficients of thermal conductivity K and 2 K , thickness x and 4 x respectively. The temperatures of two outer surfaces of a composite slab are T2T_{2} and T1T_{1} respectively (T2>T1)\left( T_{2}>T_{1} \right). The rate of heat transfer through the slab in a steady state is [A(T2−T1)Kx]f\left\lbrack \frac{A\left( T_{2}-T_{1} \right)K}{x} \right\rbrack f, where ff is equal to

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  3. Question 3

    17 Apr 2026 S2

    113
    In a composite slab there are two materials having coefficients of thermal conductivity K and 2K, thickness x and 4x repectively. The temperature of the two outer surfaces of a composite slab are T2T_2 and T1 (T2>T1)T_1\ (T_2 > T_1). T2T_2 is on side K and T1T_1 is on side 2K. The rate of heat transfer through the slab in a steady state is [A(T2−T1)Kx]⋅f\left[\dfrac{A(T_2 - T_1)K}{x}\right]\cdot f, where f is equal to

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