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Isobaric process of an ideal gas: ratio of heat supplied and work done in terms of gamma

The same question, asked 5 times: 4 May 2023 S1*, 9 May 2023 S1*, 9 May 2023 S2*, 22 Apr 2025 S2*, 14 May 2026 S2. Every wording below, oldest first.

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  1. Question 1

    4 May 2023 S1

    41
    In an isobaric process of an ideal gas, the ratio of work done by the system to the heat supplied WQ\frac{W}{Q} is

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  2. Question 2

    9 May 2023 S1

    42
    For an ideal gas, in an isobaric process, the ratio of heat supplied QQ to the work done WW by the system is (γ\gamma = ratio of specific heat at constant pressure to that at constant volume)

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  3. Question 3

    9 May 2023 S2

    42
    In an isobaric process of an ideal gas, the ratio of work done by the system (W) during the expansion and the heat exchanged (Q) is γ=CpCv\gamma = \frac{C_p}{C_v}

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  4. Question 4

    22 Apr 2025 S2

    50
    In an isobaric process of an ideal gas, the ratio of heat supplied and work done by the system (QW)\left( \frac{Q}{W} \right) is [CpCv=γ]\left\lbrack \frac{C_{p}}{C_{v}}= \gamma \right\rbrack.

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  5. Question 5

    14 May 2026 S2

    114
    If the ratio of molar heat capacities CpCv=γ\dfrac{C_p}{C_v} = \gamma then the ratio of ΔQΔU\dfrac{\Delta Q}{\Delta U} and ΔQΔW\dfrac{\Delta Q}{\Delta W} in an isobaric process is

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