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(a^3 + b^3 + c^3 - 3abc)/(a^2 + b^2 + c^2 - ab - bc - ca) with numbers

The same question, asked 2 times: 9 Sep 2024 S2*, 23 Sep 2024 S1. Every wording below, oldest first.

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  1. Question 1

    9 Sep 2024 S2

    53
    Simplify (8.3)3+(9.2)3+(6.1)3−3×8.3×9.2×6.1(8.3)2+(9.2)2+(6.1)2−8.3×9.2−9.2×6.1−6.1×8.3\frac{(8.3)^3 + (9.2)^3 + (6.1)^3 - 3 \times 8.3 \times 9.2 \times 6.1}{(8.3)^2 + (9.2)^2 + (6.1)^2 - 8.3 \times 9.2 - 9.2 \times 6.1 - 6.1 \times 8.3}

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  2. Question 2

    23 Sep 2024 S1

    55
    Simplify. (232)3+(140)3+(353)3−3×232×140×353(232)2+(140)2+(353)2−232×140−140×353−353×232\frac{(232)^3+(140)^3+(353)^3-3\times232\times140\times353}{(232)^2+(140)^2+(353)^2-232\times140-140\times353-353\times232}

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