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a + b + c = 0 so a^3 + b^3 + c^3 = 3abc

This type of question, asked 6 times: 14 Jul 2023 S2, 24 Sep 2024 S3, 17 Sep 2025 S1, 17 Sep 2025 S3, 19 Sep 2025 S1, 19 Sep 2025 S2. All 6 questions below, oldest first.

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  1. Question 1

    14 Jul 2023 S2

    63
    What is the value of a3+b3+c3a^3 + b^3 + c^3 if (a+b+c)=0(a + b + c) = 0?

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  2. Question 2

    24 Sep 2024 S3

    58
    If a+b=ca + b = c, then the expression a3+b3−c3+3abca^3 + b^3 - c^3 + 3abc will be equal to:

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  3. Question 3

    17 Sep 2025 S1

    75
    If a=0.02a = 0.02, b=0.03b = 0.03, c=−0.05c = -0.05, and a+b+c=0a + b + c = 0, find (a3+b3+c3)÷(3abc)(a^3 + b^3 + c^3) \div (3abc)

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  4. Question 4

    17 Sep 2025 S3

    71
    193+203−393+11819^3 + 20^3 - 39^3 + 118 is equal to:

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  5. Question 5

    19 Sep 2025 S1

    75
    What is the result of (0.53+0.13−0.63)÷(3×0.5×0.1×0.6)(0.5^3 + 0.1^3 - 0.6^3) \div (3 \times 0.5 \times 0.1 \times 0.6)?

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  6. Question 6

    19 Sep 2025 S2

    74
    If a+b+c=0a + b + c = 0 and a=0.1a = 0.1, b=0.2b = 0.2, c=−0.3c = -0.3, then what is (a3+b3+c3)÷(3abc)(a^3 + b^3 + c^3) \div (3abc)?

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