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BC produced to D, AC = BC, angle BAC = 70: a combination of angle ACD and angle ABC

The same question, asked 2 times: 25 Sep 2024 S1*, 26 Sep 2024 S2. Every wording below, oldest first.

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  1. Question 1

    25 Sep 2024 S1

    60
    The side BC of △ABC\triangle ABC is produced to a point D. If AC = BC and ∠BAC=70∘\angle BAC = 70^\circ, then find the value of ∠ACD−∠ABC\angle ACD - \angle ABC.

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  2. Question 2

    26 Sep 2024 S2

    53
    The side BC of △\triangleABC is produced to a point D. If AC = BC and ∠\angleBAC = 70∘70^\circ, then find the value of 2.5∠ACD−1.5∠ABC2.5\angle ACD - 1.5\angle ABC.

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