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(sin^3 +/- cos^3)/(sin +/- cos) = 1 -/+ sin cos

This type of question, asked 2 times: 14 Jul 2023 S4, 9 Sep 2024 S2. All 2 questions below, oldest first.

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  1. Question 1

    14 Jul 2023 S4

    71
    Simplify the following. sin⁡3α+cos⁡3αsin⁡α+cos⁡α\frac{\sin^3\alpha + \cos^3\alpha}{\sin\alpha + \cos\alpha}

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  2. Question 2

    9 Sep 2024 S2

    62
    Simplify the following. sin⁡3A−cos⁡3Asin⁡A−cos⁡A\frac{\sin^3 A - \cos^3 A}{\sin A - \cos A}, where A is an acute angle.

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