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(sin - 2sin^3)/(2cos^3 - cos) = tan

This type of question, asked 2 times: 21 Jul 2023 S3, 12 Sep 2024 S1. All 2 questions below, oldest first.

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  1. Question 1

    21 Jul 2023 S3

    67
    Simplify the following expression. sin⁡θ−2sin⁡3θ2cos⁡3θ−cos⁡θ\frac{\sin\theta - 2\sin^3\theta}{2\cos^3\theta - \cos\theta}

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  2. Question 2

    12 Sep 2024 S1

    75
    The value of (sin⁡θ−2sin⁡3θ2cos⁡3θ−cos⁡θ)31tan⁡θ−sec⁡2θ\left(\frac{\sin\theta - 2\sin^3\theta}{2\cos^3\theta - \cos\theta}\right)^3 \frac{1}{\tan\theta} - \sec^2\theta is:

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