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3(cot^2 47 - sec^2 43)-style complementary pairs over cosec^2(68 + theta) - tan(theta + 61) - ... : find the value

The same question, asked 2 times: 29 Jan 2022 Tier II*, 3 Feb 2022 Tier II. Every wording below, oldest first.

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  1. Question 1

    29 Jan 2022 Tier II

    9
    The value of 3(cot⁡247∘−sec⁡243∘)−2(tan⁡223∘−cosec267∘)cosec2(68∘+θ)−tan⁡(θ+61∘)−tan⁡2(22∘−θ)+cot⁡(29∘−θ)\frac{3(\cot^2 47^\circ - \sec^2 43^\circ) - 2(\tan^2 23^\circ - \text{cosec}^2 67^\circ)}{\text{cosec}^2(68^\circ + \theta) - \tan(\theta + 61^\circ) - \tan^2(22^\circ - \theta) + \cot(29^\circ - \theta)} is:

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  2. Question 2

    3 Feb 2022 Tier II

    13
    The value of 3(cosec226∘−tan⁡264∘)+(cot⁡242∘−sec⁡248∘)cot⁡(22∘−θ)−cosec2(62∘+θ)−tan⁡(θ+68∘)+tan⁡2(28∘−θ)\frac{3(\text{cosec}^2 26^\circ - \tan^2 64^\circ) + (\cot^2 42^\circ - \sec^2 48^\circ)}{\cot(22^\circ - \theta) - \text{cosec}^2(62^\circ + \theta) - \tan(\theta + 68^\circ) + \tan^2(28^\circ - \theta)} is:

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