Beyond the book
Concept 17 of 17 in Integrals
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∫02[x] dx=1\int_0^2 [x]\,dx = 1∫02[x]dx=1, where [x][x][x] is the greatest integer not more than xxx. Is ∫02[2x] dx\int_0^2 [2x]\,dx∫02[2x]dx twice that, 222?
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