Evaluating
Concept 12 of 17 in Integrals
1 / 12
Asha puts u=x2u = x^2u=x2 in ∫122x ex2 dx\int_1^2 2x\,e^{x^2}\,dx∫122xex2dx, gets ∫eu du\int e^u\,du∫eudu, and writes [eu]12=e2−e\left[e^u\right]_1^2 = e^2 - e[eu]12=e2−e. Is she right?
Loading…