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Equations that reduce to the standard forms

Trigonometric equations

Concept 5 of 15 in Trigonometric Functions

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Think about this

Solve sin⁡θ=tan⁡θ\sin\theta = \tan\theta by dividing both sides by sin⁡θ\sin\theta: 1=1cos⁡θ1 = \frac{1}{\cos\theta}, so cos⁡θ=1\cos\theta = 1 and θ=2nπ\theta = 2n\pi. But θ=π\theta = \pi works too: sin⁡π=0=tan⁡π\sin\pi = 0 = \tan\pi. Where did it go?