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MH HSC 12 Maths

Indefinite Integration

Each concept is a short lesson, then questions until you get three right.

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11 concepts, a short lesson each

  • Antiderivatives0/2
  • Substitution0/3
  • Quadratic forms0/3
  • Parts and partial fractions0/3

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Integration as the reverse of differentiation

∫f(x) dx=F(x)+c\int f(x)\,dx = F(x) + c when F′(x)=f(x)F'(x) = f(x); use the standard formulae term by term, e.g. ∫xn dx=xn+1n+1+c\int x^n\,dx = \dfrac{x^{n+1}}{n+1} + c for n≠−1n \ne -1

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Antiderivatives0 of 2

  1. Integration as the reverse of differentiation∫f(x) dx=F(x)+c\int f(x)\,dx = F(x) + c when F′(x)=f(x)F'(x) = f(x); use the standard formulae term by term, e.g. ∫xn dx=xn+1n+1+c\int x^n\,dx = \dfrac{x^{n+1}}{n+1} + c for n≠−1n \ne -1Start
  2. Rewriting before integratingExpand, divide out or use an identity first (sin⁡2x=1−cos⁡2x2\sin^2 x = \frac{1 - \cos 2x}{2}, tan⁡2x=sec⁡2x−1\tan^2 x = \sec^2 x - 1) so every term matches a standard formStart

Substitution0 of 3

  1. Integration by substitutionPut u=g(x)u = g(x) so that g′(x) dx=dug'(x)\,dx = du: ∫f(g(x)) g′(x) dx=∫f(u) du\int f(g(x))\,g'(x)\,dx = \int f(u)\,du; in particular ∫f′(x)f(x) dx=log⁡∣f(x)∣+c\int \dfrac{f'(x)}{f(x)}\,dx = \log|f(x)| + cStart
  2. Powers and products of trigonometric functionsTurn products into sums (2cos⁡Acos⁡B=cos⁡(A+B)+cos⁡(A−B)2\cos A\cos B = \cos(A + B) + \cos(A - B)); for sin⁡mxcos⁡nx\sin^m x\cos^n x with an odd power, keep one factor and substitute for the other functionStart
  3. The substitution t = tan(x/2)For ∫dxa+bsin⁡x\int \dfrac{dx}{a + b\sin x} or dxa+bcos⁡x\dfrac{dx}{a + b\cos x}, put t=tan⁡x2t = \tan\dfrac{x}{2}: sin⁡x=2t1+t2\sin x = \dfrac{2t}{1 + t^2}, cos⁡x=1−t21+t2\cos x = \dfrac{1 - t^2}{1 + t^2}, dx=2 dt1+t2dx = \dfrac{2\,dt}{1 + t^2}Start

Quadratic forms0 of 3

  1. Standard integrals of quadratic forms∫dxx2+a2=1atan⁡−1xa\int \dfrac{dx}{x^2 + a^2} = \dfrac{1}{a}\tan^{-1}\dfrac{x}{a}, ∫dxx2−a2=12alog⁡∣x−ax+a∣\int \dfrac{dx}{x^2 - a^2} = \dfrac{1}{2a}\log\left|\dfrac{x - a}{x + a}\right|, ∫dxa2−x2=sin⁡−1xa\int \dfrac{dx}{\sqrt{a^2 - x^2}} = \sin^{-1}\dfrac{x}{a}, and the rest of the tableStart
  2. Completing the squareWrite ax2+bx+cax^2 + bx + c as a[(x+p)2±q2]a\left[(x + p)^2 \pm q^2\right], then use the standard form with x+px + p in place of xxStart
  3. Integrals of (px + q) over a quadraticWrite px+q=A ddx(ax2+bx+c)+Bpx + q = A\,\dfrac{d}{dx}(ax^2 + bx + c) + B; the AA part gives a log or a root, the BB part a standard quadratic formStart

Parts and partial fractions0 of 3

  1. Integration by parts∫u v dx=u∫v dx−∫(u′∫v dx)dx\int u\,v\,dx = u\int v\,dx - \int \left(u'\int v\,dx\right)dx; choose uu by LIATE (log, inverse trig, algebraic, trig, exponential)Start
  2. Special forms from integration by parts∫ex[f(x)+f′(x)]dx=exf(x)+c\int e^x\left[f(x) + f'(x)\right]dx = e^x f(x) + c; ∫a2−x2 dx\int \sqrt{a^2 - x^2}\,dx and its relatives; integrals that return to themselves, like ∫exsin⁡x dx\int e^x\sin x\,dxStart
  3. Integration by partial fractionsSplit a proper rational function into Ax−a+Bx−b+…\dfrac{A}{x - a} + \dfrac{B}{x - b} + \dots (repeated and quadratic factors too), then integrate each pieceStart

Practise Indefinite Integration

Once the concepts click, try the questions your exam asks.