MHT-CET Maths · Differential Equations

Order, Degree, Formation, and Verification

The order is the highest derivative present; the degree is the power of that highest derivative once the equation is made polynomial in its derivatives; n independent arbitrary constants force an order-n differential equation, which you build by differentiating and eliminating the constants — or verify by substituting a proposed solution back.

Why this matters

This is the entire MHT-CET differential-equations subtopic and it is a mark-bank: 33 PYQs sit here, spanning EASY definitional order/degree right up to HARD elimination of circle and parabola families. Two mechanical skills carry almost every question — read order/degree only AFTER clearing radicals and fractional powers, and form a family's equation by differentiating once per independent constant and eliminating. The recurring traps are exactly three: the degree is undefined when a derivative sits inside a log/trig, redundant constants (like C₃e^{x+C₄}) must be collapsed before you count the order, and only INDEPENDENT constants count.

Concept 1 of 9

Differential Equation Terminology

Intuition

Before classifying anything, fix the vocabulary. A differential equation relates a function to its derivatives. Its order and degree are two independent labels; its solution comes in two flavours — a general solution carrying arbitrary constants, and a particular solution with those constants pinned down by conditions.

Definition

The vocabulary you must have cold:

  • Differential equation: an equation involving derivatives of an unknown function, e.g. dydx=3x\dfrac{dy}{dx} = 3x or d2ydx2+4y=0\dfrac{d^2y}{dx^2} + 4y = 0.
  • Order: the order of the highest derivative present.
  • Degree: the power of the highest-order derivative once the equation is polynomial in its derivatives.
  • Arbitrary constants: free parameters (a,b,c,C1,a, b, c, C_1, \dots) in a solution family.
  • General solution: contains as many independent arbitrary constants as the order.
  • Particular solution: a general solution with its constants fixed by given conditions.

The master link

order of the ODE  =  number of independent arbitrary constants in its general solution\text{order of the ODE} \;=\; \text{number of independent arbitrary constants in its general solution}
  • orderorder of the highest derivative appearing
  • arbitrary constantsindependent free parameters in the solution family

Worked example

For y=c1e2x+c2e3xy = c_1 e^{2x} + c_2 e^{-3x}, name the order of the differential equation it solves and the type of solution it is.
  1. Count the independent arbitrary constants: c1c_1 and c2c_2 — two of them.
  2. Order == number of independent arbitrary constants =2= 2.
  3. Because the constants are still free, this is the GENERAL solution of a second-order equation.
Answer:Order 2; it is a general solution.
Practice this conceptself-check · 4 quick reps

Try it yourself

A general solution carries the constants aa and bb as in y=acosx+bsinxy = a\cos x + b\sin x. What is the order of its differential equation?

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    A general solution has 4 arbitrary constants. Order of the ODE?
  2. 2.
    Is y=3e2xy = 3e^{2x} (no free constant) a general or particular solution?
  3. 3.
    Order of the ODE whose solution is y=c1+c2xy = c_1 + c_2 x?
  4. 4.
    How many arbitrary constants in the general solution of a 3rd-order ODE?

Order and degree are separate labels

Order is about WHICH derivative is highest; degree is about the POWER on it. (d2ydx2)3=x\big(\tfrac{d^2y}{dx^2}\big)^3 = x is order 2 but degree 3. Don't conflate the two.

"Number of constants" means INDEPENDENT constants

Two constants that always merge into one (like c1+c3c_1 + c_3) count as a single arbitrary constant. Collapse the family first, then count — the order equals the number of constants that survive.

Concept 2 of 9

Order = Order of the Highest Derivative Present

Intuition

Order is the easiest classifier to read: scan the equation for derivatives and pick the one differentiated the most times. A cubed second derivative is still order 2 — the power never touches the order.

Definition

Order of a differential equation == the order of the highest-order derivative that appears in it.

  • d2ydx2\dfrac{d^2y}{dx^2} present but no higher derivative \Rightarrow order 2, regardless of any power on it.
  • A high power on a LOW derivative does not raise the order: (dydx)5+d3ydx3=0\big(\tfrac{dy}{dx}\big)^{5} + \tfrac{d^3y}{dx^3} = 0 is order 3 (because d3ydx3\tfrac{d^3y}{dx^3} is present), not order 5.
  • Mixed powers of the same top derivative also leave the order alone.

Order

order=the order of the highest derivative appearing in the equation\text{order} = \text{the order of the highest derivative appearing in the equation}

Worked example

Find the order of x2d3ydx3+(dydx)4y=0x^2\dfrac{d^3y}{dx^3} + \big(\dfrac{dy}{dx}\big)^{4} - y = 0.
  1. List the derivatives present: d3ydx3\dfrac{d^3y}{dx^3} and dydx\dfrac{dy}{dx}.
  2. The highest-order one is d3ydx3\dfrac{d^3y}{dx^3} — a third derivative.
  3. The power 44 sits on the FIRST derivative, so it is irrelevant to the order.
Answer:Order 3.
Practice this conceptself-check · 4 quick reps

Try it yourself

For the equation (d2ydx2)3+5(dydx)7=d4ydx4+cosx\big(\tfrac{d^2y}{dx^2}\big)^{3} + 5\big(\tfrac{dy}{dx}\big)^{7} = \tfrac{d^4y}{dx^4} + \cos x, give the order mm and hence m2m^2.

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    Order of (d2ydx2)7+y=0\big(\frac{d^2y}{dx^2}\big)^7 + y = 0?
  2. 2.
    Order of d4ydx4(dydx)10=x\frac{d^4y}{dx^4} - \big(\frac{dy}{dx}\big)^{10} = x?
  3. 3.
    Order of xd3ydx3dydx=0x\frac{d^3y}{dx^3} - \frac{dy}{dx} = 0?
  4. 4.
    If order m=3m=3 and degree n=1n=1, find m2+n2m^2 + n^2.

From the bank · past-year question

Example 2Differential EquationsMODERATE
If order and degree of the differential equation (d2ydx2)5+4(d2ydx2)5d3ydx3+d3ydx3=sinx\left(\frac{d^{2}y}{dx^{2}}\right)^{5}+4\left(\frac{d^{2}y}{dx^{2}}\right)^{5}\cdot\frac{d^{3}y}{dx^{3}}+\frac{d^{3}y}{dx^{3}}=\sin x, are mm and nn respectively, then the value of m2+n2m^{2}+n^{2} is equal to

[Q139 · 3rd May Shift 2 · 2023]

A power on the top derivative is DEGREE, never order

(d2ydx2)5\big(\tfrac{d^2y}{dx^2}\big)^{5} reads as "order 2, degree 5", not "order 5". The exponent belongs to degree; the order only counts how many times you differentiated.

Concept 3 of 9

Degree = Power of the Highest Derivative After Clearing Radicals

Intuition

Degree is only meaningful once the equation is polynomial in its derivatives. So the first move is always to rationalize: raise both sides to a power that clears every root and fractional exponent. Read the degree only from the CLEAN equation, never the raw one.

Definition

To find the degree: 1. Clear all radicals and fractional powers on the derivatives (raise to a suitable power). 2. Once the equation is polynomial in the derivatives, the degree is the power on the highest-order derivative.

  • Example shape: y=y55\sqrt{y''} = \sqrt[5]{y' - 5} becomes (y)5=(y5)2(y'')^5 = (y'-5)^2 after raising to the 10th power \Rightarrow degree 5.
  • The LCM of the fractional exponents tells you the power to raise both sides to.

Degree

degree=power of the highest-order derivative, once the equation is polynomial in its derivatives\text{degree} = \text{power of the highest-order derivative, once the equation is polynomial in its derivatives}

Worked example

Find the order and degree of (d2ydx2)2/3=(1+dydx)1/2\big(\dfrac{d^2y}{dx^2}\big)^{2/3} = \big(1 + \dfrac{dy}{dx}\big)^{1/2}, and their sum.
  1. Highest derivative is d2ydx2\dfrac{d^2y}{dx^2} \Rightarrow order =2= 2.
  2. Clear the fractional powers: raise both sides to the 6th power (LCM of 3 and 2): (d2ydx2)4=(1+dydx)3\big(\tfrac{d^2y}{dx^2}\big)^{4} = \big(1 + \tfrac{dy}{dx}\big)^{3}.
  3. Now the power on d2ydx2\dfrac{d^2y}{dx^2} is 44 \Rightarrow degree =4= 4.
  4. Sum =2+4=6= 2 + 4 = 6.
Answer:Order 2, degree 4; sum =6= 6.
Practice this conceptself-check · 4 quick reps

Try it yourself

Find the order and degree of kd2ydx2=[1+(dydx)2]3/2k\,\dfrac{d^2y}{dx^2} = \Big[1 + \big(\dfrac{dy}{dx}\big)^2\Big]^{3/2}.

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    Degree of (d2ydx2)3/2=(dydx)5/2\big(\frac{d^2y}{dx^2}\big)^{3/2} = \big(\frac{dy}{dx}\big)^{5/2} after clearing?
  2. 2.
    Order and degree of dydx4dydx7x=0\sqrt{\frac{dy}{dx}} - 4\frac{dy}{dx} - 7x = 0?
  3. 3.
    Sum of order and degree of (d3ydx3)2=1+dydx\big(\frac{d^3y}{dx^3}\big)^2 = 1 + \frac{dy}{dx}?
  4. 4.
    Degree of (1+(y)2)1/2=y\big(1+(y')^2\big)^{1/2} = y''?

From the bank · past-year question

Example 3Differential EquationsMODERATE
The sum of the degree and order of the differential equation d2y dx2=dy dx55\sqrt{\frac{d^{2}y}{\text{ }dx^{2}}}=\sqrt[5]{\frac{dy}{\text{ }dx}- 5} is

[Q149 · 20 April Shift I · 2025]

Clear radicals BEFORE you read the degree

The degree is NOT the fractional exponent you first see. For (d2ydx2)0.6=y\big(\tfrac{d^2y}{dx^2}\big)^{0.6} = y', raise to the 5th power to get (d2ydx2)3=(y)5\big(\tfrac{d^2y}{dx^2}\big)^{3} = (y')^5: degree =3= 3, not 0.60.6. Make it polynomial first.

Raise to the LCM of the fractional exponents

With a   \sqrt{\;} (power 12\tfrac12) and a   5\sqrt[5]{\;} (power 15\tfrac15), raise both sides to the 10th power in one shot — squaring alone leaves the 5th root, and 5th-powering alone leaves the square root.

Concept 4 of 9

When Degree Is Undefined (Derivative Inside a Transcendental)

Intuition

You can only clear radicals and fractional powers by algebra. If a derivative is trapped inside a log, a trig, or an exponential, no amount of raising to powers makes the equation polynomial in its derivatives — so the degree simply does not exist. The order still does.

Definition

Degree is undefined when the equation cannot be made polynomial in its derivatives:

  • A derivative appears inside a transcendental function: log ⁣(d2ydx2)\log\!\big(\tfrac{d^2y}{dx^2}\big), sin ⁣(dydx)\sin\!\big(\tfrac{dy}{dx}\big), eye^{\,y''}, etc.
  • Order is still well-defined in these cases — read it as usual (the highest derivative present).
  • Only radicals/fractional powers can be cleared; a derivative inside log\log/sin\sin/cos\cos/e()e^{(\cdot)} is permanent.

Degree-undefined criterion

degree undefined    a derivative sits inside a transcendental (log, sin, cos, e())\text{degree undefined} \iff \text{a derivative sits inside a transcendental (}\log,\ \sin,\ \cos,\ e^{(\cdot)}\text{)}

Worked example

State the order and degree of d2ydx2=edy/dx+x\dfrac{d^2y}{dx^2} = e^{\,dy/dx} + x.
  1. Highest derivative is d2ydx2\dfrac{d^2y}{dx^2} \Rightarrow order =2= 2.
  2. The term edy/dxe^{\,dy/dx} contains a derivative inside an exponential.
  3. No algebra can make this polynomial in the derivatives, so the degree does not exist.
Answer:Order 2; degree not defined.
Practice this conceptself-check · 4 quick reps

Try it yourself

Find the order and degree of dydx+sin ⁣(dydx)=0\dfrac{dy}{dx} + \sin\!\Big(\dfrac{dy}{dx}\Big) = 0.

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    Degree of d2ydx2=cos ⁣(dydx)\frac{d^2y}{dx^2} = \cos\!\big(\frac{dy}{dx}\big)?
  2. 2.
    Order of d2ydx2=x2log ⁣(d2ydx2)\frac{d^2y}{dx^2} = x^2\log\!\big(\frac{d^2y}{dx^2}\big)?
  3. 3.
    Degree of edy/dx=xe^{\,dy/dx} = x?
  4. 4.
    Degree of y+tan(y)=0y'' + \tan(y') = 0?

From the bank · past-year question

Example 4Differential EquationsEASY
The degree of the differential equation d2y dx2+3( dy dx)2=x2log( d2y dx2)\frac{d^{2}y}{\text{ }dx^{2}}+ 3\left( \frac{\text{ }dy}{\text{ }dx} \right)^{2}=x^{2}\log\left( \frac{{\text{ }d}^{2}y}{\text{ }dx^{2}} \right) is

[Q114 · 22 April Shift I · 2025]

Seeing a first power does NOT mean degree 1

For d2ydx2+sin ⁣(dydx)=0\tfrac{d^2y}{dx^2} + \sin\!\big(\tfrac{dy}{dx}\big) = 0, writing "degree 1" because d2ydx2\tfrac{d^2y}{dx^2} appears once is the trap. A derivative inside sin\sin, cos\cos, log\log, or e()e^{(\cdot)} makes the degree UNDEFINED regardless of the visible power.

Order survives; only degree dies

"Degree undefined" never means "order undefined". Always still report the order — it is just the highest derivative present.

Concept 5 of 9

Collapse Redundant Arbitrary Constants Before Counting Order

Intuition

The order of a family equals its number of INDEPENDENT arbitrary constants — but families are often written with fake extra constants that secretly merge. Simplify first: combine sums, absorb exponentials, and see how many truly-free constants remain. That count is the order.

Definition

Constants merge in predictable ways — spot and collapse them:

  • Sums merge: C1+C2AC_1 + C_2 \to A (one constant), and C1+C3AC_1 + C_3 \to A.
  • Exponential shifts absorb: C3ex+C4=(C3eC4)ex=BexC_3 e^{x + C_4} = (C_3 e^{C_4})e^x = B e^x — the C4C_4 vanishes into a single BB.
  • Same-form terms merge: (C1+C2)ex=Aex(C_1 + C_2)e^x = A e^x; two constants become one.
  • After collapsing, order = number of surviving independent constants.

Constant-absorption identity

C3ex+C4=(C3eC4)ex=BexC_3\,e^{\,x + C_4} = \big(C_3 e^{C_4}\big)e^{x} = B\,e^{x}
  • Bthe single surviving constant after absorbing C3,C4C_3, C_4

Worked example

Find the order of the ODE whose general solution is y=C1+C2ex+C3ex+C4y = C_1 + C_2 e^x + C_3 e^{x + C_4}.
  1. Absorb the exponential shift: C3ex+C4=(C3eC4)ex=BexC_3 e^{x + C_4} = (C_3 e^{C_4})e^x = B e^x.
  2. Now y=C1+C2ex+Bex=C1+(C2+B)ex=A+Dexy = C_1 + C_2 e^x + B e^x = C_1 + (C_2 + B)e^x = A + D e^x.
  3. Only two independent constants survive: AA and DD.
Answer:Order 2.
Practice this conceptself-check · 4 quick reps

Try it yourself

Find the order of the ODE whose general solution is y=(C1+C2)sin(x+C3)C4ex+C5y = (C_1 + C_2)\sin(x + C_3) - C_4 e^{x + C_5}.

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    Independent constants in y=C1+C2cosx+C3C4ex+C5y = C_1 + C_2\cos x + C_3 - C_4 e^{x+C_5}?
  2. 2.
    Order for y=Aex+By = A e^{x+B}?
  3. 3.
    Order for y=(a+b)x+cy = (a+b)x + c?
  4. 4.
    Independent constants in y=c1e2x+c2y = c_1 e^{2x+c_2}?

From the bank · past-year question

Example 5Differential EquationsHARD
The order of the differential equation, whose solution is y=C1+C2ex+C3ex+C4y = C_1 + C_2 e^x + C_3 e^{x+C_4}, is

[Q110 · 15th May Shift 2 · 2023]

ex+Ce^{x + C} hides a constant, it does not add one

C3ex+C4C_3 e^{x + C_4} LOOKS like two constants but is just BexB e^x — one constant. Counting C4C_4 separately over-states the order. Absorb every exponential shift before you count.

Only INDEPENDENT constants count

A sum like C1+C2C_1 + C_2 is a single free parameter. Two constants that can only ever appear as their sum contribute one to the order, not two.

Concept 6 of 9

Formation: n Independent Constants ⇒ Order-n Differential Equation

Intuition

To build the differential equation of a family, you must get rid of every arbitrary constant. Each differentiation gives you one more equation to eliminate one constant — so a family with n independent constants needs n differentiations, producing an order-n equation. Count the constants first; that fixes the order before you compute anything.

Definition

The formation recipe:

  • Count the independent arbitrary constants nn in the family (collapse redundant ones first).
  • **Differentiate the family nn times, then eliminate** all nn constants using the original equation plus the derived equations.
  • The result is a differential equation of **order nn**, free of arbitrary constants.
  • The degree of that equation is read afterwards (clear radicals first).

Formation order

n independent arbitrary constants    differential equation of order nn \text{ independent arbitrary constants} \;\Longrightarrow\; \text{differential equation of order } n

Worked example

What order and degree of differential equation represents the family of tangent lines to x2=4yx^2 = 4y?
  1. A tangent to x2=4yx^2 = 4y (here a=1a = 1) in slope form is x=my+1mx = m y + \dfrac{1}{m}, i.e. mx=m2y+1m x = m^2 y + 1 — ONE arbitrary constant mm.
  2. One constant \Rightarrow order 1: replace m=dydxm = \dfrac{dy}{dx}: xdydx=(dydx)2y+1x\dfrac{dy}{dx} = \big(\dfrac{dy}{dx}\big)^2 y + 1.
  3. The highest derivative dydx\dfrac{dy}{dx} appears to the second power \Rightarrow degree 2.
Answer:Order 1, degree 2.
Practice this conceptself-check · 4 quick reps

Try it yourself

The family of curves y2=2c(x+c)y^2 = 2c(x + \sqrt{c}) with positive parameter cc. What are the order and degree of its differential equation?

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    Family y=c1ec2xy = c_1 e^{c_2 x} has how many constants, so what order?
  2. 2.
    Order of the ODE of all parabolas with axis parallel to the Y-axis, (xh)2=4a(yk)(x-h)^2 = 4a(y-k)?
  3. 3.
    Order of the ODE of all straight lines y=mx+cy = mx + c?
  4. 4.
    Order of the ODE of all lines through a FIXED point (1,1)(1,-1)?

From the bank · past-year question

Example 6Differential EquationsMODERATE
The order and degree of differential equation of all tangent lines to the parabola x2=4yx^{2}= 4y is respectively.

[Q114 · 19 April Shift I · 2025]

Collapse constants BEFORE fixing the order

For all parabolas with axis parallel to Y, (xh)2=4a(yk)(x-h)^2 = 4a(y-k) has THREE independent constants h,a,kh, a, k — so its ODE is order 3 (d3ydx3=0\tfrac{d^3y}{dx^3} = 0). Miscounting the constants sets the wrong order from the start.

A fixed point removes a constant

All lines through a fixed point have only the slope free (order 1), while all lines in the plane have slope AND intercept free (order 2). Read what is fixed before counting.

Concept 7 of 9

Forming the Differential Equation of a Curve Family

Intuition

Once you know the order equals the number of constants, the mechanics are pure elimination: differentiate the family, solve for a constant, and substitute back. Known functions like e^x stay in the equation — only the ARBITRARY constants must go. The visual: one equation with a free constant is a whole family of curves; the differential equation is the single rule they all obey.

Definition

For a family with constants, differentiate as many times as there are constants, then eliminate:

  • One constant: differentiate once, solve for the constant, substitute back.
  • Two constants (e.g. Ax2+By2=1Ax^2 + By^2 = 1): differentiate twice and eliminate A,BA, B, giving a second-order equation.
  • Keep known functions: in x2y=4ex+cx^2 y = 4e^x + c, the exe^x is a known function, NOT the arbitrary constant — only cc is eliminated, so exe^x survives in the answer.
  • For y=ex(a+bx+x2)y = e^x(a + bx + x^2): use y=exuy = e^x u, differentiate, and eliminate a,ba, b.

Elimination recipe

differentiate n times    solve for the constants    substitute back to eliminate them\text{differentiate } n \text{ times} \;\to\; \text{solve for the constants} \;\to\; \text{substitute back to eliminate them}
y = c·x²(one curve per c)eliminate c → x·y′ = 2y

Worked example

Form the differential equation of the family x2y=4ex+cx^2 y = 4e^x + c, where cc is arbitrary.
  1. One arbitrary constant cc \Rightarrow differentiate once.
  2. ddx(x2y)=ddx(4ex+c)\dfrac{d}{dx}(x^2 y) = \dfrac{d}{dx}(4e^x + c): 2xy+x2dydx=4ex2xy + x^2\dfrac{dy}{dx} = 4e^x.
  3. The constant cc has already dropped out; the known function 4ex4e^x stays.
  4. Rearrange: x2dydx+2xy4ex=0x^2\dfrac{dy}{dx} + 2xy - 4e^x = 0.
Answer:x2dydx+2xy4ex=0x^2\dfrac{dy}{dx} + 2xy - 4e^x = 0.
Practice this conceptself-check · 4 quick reps

Try it yourself

Form the differential equation of the family y=ex(a+bx+x2)y = e^x(a + bx + x^2).

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    Form the ODE of y=c1ec2xy = c_1 e^{c_2 x}.
  2. 2.
    Form the ODE of y=ex(acosx+bsinx)y = e^x(a\cos x + b\sin x).
  3. 3.
    Form the ODE of all lines through (1,1)(1,-1).
  4. 4.
    Form the ODE of y=Xsin(6t+5)+Ycos(6t+5)y = X\sin(6t+5) + Y\cos(6t+5).

From the bank · past-year question

Example 7Differential EquationsMODERATE
The differential equation whose solution represents the family x2y=4ex+cx^{2}y= 4e^{x}+ c, where c is an arbitrary constant, is

[Q150 · 20 April Shift I · 2025]

Eliminate the CONSTANT, not the known function

In x2y=4ex+cx^2 y = 4e^x + c only cc is arbitrary — the exe^x is a fixed function that survives differentiation. Dropping exe^x as if it were the constant gives the wrong equation. The correct ODE keeps the 4ex4e^x term.

Differentiate ONCE per constant — no more, no less

Ax2+By2=1Ax^2 + By^2 = 1 has two constants, so it needs TWO differentiations to eliminate both (giving xyy+x(y)2yy=0xy y'' + x(y')^2 - yy' = 0). Stopping after one differentiation leaves a constant behind.

Concept 8 of 9

Forming the Differential Equation of Circles and Parabolas

Intuition

Geometric families are just curve families with a geometric constraint that fixes some constants and frees others. The whole skill is translating the words ("centre on the X-axis", "touching the Y-axis", "vertex at origin, axis along +Y") into an equation with the RIGHT number of free constants, then eliminating them exactly as before.

Definition

Set up the standard form from the geometric description, then eliminate:

  • Circles, centre on X-axis, through origin: (xa)2+y2=a2x2+y2=2ax(x-a)^2 + y^2 = a^2 \Rightarrow x^2 + y^2 = 2ax; eliminate aa \to y2=x2+2xyyy^2 = x^2 + 2xy\,y' (order 1, one constant).
  • Circles through origin, centre on Y-axis: x2+y2=2ky(x2y2)y2xy=0x^2 + y^2 = 2ky \Rightarrow (x^2 - y^2)y' - 2xy = 0.
  • Circles touching Y-axis at origin, centre on X-axis: x2+y2=2hxx2y2+2xyy=0x^2 + y^2 = 2hx \Rightarrow x^2 - y^2 + 2xy\,y' = 0.
  • Parabolas, vertex origin, axis along +Y: x2=4ayxdydx=2yx^2 = 4ay \Rightarrow x\dfrac{dy}{dx} = 2y (one constant aa, order 1).
  • All parabolas, axis parallel to Y: three constants \Rightarrow order 3, d3ydx3=0\dfrac{d^3y}{dx^3} = 0.

Two workhorses

x2+y2=2ax  (circle)x2=4ay  (parabola, axis +Y)x^2 + y^2 = 2ax \;(\text{circle}) \qquad x^2 = 4ay \;(\text{parabola, axis } +Y)
  • athe single geometric parameter to eliminate by one differentiation

Worked example

Form the differential equation of all circles passing through the origin with centres on the X-axis.
  1. Circle through origin, centre (a,0)(a, 0): (xa)2+y2=a2(x - a)^2 + y^2 = a^2, i.e. x22ax+y2=0x^2 - 2ax + y^2 = 0.
  2. Differentiate: 2x2a+2ydydx=0a=x+ydydx2x - 2a + 2y\dfrac{dy}{dx} = 0 \Rightarrow a = x + y\dfrac{dy}{dx}.
  3. Substitute aa back into x22ax+y2=0x^2 - 2ax + y^2 = 0: x22x(x+yy)+y2=0x^2 - 2x\big(x + y\,y'\big) + y^2 = 0.
  4. Simplify: y2=x2+2xydydxy^2 = x^2 + 2xy\dfrac{dy}{dx}.
Answer:y2=x2+2xydydxy^2 = x^2 + 2xy\dfrac{dy}{dx}.
Practice this conceptself-check · 4 quick reps

Try it yourself

Form the differential equation of all circles touching the Y-axis at the origin with centre on the X-axis.

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    ODE of parabolas, vertex origin, axis along +Y (x2=4ay)(x^2 = 4ay)?
  2. 2.
    ODE of circles through origin, centre on Y-axis?
  3. 3.
    ODE of all parabolas with axis parallel to Y-axis?
  4. 4.
    ODE of circles centre on y=5y = 5, touching X-axis?

From the bank · past-year question

Example 8Differential EquationsMODERATE
The differential equation of all circles, passing through the origin and having their centres on the X-axis, is

[Q142 · 10th May Shift 2 · 2024]

Translate the geometry into the RIGHT free constants

"Centre on the X-axis and touching the Y-axis" fixes the centre as (a,0)(a,0) with radius a|a| — ONE free constant, giving an order-1 equation. Treating it as a general circle (two/three constants) inflates the order and the answer.

Mind the sign when substituting the eliminated constant

For circles through the origin centred on the X-axis, substituting a=x+yya = x + yy' yields y2=x2+2xyyy^2 = x^2 + 2xy\,y' — a plus sign. Careless algebra flips it to y2=x22xyyy^2 = x^2 - 2xy\,y', which is a different (wrong) option.

Concept 9 of 9

Verifying a Solution and Identifying Its Family

Intuition

Sometimes you are handed a candidate solution and asked to check it, find a constant that makes it fit, or say what curve it represents. The move is the reverse of formation: substitute the function (and its derivatives) into the differential equation and simplify — matching both sides confirms it, or reveals the unknown constant.

Definition

Three verification tasks, all by substitution:

  • Confirm a solution: compute y,yy', y'' from the given yy, plug into the ODE, and check the equation holds identically.
  • **Find a constant kk:** for a PARAMETRIC solution x=x(t), y=y(t)x = x(t),\ y = y(t), use dydx=dy/dtdx/dt\dfrac{dy}{dx} = \dfrac{dy/dt}{dx/dt} and d2ydx2=ddx ⁣(dydx)\dfrac{d^2y}{dx^2} = \dfrac{d}{dx}\!\big(\tfrac{dy}{dx}\big) to substitute, then solve for kk.
  • Identify the family: solve/simplify the given ODE to its solution curve and name it (circle, hyperbola, ellipse, pair of lines).

Parametric derivative

dydx=dy/dtdx/dtd2ydx2=1dx/dtddt ⁣(dydx)\dfrac{dy}{dx} = \dfrac{dy/dt}{dx/dt} \qquad \dfrac{d^2y}{dx^2} = \dfrac{1}{dx/dt}\dfrac{d}{dt}\!\left(\dfrac{dy}{dx}\right)
  • tthe parameter — differentiate x and y with respect to it, then divide

Worked example

For x=sintx = \sin t, y=aet2+bet2y = a e^{t\sqrt{2}} + b e^{-t\sqrt{2}}, find kk so that (1x2)yxy=ky(1 - x^2)y'' - x y' = k y.
  1. Note yy satisfies d2ydt2=2y\dfrac{d^2y}{dt^2} = 2y (each exponential contributes a factor (±2)2=2(\pm\sqrt2)^2 = 2).
  2. With x=sintx = \sin t: dxdt=cost\dfrac{dx}{dt} = \cos t, and 1x2=cos2t1 - x^2 = \cos^2 t.
  3. Converting the parametric derivatives, (1x2)yxy(1 - x^2)y'' - x y' reduces to d2ydt2=2y\dfrac{d^2y}{dt^2} = 2y.
  4. So (1x2)yxy=2y(1 - x^2)y'' - x y' = 2y, giving k=2k = 2.
Answer:k=2k = 2.
Practice this conceptself-check · 4 quick reps

Try it yourself

The particular solution of (1+y2)dxxydy=0(1 + y^2)\,dx - xy\,dy = 0 through (1,0)(1, 0) represents which conic?

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    Which ODE does y=ex(Acosx+Bsinx)y = e^x(A\cos x + B\sin x) satisfy?
  2. 2.
    Does y=c1ec2xy = c_1 e^{c_2 x} satisfy yy=(y)2yy'' = (y')^2?
  3. 3.
    dydx=1y2y\frac{dy}{dx} = \frac{1 - y^2}{y} gives which family?
  4. 4.
    Family represented by x2=c(1+y2)x^2 = c(1 + y^2) with c>0c > 0?

From the bank · past-year question

Example 9Differential EquationsHARD
The function y(x)y(x) represented by x=sintx = \sin t, y=aet2+bet2y = ae^{t\sqrt{2}} + be^{-t\sqrt{2}}, t(π2,π2)t \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right) satisfies the equation (1x2)yxy=ky(1-x^2)y'' - xy' = ky, then the value of kk is

[Q124 · Shift 1 · 2023]

Convert parametric derivatives correctly

dydxdydt\dfrac{dy}{dx} \ne \dfrac{dy}{dt} — you must divide by dxdt\dfrac{dx}{dt}. For x=sintx = \sin t, dxdt=cost\dfrac{dx}{dt} = \cos t; skipping this factor is the most common error in find-kk questions and gives the wrong constant.

Identify the conic from the SIMPLIFIED solution

x2=c(1+y2)x^2 = c(1 + y^2) only becomes x2y2=1x^2 - y^2 = 1 (a hyperbola) AFTER applying the given point to fix cc. Reading the conic type off the un-simplified, constant-carrying form is unreliable.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (9)

  • Differential Equation Terminology

    The master link

    order of the ODE  =  number of independent arbitrary constants in its general solution\text{order of the ODE} \;=\; \text{number of independent arbitrary constants in its general solution}
  • Order = Order of the Highest Derivative Present

    Order

    order=the order of the highest derivative appearing in the equation\text{order} = \text{the order of the highest derivative appearing in the equation}
  • Degree = Power of the Highest Derivative After Clearing Radicals

    Degree

    degree=power of the highest-order derivative, once the equation is polynomial in its derivatives\text{degree} = \text{power of the highest-order derivative, once the equation is polynomial in its derivatives}
  • When Degree Is Undefined (Derivative Inside a Transcendental)

    Degree-undefined criterion

    degree undefined    a derivative sits inside a transcendental (log, sin, cos, e())\text{degree undefined} \iff \text{a derivative sits inside a transcendental (}\log,\ \sin,\ \cos,\ e^{(\cdot)}\text{)}
  • Collapse Redundant Arbitrary Constants Before Counting Order

    Constant-absorption identity

    C3ex+C4=(C3eC4)ex=BexC_3\,e^{\,x + C_4} = \big(C_3 e^{C_4}\big)e^{x} = B\,e^{x}
  • Formation: n Independent Constants ⇒ Order-n Differential Equation

    Formation order

    n independent arbitrary constants    differential equation of order nn \text{ independent arbitrary constants} \;\Longrightarrow\; \text{differential equation of order } n
  • Forming the Differential Equation of a Curve Family

    Elimination recipe

    differentiate n times    solve for the constants    substitute back to eliminate them\text{differentiate } n \text{ times} \;\to\; \text{solve for the constants} \;\to\; \text{substitute back to eliminate them}
  • Forming the Differential Equation of Circles and Parabolas

    Two workhorses

    x2+y2=2ax  (circle)x2=4ay  (parabola, axis +Y)x^2 + y^2 = 2ax \;(\text{circle}) \qquad x^2 = 4ay \;(\text{parabola, axis } +Y)
  • Verifying a Solution and Identifying Its Family

    Parametric derivative

    dydx=dy/dtdx/dtd2ydx2=1dx/dtddt ⁣(dydx)\dfrac{dy}{dx} = \dfrac{dy/dt}{dx/dt} \qquad \dfrac{d^2y}{dx^2} = \dfrac{1}{dx/dt}\dfrac{d}{dt}\!\left(\dfrac{dy}{dx}\right)

Watch out for (17)

Mastery check — 5 interleaved questions

Try each one before clicking. Questions are interleaved across the concepts above, not grouped — interleaving sharpens transfer.

Example 1Differential EquationsMODERATE
The differential equation of all parabolas, whose axes are parallel to Y-axis, is

[Q143 · 9th May Shift 1 · 2024]

Example 2Differential EquationsMODERATE
The order and degree of the differential equation dydx4dydx7x=0\sqrt{\frac{dy}{dx}} - 4\frac{dy}{dx} - 7x = 0 are

[Q121 · May Shift 1 · 2021]

Example 3Differential EquationsMODERATE
The order of the differential equation, whose general solution is given by y=c1+c2cosx+c3c4ex+c5y = c_1 + c_2\cos x + c_3 - c_4 e^{x+c_5} where c1,c2,c3,c4c_1, c_2, c_3, c_4 and c5c_5 are arbitrary constants, is

[Q149 · 10th May Shift 2 · 2023]

Example 4Differential EquationsHARD
The differential equation of y=ex(a+bx+x2)y=e^{x}(a+bx+x^{2}) is

[Q148 · 15th May Shift 1 · 2023]

Example 5Differential EquationsMODERATE
The differential equation of all circles having their centres on the line y=5y= 5 and touching ( X -axis) is ____\_\_\_\_

[Q129 · 21 April Shift II · 2025]

Drill every past-year question on this subtopic

33 questions from the bank — paginated, with cart and Word-export support.