NDA Chemistry · Atomic Structure and Periodic Classification
Electron Configuration and Valence Shells
Electrons fill shells from the inside out, each shell holding up to 2n² electrons; the outermost (valence) shell decides how the atom bonds.
Why this matters
4 PYQs built on one rule — the maximum electrons a shell can hold is 2n². From that rule the bank asks the cap of a named shell (K, L, M, N), or works out the valence-shell count of an element from its atomic number. Learn 2n² and you cover the whole subtopic.
Concept 1 of 2
Maximum electrons in a shell (the 2n² rule)
Intuition
Definition
The shell-capacity rule and the resulting caps:
- The maximum number of electrons a shell can hold is 2n², where n is the shell number.
- K shell (n = 1) → 2(1)² = 2 electrons.
- L shell (n = 2) → 2(2)² = 8 electrons.
- M shell (n = 3) → 2(3)² = 18 electrons.
- N shell (n = 4) → 2(4)² = 32 electrons.
Maximum electrons per shell
- nshell number (K=1, L=2, M=3, N=4)
Worked example
- The N shell is the fourth shell, so n = 4.
- Apply the rule: maximum = 2n² = 2 × 4² = 2 × 16.
- = 32 electrons.
Practice this conceptself-check · 4 quick reps
Try it yourself
Practice — Level 1 (4 reps)
Quick reps to lock in the method. Try each, then check.
- 1.Maximum electrons in the first (K) shell?
- 2.Maximum electrons in the N shell?
- 3.Maximum electrons in the L shell?
- 4.Maximum electrons in the M shell?
From the bank · past-year question
[Q72 · Apr · 2020]
2n² is a CAP, not the actual filling
Concept 2 of 2
Valence-shell electrons and bonding from the configuration
Intuition
Definition
How to read bonding from the configuration:
- Fill shells in order 2, 8, 8, 18 (using the Bohr filling scheme); the outermost shell's electrons are the valence electrons.
- Bromine (Z = 35): config 2, 8, 18, 7 → valence shell has 7 electrons.
- An atom with 6 valence electrons (Z = 8, oxygen: 2, 6) needs to gain 2 to complete its octet — so it gains 2 electrons (e.g. when bonding with sodium to form Na₂O).
- Valency = electrons gained, lost or shared to reach 8 in the outer shell.
Electrons gained/lost to reach an octet
Worked example
- Fill shells from the inside: 2 (K) + 8 (L) + 18 (M) = 28 electrons used.
- Remaining electrons: 35 − 28 = 7, which go into the N shell.
- So the configuration is 2, 8, 18, 7 — the valence shell holds 7 electrons.
Practice this conceptself-check · 3 quick reps
Try it yourself
Practice — Level 1 (3 reps)
Quick reps to lock in the method. Try each, then check.
- 1.How many valence electrons does an atom with atomic number 35 have?
- 2.An atom with configuration 2, 6 gains how many electrons to complete its octet?
- 3.How many valence electrons does an atom with atomic number 11 (sodium) have?
From the bank · past-year question
[Q84 · Apr · 2022]
Valence electrons live in the OUTERMOST shell only
Summary — formulas & gotchas at a glance
A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.
Formulas (2)
- Maximum electrons in a shell (the 2n² rule)
Maximum electrons per shell
- Valence-shell electrons and bonding from the configuration
Electrons gained/lost to reach an octet
Watch out for (2)
- 2n² is a CAP, not the actual filling→ Maximum electrons in a shell (the 2n² rule)
- Valence electrons live in the OUTERMOST shell only→ Valence-shell electrons and bonding from the configuration
Mastery check — 2 interleaved questions
Try each one before clicking. Questions are interleaved across the concepts above, not grouped — interleaving sharpens transfer.
[Q113 · Sep · 2024]
[Q62 · Sep · 2018]
Drill every past-year question on this subtopic
4 questions from the bank — paginated, with cart and Word-export support.