NDA Maths · Application of Derivatives

Monotonicity, Maxima & Minima

The sign of f′ says where a function rises or falls; the zeros of f′ are the candidates for peaks and valleys, sorted by the first- or second-derivative test, with endpoints checked for the absolute extremum.

Why this matters

This is the densest subtopic in the chapter. Almost every question is one of four moves: read intervals from the sign of f′, classify a critical point, find the greatest/least value on an interval, or impose a condition (no extremum / monotonic) on a parameter.

Concept 1 of 4

Increasing and decreasing intervals

Intuition

Where the tangent slopes up the function rises, where it slopes down it falls. So the sign of f(x)f'(x) on an interval decides monotonicity — find where f=0f'=0 or is undefined, then test the sign of ff' in each resulting interval.

Definition

On an interval: f(x)>0ff'(x)>0\Rightarrow f increasing; f(x)<0ff'(x)<0\Rightarrow f decreasing. Method: solve f(x)=0f'(x)=0 for the critical xx, split the line at those points, and test the sign of ff' in each piece (a product like (xa)(xb)(xc)(x-a)(x-b)(x-c) flips sign at each root). 'Monotonic on an interval' or 'no turning' imposes a one-sided sign condition that may fix a parameter.

f′ > 0 ↑f′ < 0 ↓f′ > 0 ↑f′=0

Worked example

On which intervals is f(x)=x33xf(x)=x^3-3x increasing?
Practice this conceptself-check · 4 quick reps

From the bank · past-year question

Example 1Application of DerivativesMODERATE
If f(x)=x335x22+6x+7f(x) = \dfrac{x^{3}}{3} - \dfrac{5x^{2}}{2} + 6x + 7 increases in the interval TT and decreases in the interval SS, then which one of the following is correct ?

[Q100 · Sep · 2019]

Monotonicity is decided by the sign of ff', not ff

ff increasing     f(x)0\iff f'(x)\ge 0 on the interval (and f(x)0f'(x)\le 0 for decreasing). A large or positive VALUE of ff says nothing — read the sign of the DERIVATIVE. Sign-test ff' on each piece between its zeros.

Concept 2 of 4

Critical points and the derivative tests

Intuition

Local peaks and valleys occur where the tangent is flat (f=0f'=0). To tell which is which, either watch the sign of ff' flip (first-derivative test) or check the bend ff'' (second-derivative test): f>0f''>0 is a valley, f<0f''<0 a peak.

Definition

Critical points: where f(x)=0f'(x)=0 (or undefined). First-derivative test: ff' changes ++\to- ⇒ local max; +-\to+ ⇒ local min. Second-derivative test: at a critical point, f>0f''>0 ⇒ local min, f<0f''<0 ⇒ local max, f=0f''=0 ⇒ inconclusive. A function can attain the same extreme value at two points (e.g. ±3\pm 3).

local max (f″<0)local min (f″>0)tangent flat at both

Worked example

Find and classify the extrema of f(x)=x2+128xf(x)=x^2+\dfrac{128}{x} (x>0x>0).
Practice this conceptself-check · 4 quick reps

From the bank · past-year question

Example 2Application of DerivativesEASY
A differentiable function f(x)f(x) has a local maximum at x=0x=0. Let y=2f(x)+axby=2f(x)+ax-b. Which of the following is/are correct? (A) f(0)=0f'(0)=0 (B) f(0)<0f''(0)<0 Select the correct answer using the code given below:

[Q91 · Apr · 2024]

f>0f''>0 is a MINIMUM, not a maximum

Second-derivative test: at a critical point f>0f''>0 means the curve is concave up ⇒ a local minimum; f<0f''<0 ⇒ a local maximum. The sign is the opposite of what students often guess. (f=0f''=0 is inconclusive — fall back to the first-derivative test.)

f=0f'=0 is NECESSARY, not sufficient, for an extremum

A critical point is only a CANDIDATE. f=0f'=0 can be a point of inflection with no extremum (e.g. f(x)=x3f(x)=x^3 at x=0x=0). You must still confirm a genuine sign change of ff' (or check ff'').

Concept 3 of 4

Greatest and least value on an interval

Intuition

The absolute (global) maximum or minimum on a closed interval is the largest/smallest among the critical-point values and the endpoint values. Forgetting the endpoints is the classic mistake. On an open interval the extreme may not be attained at all.

Definition

On [a,b][a,b]: compute ff at every critical point inside, plus f(a)f(a) and f(b)f(b); the greatest is the absolute max, the least the absolute min. On an open interval the sup/inf may be approached but never reached (so 'attains its maximum' can be false even when bounded).

Worked example

Find the greatest and least value of f(x)=2sinx+1f(x)=2\sin x+1 on [0,π][0,\pi].
Practice this conceptself-check · 4 quick reps

From the bank · past-year question

Example 3Application of DerivativesHARD
Let f(x)=cos2x+xf(x)=\cos 2x+x on [π2,π2]\left[-\dfrac{\pi}{2},\dfrac{\pi}{2}\right].
What is the greatest value of f(x)f(x)?

[Q85 · Sep · 2024]

On a closed interval, ALWAYS test the endpoints

The absolute max/min on [a,b][a,b] is the largest/smallest among the critical-point values AND f(a),f(b)f(a),f(b). The extreme value frequently sits at an endpoint, not at a turning point — comparing only critical points is the classic error.

Concept 4 of 4

Conditions for no extremum / counting extrema

Intuition

To force a polynomial to have no turning points, make its derivative keep one sign — for a cubic, that means the quadratic ff' has no real roots (discriminant < 0). To count extrema, count the sign-changes of ff', i.e. how many times f=0f'=0 with a genuine sign flip.

Definition

  • No extremum (cubic): ff' is a quadratic; require discriminant <0<0 so ff' never changes sign (monotonic).
  • Counting extrema: solve f(x)=0f'(x)=0 on the given domain and count the roots where ff' actually changes sign (e.g. cos4x=12\cos 4x=-\tfrac12 has several solutions in (0,π)(0,\pi)).

Worked example

For what kk does f(x)=x3+x2+kxf(x)=x^3+x^2+kx have no local extremum?
Practice this conceptself-check · 4 quick reps

From the bank · past-year question

Example 4Application of DerivativesMODERATE
What is the condition that f(x)=x3+x2+kxf(x)=x^{3}+x^{2}+kx has no local extremum?

[Q95 · Sep · 2021]

Count genuine SIGN-CHANGES of ff', not just roots of ff'

A root of ff' is an extremum only if ff' actually flips sign there. A repeated root (e.g. f=(x2)2f'=(x-2)^2) touches zero without changing sign — no extremum. For a cubic to have NO extremum, force ff' (a quadratic) to have discriminant <0<0 so it never changes sign.

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