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Complex Numbers — NDA Mathematics

Complex Numbers is around 72 past-year NDA questions built on one idea: i² = −1 turns every quadratic into something solvable and puts numbers on a plane. Work the three notes in order — first the fundamentals, conjugate, modulus and argument (the Argand-plane geometry); then powers of i and De Moivre's theorem for roots; and finally the cube roots of unity, whose identities (ω³ = 1 and 1 + ω + ω² = 0) answer a large, predictable family of questions. The recurring trap is the principal argument's quadrant — always place the number on the plane before reading off its angle.

The handout has every subtopic, worked example, formula and trap with answers shown. The formula sheet is the chapter’s formulas and traps alone, on one page.

Subtopic notes

Formula & revision sheet

8 formulas · 8 gotchas across all subtopics — the exam-eve cheat-sheet

Modulus, Argument & Conjugate

Formulas (5)

  • What a complex number is · Fundamentals of a complex number
    i2=−1a+ib=c+id  ⟺  a=c, b=d(a+ib)(c+id)=(ac−bd)+i(ad+bc)i^2=-1 \qquad a+ib=c+id \iff a=c,\ b=d \qquad (a+ib)(c+id)=(ac-bd)+i(ad+bc)
  • Conjugate; purely real / purely imaginary · Conjugate identities
    a+ib‾=a−ibzzˉ=∣z∣2Re⁡(z)=z+zˉ2Im⁡(z)=z−zˉ2iz1z2‾=zˉ1 zˉ2\overline{a+ib}=a-ib \qquad z\bar z=|z|^2 \qquad \operatorname{Re}(z)=\dfrac{z+\bar z}{2} \qquad \operatorname{Im}(z)=\dfrac{z-\bar z}{2i} \qquad \overline{z_1z_2}=\bar z_1\,\bar z_2
  • Modulus and the triangle inequality · Modulus properties
    ∣z∣=a2+b2∣z1z2∣=∣z1∣ ∣z2∣∣z1z2∣=∣z1∣∣z2∣∣z∣2=zzˉ∣z1+z2∣≤∣z1∣+∣z2∣|z|=\sqrt{a^2+b^2} \qquad |z_1z_2|=|z_1|\,|z_2| \qquad \left|\dfrac{z_1}{z_2}\right|=\dfrac{|z_1|}{|z_2|} \qquad |z|^2=z\bar z \qquad |z_1+z_2|\le|z_1|+|z_2|
  • Argument and polar form · Polar form and argument
    z=r(cos⁡θ+isin⁡θ)=reiθarg⁡(z1z2)=arg⁡z1+arg⁡z2arg⁡ ⁣(z1z2)=arg⁡z1−arg⁡z2z=r(\cos\theta+i\sin\theta)=re^{i\theta} \qquad \arg(z_1z_2)=\arg z_1+\arg z_2 \qquad \arg\!\left(\dfrac{z_1}{z_2}\right)=\arg z_1-\arg z_2
  • Loci in the Argand plane — which curve is it? · Translation dictionary
    zzˉ=x2+y2,z+zˉ=2x,z−zˉ=2iy,∣z−a∣=r (circle),∣z−a∣=∣z−b∣ (perpendicular bisector)z\bar z=x^2+y^2,\quad z+\bar z=2x,\quad z-\bar z=2iy,\quad |z-a|=r\ \text{(circle)},\quad |z-a|=|z-b|\ \text{(perpendicular bisector)}

Watch out for (6)

Powers of i, De Moivre & Roots

Formulas (2)

  • Powers of i (the period-4 cycle) · Powers of i
    i2=−1i3=−ii4=1i4k+r=irik+ik+1+ik+2+ik+3=0i^2=-1 \qquad i^3=-i \qquad i^4=1 \qquad i^{4k+r}=i^r \qquad i^k+i^{k+1}+i^{k+2}+i^{k+3}=0
  • De Moivre's theorem and roots · De Moivre's theorem and nth roots
    (cos⁡θ+isin⁡θ)n=cos⁡nθ+isin⁡nθzn=rneinθz1/n=r1/nei(θ+2kπ)/n, k=0,…,n−1(\cos\theta+i\sin\theta)^n=\cos n\theta+i\sin n\theta \qquad z^n=r^n e^{in\theta} \qquad z^{1/n}=r^{1/n}e^{i(\theta+2k\pi)/n},\ k=0,\ldots,n-1

Watch out for (1)

Cube Roots of Unity

Formulas (1)

Watch out for (1)

PYQ weightage by concept

9 concepts · 76 PYQs — where the marks actually sit, so you know what to drill first

Modulus, Argument & Conjugate46 PYQs · 61%
ConceptPYQsShare
Modulus and the triangle inequality1925%
Conjugate; purely real / purely imaginary1013%
Argument and polar form912%
Loci in the Argand plane — which curve is it?68%
What a complex number is23%
Powers of i, De Moivre & Roots18 PYQs · 24%
ConceptPYQsShare
Powers of i (the period-4 cycle)1317%
De Moivre's theorem and roots57%
Cube Roots of Unity18 PYQs · 24%
ConceptPYQsShare
Applying ω: powers, expressions, related roots1520%
1, ω, ω² and their identities34%

Test yourself on Complex Numbers

20 past NDA questions from this chapter, timed at 25 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.

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