PYQ Vault

NDA Maths · Conics

Conic Sections — Identification & Eccentricity

Every conic is the locus of points whose distance from a fixed focus is a constant multiple — the eccentricity e — of the distance from a fixed directrix. The value of e alone says which conic it is.

Why this matters

This is the chapter's organising idea. One number, e, separates circle (0), ellipse (<1), parabola (=1), and hyperbola (>1). Knowing this — and how to wrestle a messy second-degree equation into a standard form — lets you classify any conic at a glance.

Test yourself — a quick 18-question Conics recall quiz, instant score.

Concept 1 of 3: What a Conic Is — Focus, Directrix, Eccentricity

A conic is born from one rule: stay a fixed ratio away from a point (the focus) compared with a line (the directrix). That ratio is the eccentricity, and as you dial it from 0 upward the same rule traces a circle, then an ellipse, then a parabola, then a hyperbola.

Definition

A conic is the locus of a point PP for which PFPM=e\dfrac{PF}{PM} = e, where FF is the focus, the line is the directrix, PMPM is the perpendicular distance to it, and e≥0e\ge 0 is the eccentricity. The value of ee classifies the curve:

  • e=0e = 0: circle
  • 0<e<10 < e < 1: ellipse
  • e=1e = 1: parabola
  • e>1e > 1: hyperbola

The latus rectum is the focal chord perpendicular to the axis; it recurs in every conic's formulas. Coordinate-geometry tools every conic question borrows (they are not conic facts, but nothing here works without them): the distance formula (x2−x1)2+(y2−y1)2\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} for a chord or focal length; the perpendicularity test — two directions are perpendicular iff their dot product is 0, i.e. slopes multiply to −1-1; the section and midpoint formulas; and solving a quadratic (a parameter like bb in b2+b−2=0b^2+b-2=0 is fixed by factorising, with the negative root rejected when it is a length).

Focus–directrix definition

PFPM=e\dfrac{PF}{PM} = e

Worked example

A conic has eccentricity e=35e = \dfrac{3}{5}. Which conic is it?
Practice this concept3 quick reps

Concept 2 of 3: Eccentricity Values & Comparing Conics

Each conic has its own eccentricity formula in terms of a and b. Reading the standard form gives a, b, and hence e — and questions that compare two conics (or fix a parameter so they share foci) just set their c-values or e-values against each other.

Definition

From the standard forms:

  • Ellipse x2a2+y2b2=1\tfrac{x^2}{a^2}+\tfrac{y^2}{b^2}=1 (a>ba>b): c2=a2−b2c^2 = a^2 - b^2, e=ca<1e = \tfrac{c}{a} < 1.
  • Parabola: e=1e = 1 always.
  • Hyperbola x2a2−y2b2=1\tfrac{x^2}{a^2}-\tfrac{y^2}{b^2}=1: c2=a2+b2c^2 = a^2 + b^2, e=ca>1e = \tfrac{c}{a} > 1.

A minus sign between the squared terms (after normalising to =1=1) signals a hyperbola; a plus sign with unequal denominators signals an ellipse. Shared-foci conditions equate the two cc values.

Eccentricities

ellipse e=1−b2a2,hyperbola e=1+b2a2\text{ellipse } e=\sqrt{1-\tfrac{b^2}{a^2}}, \quad \text{hyperbola } e=\sqrt{1+\tfrac{b^2}{a^2}}

Worked example

Find the eccentricity of the hyperbola x216−y29=1\dfrac{x^2}{16} - \dfrac{y^2}{9} = 1.

The same idea in a real exam question:

NDA · Apr 2019 · Q54Easy

Example 2 · Conics · Conic Sections — Identification and Eccentricity Comparison

The equation 2x2−3y2−6=02x^2-3y^2-6=0 represents

Ellipse and hyperbola use OPPOSITE sign relations

For the ellipse, b2=a2(1−e2)b^2 = a^2(1 - e^2) (so e<1e<1); for the hyperbola, b2=a2(e2−1)b^2 = a^2(e^2 - 1) (so e>1e>1). Using the ellipse's relation on a hyperbola — or vice versa — gives an impossible (negative) b2b^2 and the wrong eccentricity.

Concept 3 of 3: Identifying a General Second-Degree Equation

A second-degree equation in x and y can be a genuine conic — or a degenerate one (a point, a line, a pair of lines). Completing the square in both variables collapses it to a recognisable standard form, and the right-hand side tells you whether it is real, empty, or a single point.

Definition

For an equation Ax2+Cy2+Dx+Ey+F=0Ax^2 + Cy^2 + Dx + Ey + F = 0 (no xyxy term), complete the square in xx and yy:

  • Equal positive coefficients on the squares → circle; unequal same-sign → ellipse; opposite signs → hyperbola; one square missing → parabola.
  • Degenerate cases: if completing the square gives (x−h)2+k(y−j)2=0(x-h)^2 + k(y-j)^2 = 0, it is a single point; a negative right side gives no real locus; a difference equal to 0 gives a pair of straight lines.
  • A family like x2p−k+y2q−k=1\dfrac{x^2}{p-k}+\dfrac{y^2}{q-k}=1 is an ellipse when both denominators are positive and unequal, a hyperbola when they have opposite signs.

Complete the square to classify

Ax2+Cy2+Dx+Ey+F=0 →complete squares standard formAx^2 + Cy^2 + Dx + Ey + F = 0 \ \xrightarrow{\text{complete squares}}\ \text{standard form}

Worked example

What does x2+4y2−2x+8y+5=0x^2 + 4y^2 - 2x + 8y + 5 = 0 represent?

The same idea in a real exam question:

NDA · Sep 2018 · Q52Moderate

Example 3 · Conics · Conic Sections — Identification and Eccentricity Comparison

The second degree equation x2+4y2−2x−4y+2=0x^2 + 4y^2 - 2x - 4y + 2 = 0 represents

A second-degree equation is not always a curve

After completing the square, check the right-hand side: =0=0 can mean a point or a pair of lines, and a negative value means no real points at all. Don't assume every Ax2+Cy2+⋯=0Ax^2+Cy^2+\cdots=0 is an ellipse or hyperbola.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (3)

Watch out for (2)

Test yourself on Conics

15 past NDA questions from this chapter, timed at 19 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.

Related notes