PYQ Vault

NDA Maths · Differential Equations

Order, Degree and Solutions

The order of a differential equation is the highest derivative present; the degree is the power of that highest derivative once the equation is made polynomial in its derivatives; the number of arbitrary constants in a solution equals the order.

Why this matters

Start here — and bank the easy marks. 22 PYQs, and many simply ask for order and/or degree, which is pure definition once you handle one trap: clear radicals and fractional powers first. The rest connect a solution's arbitrary constants to the order.

Test yourself — a quick 13-question Differential Equations recall quiz, instant score.

Concept 1 of 2: Order and degree of a differential equation

Order counts how many times you have differentiated — it is the highest derivative that appears. Degree is the exponent on that highest derivative, but ONLY after you have cleared away any radicals or fractional powers so the equation is polynomial in its derivatives. If a derivative is trapped inside a trig or log, the degree simply does not exist.

Definition

The two classifiers:

  • Order = the order of the highest derivative present (e.g. d2y/dx2d^2y/dx^2 gives order 2).
  • Degree = the power of the highest-order derivative AFTER the equation is made free of radicals and fractional powers (made polynomial in the derivatives).
  • Degree is undefined when a derivative appears inside a transcendental function, e.g. cos⁡ ⁣(dydx)\cos\!\big(\tfrac{dy}{dx}\big) or ln⁡ ⁣(dydx)\ln\!\big(\tfrac{dy}{dx}\big).
  • Tip: dxdy=(dydx)−1\dfrac{dx}{dy} = \Big(\dfrac{dy}{dx}\Big)^{-1} — rewrite mixed derivatives in one form before reading the degree.
  • An integral sign in the equation: differentiate both sides first. kdydx=∫[1+(dydx)2]2/3dxk\dfrac{dy}{dx} = \displaystyle\int\Big[1+\Big(\dfrac{dy}{dx}\Big)^2\Big]^{2/3}dx is not yet a differential equation you can classify. Differentiating removes the integral and raises the order by one: kd2ydx2=[1+(dydx)2]2/3k\dfrac{d^2y}{dx^2} = \Big[1+\Big(\dfrac{dy}{dx}\Big)^2\Big]^{2/3}. Only now clear the fractional power and read order and degree.

Order and degree

order=order of the highest derivative presentdegree=power of the highest-order derivative, after making it polynomial in the derivatives\text{order} = \text{order of the highest derivative present} \qquad \text{degree} = \text{power of the highest-order derivative, after making it polynomial in the derivatives}

Worked example

Find the order and degree of (d2ydx2)2=1+(dydx)3\Big(\dfrac{d^2y}{dx^2}\Big)^{2} = 1 + \Big(\dfrac{dy}{dx}\Big)^{3}.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

NDA · Apr 2020 · Q74Hard

Example 1 · Differential Equations · Order, Degree, and Solutions of ODE

The order and degree of the differential equation kdydx=∫[1+(dydx)2]23dxk\frac{dy}{dx}=\int\left[1+\left(\frac{dy}{dx}\right)^2\right]^{\frac{2}{3}}dx are respectively

Clear fractional powers BEFORE reading the degree

The degree is NOT the fractional exponent you see. For (2−(y′)2)0.6=y′′\big(2-(y')^2\big)^{0.6} = y'', raise to the 5th power to get (2−(y′)2)3=(y′′)5\big(2-(y')^2\big)^3 = (y'')^5: the degree is 5, not 0.6. Make it polynomial first.

Degree is undefined when a derivative sits inside a transcendental

For d2ydx2+sin⁡ ⁣(dydx)=0\dfrac{d^2y}{dx^2} + \sin\!\big(\tfrac{dy}{dx}\big) = 0 the order is 2 but the degree does NOT exist — you can never make it polynomial in dydx\tfrac{dy}{dx}. Writing "degree 1" because you see a first power is the trap; a derivative inside sin⁡\sin, cos⁡\cos, ln⁡\ln or e(⋅)e^{(\cdot)} kills the degree.

Concept 2 of 2: Solutions and arbitrary constants

A general solution carries one arbitrary constant for each integration — so the number of arbitrary constants equals the order of the equation. Turn that around: to find the order of the ODE behind a given family, just count its independent arbitrary constants.

Definition

Solutions and what they tell you:

  • A general solution of an order-nn ODE contains exactly nn arbitrary constants; a particular solution fixes them via conditions.
  • So the order = number of independent arbitrary constants in the family. y=acos⁡x+bsin⁡xy=a\cos x+b\sin x (two constants) → order 2.
  • An ODE like d2ydx2+k2y=0\dfrac{d^2y}{dx^2}+k^2y=0 has periodic (SHM) solutions; d2ydx2−k2y=0\dfrac{d^2y}{dx^2}-k^2y=0 gives exponential growth.
  • Two members of one solution family never meet when they differ by an additive constant: y=x2+c1y=x^2+c_1 and y=x2+c2y=x^2+c_2 are vertical translates of the same curve, so setting them equal gives c1=c2c_1=c_2, a contradiction — "how many points of intersection?" is none. (Families where the constant multiplies, like y=cx2y=cx^2, DO share the origin.)

Worked example

What is the order of the differential equation whose general solution is y=c1e2x+c2e−3xy = c_1 e^{2x} + c_2 e^{-3x}?
Practice this conceptself-check · 3 quick reps

The same idea in a real exam question:

NDA · Sep 2018 · Q89Easy

Example 2 · Differential Equations · Order, Degree, and Solutions of ODE

What is the order of the differential equation whose solution is y=acos⁡x+bsin⁡x+ce−x+dy=a\cos x+b\sin x+ce^{-x}+d, where a, b, c and d are arbitrary constants?

Count INDEPENDENT constants

y=A[sin⁡(x+C)+cos⁡(x+C)]y=A[\sin(x+C)+\cos(x+C)] looks like two constants, but it collapses to Bsin⁡(x+D)B\sin(x+D) — still two independent constants, so order 2 (giving y′′+y=0y''+y=0). Combine first; constants that merge don't each count.

Summary — formulas & gotchas at a glance

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Formulas (1)

  • Order and degree of a differential equation

    Order and degree

    order=order of the highest derivative presentdegree=power of the highest-order derivative, after making it polynomial in the derivatives\text{order} = \text{order of the highest derivative present} \qquad \text{degree} = \text{power of the highest-order derivative, after making it polynomial in the derivatives}

Watch out for (3)

Test yourself on Differential Equations

20 past NDA questions from this chapter, timed at 25 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.