NDA Maths · Permutation & Combination

Combinations & Selections

Selecting a group where order doesn't matter — straight nCr selections, subsets, and the constrained selections (at-least / at-most, compulsory members, complementary counting).

Why this matters

Selection problems hinge on spotting that order is irrelevant. The high-value trick is complementary counting — 'at least one' is total minus none — which beats summing cases.

Concept 1 of 2

Selections and subsets

Intuition

A combination counts groups, not orders. Choosing rr from nn is nCr^nC_r; the number of subsets of an nn-set is 2n2^n. Fixing compulsory members just reduces the pool and the number to choose.

Definition

Choose rr of nn (order irrelevant): nCr^nC_r. Subsets of an nn-element set: 2n2^n. Compulsory members: if kk must be included, choose the rest: nkCrk^{n-k}C_{r-k}. Probabilities use favourable Ctotal C\dfrac{\text{favourable }C}{\text{total }C}.

Worked example

In how many ways can a committee of 3 be chosen from 8 people?
  1. Order irrelevant: 8C3=8763!^8C_3=\dfrac{8\cdot7\cdot6}{3!}.
Answer:5656.
Practice this conceptself-check · 4 quick reps

Try it yourself

A team of 5 is chosen from 10 players, 2 of whom must be included. How many teams?

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    Choose rr of nn, order irrelevant?
  2. 2.
    Number of subsets of an nn-set?
  3. 3.
    8C3=^8C_3=?
  4. 4.
    kk compulsory members of rr from nn?

From the bank · past-year question

Example 1Permutation & CombinationEASY
In how many ways can a team of 5 players be selected from 8 players so as not to include a particular player?

[Q44 · Apr · 2021]

Concept 2 of 2

Constrained selection: at-least, at-most, cases

Intuition

When a selection must satisfy 'at least one of X', it's almost always faster to count the complement (total minus the forbidden 'none') than to sum cases. Genuinely multi-part constraints split into disjoint cases that add.

Definition

At-least-one: totalnone\text{total}-\text{none}. **At-most kk:** sum nC0++nCk^nC_0+\cdots+^nC_k. Cases: when the constraint forces distinct sub-situations (e.g. 'choose 3 from 4 women + 3 men with a balance rule'), count each disjoint case and add. Watch for over-/under-counting at the boundaries.

Worked example

From 6 programmers and 4 typists, choose 5 with at least one typist. How many ways?
  1. Total 10C5=252^{10}C_5=252; none-typist (all programmers) 6C5=6^6C_5=6.
  2. At least one =2526=252-6.
Answer:246246.
Practice this conceptself-check · 4 quick reps

Try it yourself

How many selections of at most 2 items from 5 distinct items?

Practice — Level 1 (4 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    'At least one' is best counted as?
  2. 2.
    'At most kk' selections?
  3. 3.
    At least one typist, 5 of 6+4, none=6C5=^6C_5: answer?
  4. 4.
    When do you sum cases?

From the bank · past-year question

Example 2Permutation & CombinationHARD
A man has 7 relatives (4 women and 3 men). His wife also has 7 relatives (3 women and 4 men). In how many ways can they invite 3 women and 3 men so that 3 of them are the man's relatives and 3 are his wife's relatives?

[Q5 · Apr · 2024]

Mastery check — 5 interleaved questions

Try each one before clicking. Questions are interleaved across the concepts above, not grouped — interleaving sharpens transfer.

Example 1Permutation & CombinationMODERATE
Committee of 3 from 4 men and 5 women. P(exactly 2 men)?

[Q119 · Apr · 2018]

Example 2Permutation & CombinationEASY
What is the number of positive integer solutions of x+y+z=5x + y + z = 5?

[Q19 · Apr · 2025]

Example 3Permutation & CombinationEASY
There are 17 cricket players, out of which 5 players can bowl. In how many ways can a team of 11 players be selected so as to include 3 bowlers?

[Q16 · Sep · 2018]

Example 4Permutation & CombinationMODERATE
From 6 programmers and 4 typists, an office wants to recruit 5 people. What is the number of ways this can be done so as to recruit at least one typist?

[Q20 · Apr · 2019]

Example 5Permutation & CombinationMODERATE
A set SS contains (2n+1)(2n+1) elements. There are 4096 subsets of SS which contain at most nn elements. What is nn equal to?

[Q14 · Sep · 2023]

Drill every past-year question on this subtopic

11 questions from the bank — paginated, with cart and Word-export support.

Related notes