NDA Maths · Trigonometric Equations

General Solutions & Counting Solutions

Because sine, cosine, and tangent repeat, a trig equation has an infinite family of solutions captured by one general formula — and counting how many fall in a given interval is the most-tested skill in the chapter.

Why this matters

The chapter's hardest pocket (13 PYQs, 6 HARD). Two skills dominate: writing the general solution after reducing the equation to a standard sin = sin / cos = cos / tan = tan form, and counting the solutions inside an interval. Get the reduction right and the counting follows.

Concept 1 of 4

The General-Solution Formulas

Intuition

Solving sin θ = sin α doesn't give one answer — it gives every angle co-terminal with α or its supplement. The three general-solution formulas package that whole infinite family into a single expression with an integer parameter n.

Definition

Write each equation in the form (function of θ) = (same function of a known angle α), then:

  • sinθ=sinαθ=nπ+(1)nα\sin\theta = \sin\alpha \Rightarrow \theta = n\pi + (-1)^n \alpha
  • cosθ=cosαθ=2nπ±α\cos\theta = \cos\alpha \Rightarrow \theta = 2n\pi \pm \alpha
  • tanθ=tanαθ=nπ+α\tan\theta = \tan\alpha \Rightarrow \theta = n\pi + \alpha

for nZn \in \mathbb{Z}. The principal solution is the one in the first cycle; the general solution adds the periodic family. (Special: sinθ=0θ=nπ\sin\theta=0 \Rightarrow \theta=n\pi; cosθ=0θ=(2n+1)π2\cos\theta=0 \Rightarrow \theta=(2n+1)\tfrac{\pi}{2}.)

General solutions

sinθ=sinα: θ=nπ+(1)nα;cosθ=cosα: θ=2nπ±α;tanθ=tanα: θ=nπ+α\sin\theta=\sin\alpha:\ \theta=n\pi+(-1)^n\alpha; \quad \cos\theta=\cos\alpha:\ \theta=2n\pi\pm\alpha; \quad \tan\theta=\tan\alpha:\ \theta=n\pi+\alpha

Worked example

Find the general solution of cosθ=12\cos\theta = \tfrac{1}{2}.
  1. cosθ=cosπ3\cos\theta = \cos\tfrac{\pi}{3}, so use θ=2nπ±α\theta = 2n\pi \pm \alpha with α=π3\alpha = \tfrac{\pi}{3}.
Answer:θ=2nπ±π3, nZ\theta = 2n\pi \pm \dfrac{\pi}{3},\ n \in \mathbb{Z}.
Practice this concept2 quick reps

Practice — Level 1 (2 reps)

Quick reps to lock in the method. Try each, then check.

  1. 1.
    General solution of tanθ=1\tan\theta = 1?
  2. 2.
    General solution of sinθ=0\sin\theta = 0?

From the bank · past-year question

Example 1Trigonometric EquationsMODERATE
What is the general solution of cos100xsin100x=1\cos^{100}x-\sin^{100}x=1? (where nn is an integer)

[Q27 · Sep · 2024]

sin and cos use DIFFERENT general forms

sinθ=sinα\sin\theta=\sin\alpha uses nπ+(1)nαn\pi+(-1)^n\alpha; cosθ=cosα\cos\theta=\cos\alpha uses 2nπ±α2n\pi\pm\alpha. Swapping them is the most common error and changes which solutions you count.

Concept 2 of 4

Reducing an Equation to Standard Form

Intuition

Most equations don't arrive as sin = sin. The work is to massage them — co-function shifts, double-angle identities, or factoring a quadratic in one ratio — into a standard form. Watch for extraneous roots when you square.

Definition

Common reductions:

  • Co-function: sin2θ=cos3θ=sin(π23θ)\sin 2\theta = \cos 3\theta = \sin(\tfrac{\pi}{2} - 3\theta), then equate angles.
  • Quadratic in one ratio: equations like 2cos2x+cosx1=02\cos^2 x + \cos x - 1 = 0 factor; solve each linear factor.
  • Half-angle / Weierstrass: cscx+cotx=3\csc x + \cot x = \sqrt3 becomes 1+cosx=3sinx1 + \cos x = \sqrt3\sin x; square carefully.
  • Always verify roots in the ORIGINAL equation — squaring or dividing can introduce or drop solutions (e.g. where a denominator vanishes).

Co-function reduction

cosθ=sin ⁣(π2θ),sinθ=cos ⁣(π2θ)\cos\theta = \sin\!\left(\tfrac{\pi}{2} - \theta\right), \quad \sin\theta = \cos\!\left(\tfrac{\pi}{2} - \theta\right)

Worked example

Solve sin3θ=cos2θ\sin 3\theta = \cos 2\theta for 0<θ<π20 < \theta < \tfrac{\pi}{2}.
  1. Write cos2θ=sin(π22θ)\cos 2\theta = \sin(\tfrac{\pi}{2} - 2\theta), so sin3θ=sin(π22θ)\sin 3\theta = \sin(\tfrac{\pi}{2} - 2\theta).
  2. Equate: 3θ=π22θ5θ=π23\theta = \tfrac{\pi}{2} - 2\theta \Rightarrow 5\theta = \tfrac{\pi}{2}.
Answer:θ=π10\theta = \dfrac{\pi}{10} (i.e. 1818^\circ).

From the bank · past-year question

Example 2Trigonometric EquationsHARD
What is/are the solution(s) of the trigonometric equation cscx+cotx=3\csc x + \cot x = \sqrt{3}, where 0<x<2π0 < x < 2\pi?

[Q42 · Sep · 2018]

Squaring can add false roots

1+cosx=3sinx1 + \cos x = \sqrt3\sin x squared gives a quadratic whose roots include cosx=1\cos x = -1 — which makes the original cscx+cotx\csc x + \cot x undefined. Substitute every root back before counting.

Concept 3 of 4

Counting Solutions in an Interval

Intuition

'How many solutions?' is asking how many members of the infinite family land inside the interval. Reduce to a single function = constant, then count the periods that fit — graphically, how many times the curve crosses the level line.

Definition

To count solutions of (function) =k= k on an interval:

  • Reduce to one trig function equal to a constant (e.g. cot2xcot3x=1cos5x=0\cot 2x\cot 3x = 1 \Rightarrow \cos 5x = 0).
  • Find the general solution, then list the values of nn that keep θ\theta inside the interval.
  • Discard values where the original equation is undefined (a cotangent/cosecant blowing up, a denominator zero).
  • Graphically, the count is the number of intersections of y=(function)y = (\text{function}) with the horizontal line y=ky = k over the interval.

Count = solutions of the reduced equation in range

cot2xcot3x=1  cos5x=0  5x=(2n+1)π2\cot 2x\,\cot 3x = 1 \ \Rightarrow\ \cos 5x = 0 \ \Rightarrow\ 5x = (2n+1)\tfrac{\pi}{2}
y = ½π/65π/6πsin x = ½ on [0, 2π] → 2 solutions

Worked example

How many solutions does sin2x=12\sin 2x = \tfrac{1}{2} have on 0x<2π0 \le x < 2\pi?
  1. Let u=2xu = 2x, so u[0,4π)u \in [0, 4\pi) and sinu=12\sin u = \tfrac12.
  2. In each 2π2\pi of uu there are 2 solutions; over [0,4π)[0,4\pi) that is 2×2=42 \times 2 = 4.
Answer:44 solutions.

From the bank · past-year question

Example 3Trigonometric EquationsMODERATE
What is the number of solutions of the equation cot2xcot3x=1\cot 2x\cdot\cot 3x=1 for 0<x<π0<x<\pi?

[Q26 · Sep · 2024]

Concept 4 of 4

Range & Existence Conditions

Intuition

Before solving, check whether a solution can exist at all: sine and cosine are trapped in [−1, 1], so an equation that forces a value outside that has no solution. The same bound limits how many parameter values are allowed.

Definition

  • sinx,cosx[1,1]\sin x, \cos x \in [-1, 1], so asinx=ba\sin x = b needs ba|b| \le |a|; count integer parameters by intersecting with this range.
  • For cos100xsin100x=1\cos^{100}x - \sin^{100}x = 1: since both terms are in [0,1][0,1], equality forces cos2x=1\cos^2 x = 1, i.e. x=nπx = n\pi.
  • A boundary condition (0xπ20 \le x \le \tfrac{\pi}{2}) plus an undefined-point check often cuts the candidate solutions down to one or two.

Existence bound

asinx=b  solvable    baa\sin x = b \ \text{ solvable} \iff |b| \le |a|

Worked example

For how many integers kk does 3cosx=k3\cos x = k have a solution?
  1. cosx[1,1]\cos x \in [-1,1], so 3cosx[3,3]3\cos x \in [-3, 3]; need k[3,3]k \in [-3, 3].
  2. Integers: 3,2,1,0,1,2,3-3, -2, -1, 0, 1, 2, 3.
Answer:77 values.

From the bank · past-year question

Example 4Trigonometric EquationsMODERATE
The number of integer values of kk, for which the equation 2sinx=2k+12\sin x = 2k+1 has a solution, is

[Q6 · Apr · 2021]

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (4)

  • The General-Solution Formulas

    General solutions

    sinθ=sinα: θ=nπ+(1)nα;cosθ=cosα: θ=2nπ±α;tanθ=tanα: θ=nπ+α\sin\theta=\sin\alpha:\ \theta=n\pi+(-1)^n\alpha; \quad \cos\theta=\cos\alpha:\ \theta=2n\pi\pm\alpha; \quad \tan\theta=\tan\alpha:\ \theta=n\pi+\alpha
  • Reducing an Equation to Standard Form

    Co-function reduction

    cosθ=sin ⁣(π2θ),sinθ=cos ⁣(π2θ)\cos\theta = \sin\!\left(\tfrac{\pi}{2} - \theta\right), \quad \sin\theta = \cos\!\left(\tfrac{\pi}{2} - \theta\right)
  • Counting Solutions in an Interval

    Count = solutions of the reduced equation in range

    cot2xcot3x=1  cos5x=0  5x=(2n+1)π2\cot 2x\,\cot 3x = 1 \ \Rightarrow\ \cos 5x = 0 \ \Rightarrow\ 5x = (2n+1)\tfrac{\pi}{2}
  • Range & Existence Conditions

    Existence bound

    asinx=b  solvable    baa\sin x = b \ \text{ solvable} \iff |b| \le |a|

Watch out for (2)

Mastery check — 5 interleaved questions

Try each one before clicking. Questions are interleaved across the concepts above, not grouped — interleaving sharpens transfer.

Example 1Trigonometric EquationsMODERATE
If sin2θ=cos3θ\sin2\theta = \cos3\theta, where 0<θ<π20 < \theta < \dfrac{\pi}{2}, then what is sinθ\sin\theta equal to?

[Q45 · Apr · 2019]

Example 2Trigonometric EquationsMODERATE
If 0xπ20\leq x\leq\dfrac{\pi}{2}, then what is the number of values of xx satisfying the equation tanx+secx=2cosx\tan x+\sec x=2\cos x?

[Q49 · Sep · 2025]

Example 3Trigonometric EquationsHARD
If tan(πcosθ)=cot(πsinθ), 0<θ<π/2\tan(\pi\cos\theta)=\cot(\pi\sin\theta),\ 0<\theta<\pi/2; then what is the value of 8sin2 ⁣(θ+π4)8\sin^2\!\left(\theta+\frac{\pi}{4}\right)?

[Q29 · Sep · 2023]

Example 4Trigonometric EquationsMODERATE
What is the number of solutions of (sinθcosθ)2=2(\sin\theta-\cos\theta)^2=2 where π<θ<π-\pi<\theta<\pi?

[Q40 · Apr · 2024]

Example 5Trigonometric EquationsHARD
A is an angle in the fourth quadrant. It satisfies the trigonometric equation 3(3tan2AcotA)2=13(3-\tan^2 A - \cot A)^2 = 1. Which one of the following is a value of A?

[Q40 · Sep · 2018]

Drill every past-year question on this subtopic

13 questions from the bank — paginated, with cart and Word-export support.