NDA Physics · Laws of Motion and Forces

Impulse and Momentum

Momentum p = mv is the 'quantity of motion'; impulse is the product of force and the time it acts, and equals the change in momentum it produces.

Why this matters

A compact, high-yield subtopic — roughly 5 PYQs across 2019–2026. The two ideas are p = mv and impulse = Ft = change in momentum, plus the everyday cushioning principle (pulling hands back, jumping onto sand) that all derive from spreading a momentum change over a longer time to cut the force. One formula and one principle clear the whole subtopic.

Concept 1 of 2

Linear momentum, p = mv

Intuition

Momentum captures how hard a body is to stop — it grows with both mass and velocity. A slow truck and a fast bullet can carry the same momentum. Because velocity is a vector, momentum is a vector too: it has direction, and reversing direction changes the momentum even if the speed is unchanged.

Definition

Linear momentum is the product of a body's mass and velocity, p=mv\vec{p} = m\vec{v}. It is a vector pointing along the velocity, with SI unit kg m/s. Because it is a vector, a change in DIRECTION changes the momentum even at constant speed — this is why a bouncing ball's momentum changes while its speed (and kinetic energy) need not.

Linear momentum

p=mv\vec{p} = m\vec{v}
  • plinear momentum (kg m/s), a vector
  • mmass (kg)
  • vvelocity (m/s), a vector

Worked example

A 2 kg ball moving at 5 m/s strikes a wall and bounces straight back at 5 m/s. Find the change in its momentum.
Practice this conceptself-check · 4 quick reps

From the bank · past-year question

Example 1Laws of Motion and ForcesMODERATE
When a ball bounces off the ground, which of the following changes suddenly? (Assume no loss of energy to the floor)

[Q55 · Sep · 2019]

On an elastic bounce, momentum changes but speed and KE don't

NDA 2019 asked what changes suddenly when a ball bounces with no energy loss. Speed and kinetic energy (scalars depending on speed only) are unchanged; MOMENTUM changes because its direction reverses. The change in momentum is 2mv, not zero.

Concept 2 of 2

Impulse = change in momentum; the cushioning principle

Intuition

Impulse is force multiplied by the time it acts, and it equals the change in momentum it produces. The key insight: to change a body's momentum by a fixed amount, a small force over a long time does the same job as a large force over a short time. So if you can stretch out the contact TIME, you cut the peak FORCE — this is why a fielder pulls his hands back and why landing on sand hurts less.

Definition

Impulse J=FΔtJ = F\,\Delta t equals the change in momentum: FΔt=Δp=m(vu)F\,\Delta t = \Delta p = m(v - u) (the impulse-momentum theorem). Graphically, impulse is the area under a force-time graph. Since F=Δp/ΔtF = \Delta p / \Delta t, increasing the contact time Δt\Delta t for the same Δp\Delta p reduces the force — the basis of all cushioning.

Impulse-momentum theorem

J=FΔt=Δp=m(vu)J = F\,\Delta t = \Delta p = m(v - u)
  • Jimpulse (N·s, equivalently kg m/s)
  • F(average) force
  • Δttime over which the force acts
  • Δp = m(v − u)change in momentum

Worked example

A 0.15 kg cricket ball arrives at 20 m/s and is brought to rest by a fielder. If he stops it in 0.5 s instead of 0.1 s, compare the average force in the two cases.
Practice this conceptself-check · 4 quick reps

From the bank · past-year question

Example 2Laws of Motion and ForcesEASY
Why a fielder in the ground gradually pulls his hands backward while catching a fast moving cricket ball ?

[Q68 · Sep · 2025]

Cushioning increases TIME to reduce FORCE

Jumping onto sand, pulling hands back, crumple zones in cars, bending knees on landing — all work by increasing the impact TIME. The momentum change Δp is fixed; spreading it over a longer Δt lowers the peak force F = Δp/Δt. The reason is reduced force (reduced acceleration), not reduced momentum change.

Net force on the floor in a bounce includes weight

When a ball bounces, the floor's reaction must both reverse the ball's momentum AND support its weight. NDA 2024 (0.1 kg dropped from 0.45 m, rebounds to 0.20 m, contact 0.1 s): impact force = Δp/t = 0.1(3+2)/0.1 = 5 N, then add mg = 1 N to get 6 N net.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (2)

Watch out for (3)

Drill every past-year question on this subtopic

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