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Maharashtra SSC Class 10 Geometry March 2018 question paper

Maximum marks 40 · Time 2 hours

Try each question first, then open its model answer. Where the paper offers a choice, both questions are shown with OR between them.

Q.1

1 mark each · attempt any 5

  1. Q.1 (i)1 mark
    △DEF∼△MNK\triangle DEF \sim \triangle MNK. If DE=5DE = 5 and MN=6MN = 6, then find the value of A(△DEF)A(△MNK)\dfrac{A(\triangle DEF)}{A(\triangle MNK)}.
  2. Q.1 (ii)1 mark
    If two circles with radii 88 cm and 33 cm respectively touch externally, then find the distance between their centres.
  3. Q.1 (iii)1 mark
    Find the length of the altitude of an equilateral triangle with side 66 cm.
  4. Q.1 (iv)1 mark
    If θ=45∘\theta = 45^\circ, then find tan⁡θ\tan\theta.
  5. Q.1 (v)1 mark
    Slope of a line is 33 and yy-intercept is −4-4. Write the equation of the line.
  6. Q.1 (vi)1 mark
    Using Euler's formula, find VV, if E=30E = 30, F=12F = 12.

Q.2

2 marks each · attempt any 4

  1. Q.2 (i)2 marks
    The ratio of the areas of two triangles with the common base is 10:710 : 7. Height of the larger triangle is 1515 cm, then find the corresponding height of the smaller triangle.
  2. Q.2 (ii)2 marks
    In the following figure, point AA is the centre of the circle. Line MNMN is tangent at point MM. If AN=16AN = 16 cm and MN=8MN = 8 cm, determine the radius of the circle.
  3. Q.2 (iii)2 marks
    Draw ∠XYZ\angle XYZ of measure 50∘50^\circ and bisect it.
  4. Q.2 (iv)2 marks
    If cos⁡θ=2425\cos\theta = \dfrac{24}{25}, where θ\theta is an acute angle, find the value of sin⁡θ\sin\theta.
  5. Q.2 (v)2 marks
    The volume of a cube is 216216 cm3^3. Find its side.
  6. Q.2 (vi)2 marks
    The radius and slant height of a cone are 1010 cm and 3030 cm respectively. Find the curved surface area of that cone. (π=3.14)(\pi = 3.14)

Q.3

3 marks each · attempt any 3

  1. In the following figure, seg DH⊥DH \perp seg EFEF and seg GK⊥GK \perp seg EFEF. If DH=12DH = 12 cm, GK=20GK = 20 cm and A(△DEF)=300A(\triangle DEF) = 300 cm2^2, then find the following.
    Q.3 (i) (a)3 marks
    Find EFEF.
  2. Q.3 (i) (b)
    Find A(△GEF)A(\triangle GEF).
  3. Q.3 (i) (c)
    Find A(□DFGE)A(\square DFGE).
  4. Q.3 (ii)3 marks
    In the following figure, ray PAPA is tangent to the circle at AA and PBCPBC is a secant. If AP=18AP = 18, BP=10BP = 10, then find BCBC.
  5. Q.3 (iii)3 marks
    Draw the circle with centre CC and radius 3.33.3 cm. Take a point BB at a distance 6.66.6 cm from the centre CC. Draw tangents to the circle from the point BB.
  6. Q.3 (iv)3 marks
    Show that 1−cos⁡A1+cos⁡A=cosec⁡A−cot⁡A\sqrt{\dfrac{1 - \cos A}{1 + \cos A}} = \operatorname{cosec} A - \cot A.
  7. Q.3 (v)3 marks
    Write the equation of the line passing through A(−2,−3)A(-2, -3) and B(−4,7)B(-4, 7) in the form ax+by+c=0ax + by + c = 0.

Q.4

4 marks each · attempt any 2

  1. Q.4 (i)4 marks
    Prove that, "the lengths of the two tangent segments to a circle drawn from an external point are equal".
  2. Q.4 (ii)4 marks
    A tree is broken by the wind. The top of that tree struck the ground at an angle of 30∘30^\circ and at a distance of 3030 m from the root. Find the height of the whole tree. (3=1.73)(\sqrt{3} = 1.73)
  3. Q.4 (iii)4 marks
    A(5,4)A(5, 4), B(−3,−2)B(-3, -2) and C(1,−8)C(1, -8) are the vertices of triangle ABCABC. Find the equation of median ADAD.

Q.5

5 marks each · attempt any 2

  1. Q.5 (i)5 marks
    Prove that, in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the remaining two sides.
  2. Q.5 (ii)5 marks
    △SHR∼△SVU\triangle SHR \sim \triangle SVU. In △SHR\triangle SHR, SH=4.5SH = 4.5 cm, HR=5.2HR = 5.2 cm, SR=5.8SR = 5.8 cm and SHSV=35\dfrac{SH}{SV} = \dfrac{3}{5}. Construct △SVU\triangle SVU.
  3. Q.5 (iii)5 marks
    If VV is the volume of a cuboid of dimensions a×b×ca \times b \times c and SS is its surface area, then prove that 1V=2S(1a+1b+1c)\dfrac{1}{V} = \dfrac{2}{S}\left(\dfrac{1}{a} + \dfrac{1}{b} + \dfrac{1}{c}\right).