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JEE Mains Chemistry · Formula sheet

Classification of Elements and Periodicity formulas

4 formulas, 13 reference tables and 25 common traps for JEE Mains Chemistry Classification of Elements and Periodicity, grouped by subtopic.

Full notes with worked examples

Periodic Law, Blocks and Position in the Table

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Names for Z above 100 and the block from Z

Temporary IUPAC name

name=root(d1)+root(d2)+root(d3)+ium\text{name} = \text{root}(d_1) + \text{root}(d_2) + \text{root}(d_3) + \text{ium}

Placing an element from its configuration or an ion

Recover Z from an ion

Z=e−+qA=Z+nZ = e^{-} + q \qquad A = Z + n
  • qqcharge on the ion, with its sign (−3 for an ion X³⁻)
  • nnnumber of neutrons

From atomic weight to atomic number

Who and whenSorted byWhat they found
Döbereiner, 1829Atomic weightTriads such as Li, Na, K: the middle atomic weight is about the mean of the other two
Newlands, 1865Atomic weightLaw of octaves: every eighth element repeats the first; it worked only up to calcium
Lothar Meyer, 1869Atomic weightPlotted atomic volume against atomic weight and saw a repeating curve
Mendeleev, 1869Atomic weightLeft gaps and predicted eka-aluminium (Ga) and eka-silicon (Ge); reversed some pairs to keep families together
Moseley, 1913Atomic numberA plot of ν\sqrt{\nu} against ZZ is a straight line, so ZZ is the true basis
Only Moseley's work uses atomic number. A statement giving Newlands or Meyer atomic numbers is false.
Modern tableAtomic number18 groups and 7 periods; blocks s, p, d and f named by the subshell being filled
Everyone before 1913 used atomic weight; the modern law and table use atomic number.

Common traps

Twice the orbitals, not equal to them

Period 2 fills four orbitals (2s and three 2p) and holds eight elements. A statement that the number of elements equals the number of orbitals is false; each orbital takes two electrons.

Group, not period

Elements with similar outer configurations are stacked in one group. Along a period the outer configuration changes at every step, so a statement placing them in the same period is false.

Count the electrons before naming

When the question gives a configuration, add the core and every electron first. [Rn][\mathrm{Rn}] is 86, so a configuration ending 5f146d27s25f^{14}6d^{2}7s^{2} is Z=104Z = 104, not a number read off the last subshell.

Adding the charge the wrong way

An anion has MORE electrons than protons. For X2−\mathrm{X^{2-}} with 10 electrons, Z=8Z = 8, not 12. Write Z=e−+qZ = e^{-} + q with the sign of the charge and the direction takes care of itself.

Atomic and Ionic Radii

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Counting electrons to find isoelectronic species

Counting particles

e−=Z−qn=A−Ze^{-} = Z - q \qquad n = A - Z
  • qqcharge on the species, with its sign
  • AAmass number

Atomic radius across a period and down a group

SeriesAtomic radius (pm)Trend
Period 2Li 152, Be 111, B 88, C 77, N 74, O 66, F 64Falls steadily across
Period 3Na 186, Mg 160, Al 143, Si 117, P 110, S 104, Cl 99Falls steadily across
Group 1Li 152, Na 186, K 231, Rb 244, Cs 262Rises down the group
Group 17F 64, Cl 99, Br 114, I 133, At 140Rises down the group
Period 4 endsK 231, Br 114Largest and smallest in period 4, noble gas excluded
Compare the columns: Be (111) is smaller than Mg (160) and Mg is larger than Al (143).

Ionic radius and isoelectronic series

SpeciesProtonsElectronsRadius (pm)
Na atom1111186
Na+\mathrm{Na^+}1110102
Cl atom171799
Cl−\mathrm{Cl^-}1718184
O2−\mathrm{O^{2-}}810140
Isoelectronic with Mg2+\mathrm{Mg^{2+}} (72 pm), yet about twice as large: the same electrons do not mean the same size.
F−\mathrm{F^-}910133
Mg2+\mathrm{Mg^{2+}}121072
Al3+\mathrm{Al^{3+}}131053.5
K+\mathrm{K^+}1918138
Within the 10-electron rows, every extra proton makes the ion smaller.

Common traps

Half the bond, not double

The covalent radius is half the distance between the two nuclei in Cl2\mathrm{Cl_2}. A statement that it is double the atomic radius has the relation upside down.

Down a group beats across a period

Be is at the left of period 2 but still smaller than Mg, which has one more shell. When an order mixes groups and periods, compare the shells first.

Isoelectronic does not mean the same size

O2−\mathrm{O^{2-}} and Mg2+\mathrm{Mg^{2+}} both have 10 electrons, but Mg has 12 protons against oxygen's 8. The claim that their radii are equal is false even though the reason (both are isoelectronic) is true.

Isoelectronic ions have different nuclear charges

The whole point of the series is that Z changes while the electron count does not. A statement that O2−\mathrm{O^{2-}}, F−\mathrm{F^-}, Na+\mathrm{Na^+} and Mg2+\mathrm{Mg^{2+}} have the same nuclear charge is false.

A neutral atom is not its ion

Na has 11 electrons and Na+\mathrm{Na^+} has 10. In a list that mixes atoms and ions, count each one separately: Al and Mg are not in the 10-electron set, while Al3+\mathrm{Al^{3+}} and Mg2+\mathrm{Mg^{2+}} are.

Ionization Enthalpy

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Successive ionization enthalpies and the energy for a mass

Energy to ionize a mass of gaseous atoms

E=mM (ΔiH1+ΔiH2+… )E = \frac{m}{M}\,\left(\Delta_i H_1 + \Delta_i H_2 + \dots\right)
  • mmmass of the gaseous atoms, in g
  • MMmolar mass, in g mol⁻¹

First ionization enthalpy across a period

GroupPeriod 2 (kJ mol⁻¹)Period 3 (kJ mol⁻¹)Why
1Li 520Na 496One s electron outside a noble-gas core: lowest in the period
2Be 899Mg 737Filled ns2ns^2 subshell
13B 801Al 577Dip: the lone npnp electron is less penetrating
Group 13 sits BELOW group 2. The option with a smooth rise (Be < B) is the trap.
14C 1086Si 786Rises again
15N 1402P 1012Half-filled np3np^3: extra stable
16O 1314S 1000Dip: pairing in np4np^4 adds repulsion
Group 16 sits BELOW group 15: N > O and P > S.
17F 1681Cl 1256Rises again
18Ne 2080Ar 1520Filled shell: highest in the period
Read down each column for the period order; the two amber rows are the exceptions every question tests.

Down a group, and where it fails

GroupFirst ionization enthalpy (kJ mol⁻¹)Order and exception
1Li 520, Na 496, K 419, Rb 403, Cs 376Steady fall
2Be 899, Mg 737, Ca 590, Sr 549, Ba 503Steady fall
13B 801, Al 577, Ga 579, In 558, Tl 589B > Tl > Ga > Al > In
Ga is not below Al, and Tl is above both.
13, secondB 2427, Al 1816, Ga 1979, In 1820, Tl 1971B > Ga > Tl > In > Al
14C 1086, Si 786, Ge 761, Sn 708, Pb 715C > Si > Ge > Pb > Sn
Pb is above Sn.
18He 2372, Ne 2080, Ar 1520, Kr 1351, Xe 1170, Rn 1037Steady fall; Rn lowest
The exceptions appear only after a filled d or f subshell: from Ga, Tl and Pb onwards.

Common traps

The smooth order is the wrong option

Li < Be < B < C < N < O < F looks right and is always offered. It misses both dips. The true order swaps two pairs: Li < B < Be < C < O < N < F.

A simple fall down group 13 or 14 is wrong

An order like Al > Ga or Sn > Pb applies the group rule blindly. Poor shielding by d and f electrons lifts Ga and Pb. Check these two pairs before choosing.

Negative or smaller second values

Options such as −856 kJ mol⁻¹ or 590 kJ mol⁻¹ for the second ionization enthalpy of Mg are impossible. The second value must be positive and larger than 737.

Second ionization compares the cations

For IE₂, look at the ion that loses the electron. O+\mathrm{O^+} is 2p32p^3 and N+\mathrm{N^+} is 2p22p^2, so the dip moves one place: O is above F for IE₂, the reverse of the first ionization order.

Electron Gain Enthalpy

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When electron gain releases energy and when it costs energy

AtomElectron gain enthalpy (kJ mol⁻¹)SignWhy
He+48EndothermicElectron must enter the 2s2s shell
Ne+116EndothermicMost positive noble gas; the electron enters 3s3s
Ar+96EndothermicSame value as Kr
Kr+96EndothermicSame value as Ar
Xe+77EndothermicLarger atom, smaller cost
Li−60ExothermicHalf-filled 2s2s takes a second s electron
Na−53ExothermicSmall but negative
Cl−349ExothermicMost negative of all elements
The largest gap between two elements is Ne and Cl: 116−(−349)=465116 - (-349) = 465 kJ mol⁻¹.

Groups 16 and 17: why Cl beats F and S beats O

GroupElectron gain enthalpy (kJ mol⁻¹)Order by magnitude
17F −328, Cl −349, Br −325, I −295, At −270Cl > F > Br > I > At
F is second, not first. Cl is the most negative element in the table.
16O −141, S −200, Se −195, Te −190, Po −174S > Se > Te > Po > O
O is the least negative in group 16, below even Po.
1Li −60, Na −53, K −48, Rb −47, Cs −46Li > Na > K > Rb ≈ Cs
HydrogenH −73More negative than any alkali metal
Down each group the value becomes less negative, except that the first member of groups 16 and 17 is out of place.

Common traps

Neon, not helium, is the most positive

Helium's value (+48) is the smallest of the noble gases, and neon's (+116) the largest. Ar and Kr are equal at +96, which is why options that separate them need care.

Electron affinity flips the sign

A question that says the electron affinity is negative for Be, N and O → O²⁻ means those processes absorb energy. Electron affinity counts energy released, so it has the opposite sign to ΔegH\Delta_{eg}H.

F is not the most negative

Fluorine has the highest electronegativity, but not the most negative electron gain enthalpy. Its small 2p2p shell repels the added electron. Any statement that F's value is more negative than Cl's is false.

Signed or magnitude

"S > Se > Te > O" is right by magnitude and wrong on signed values. When one option is the exact reverse of another, the paper is testing which reading it means; pick the one consistent with the other statements in the question.

Electronegativity and Metallic Character

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Electronegativity on the Pauling scale

SeriesPauling electronegativityTrend
Period 2Li 1.0, Be 1.5, B 2.0, C 2.5, N 3.0, O 3.5, F 4.0Rises across
Period 3Na 0.9, Mg 1.2, Al 1.5, Si 1.8, P 2.1, S 2.5, Cl 3.0Rises across
Group 1Li 1.0, Na 0.9, K 0.8, Rb 0.8, Cs 0.7Falls down
Group 17F 4.0, Cl 3.0, Br 2.8, I 2.5, At 2.2Falls down
Group 13B 2.0, Al 1.5, Ga 1.6, In 1.7, Tl 1.8Falls from B to Al, then rises slightly
Poor shielding by d and f electrons again: Ga, In and Tl are above Al.
Values from the Pauling scale; the trend, not the second decimal, is what the questions test.

Metallic character and reactivity

CompareMore metallicReason
Na and MgNaLeft of Mg in period 3
Mg and AlMgLeft of Al in period 3
Be and MgMgBelow Be in group 2
K and CaKLeft of Ca in period 4
Be and SiBeSi is a metalloid; Be is a metal
N, P, O, S, Cl, FP most, F leastP is lowest and furthest left; F is top right
Down and to the left means more metallic.

Metals, non-metals, metalloids and diagonal pairs

ElementZGroupClass
B513Metalloid
Si1414Metalloid
Ge3214Metalloid
As3315Metalloid
Sb5115Metalloid
Te5216Metalloid
I5317Non-metal
Bi8315Metal
Pb8214Metal
The metalloids run diagonally from B down to Te; Bi and Pb below them are metals.

Common traps

Electronegativity is not a constant

Unlike ionization enthalpy, electronegativity belongs to an atom in a bond. The same element has different values in different compounds, so a statement that it depends on the bonded atom is correct.

Atomic radius is not always larger than ionic radius

A statement pairing a correct metallic order with "atomic radius is always greater than ionic radius" is half false: an anion is larger than its atom. Judge each statement on its own.

Bismuth is a metal

As and Sb in group 15 are metalloids, but Bi below them is a metal. Group 15 runs the whole range: N and P are non-metals, As and Sb metalloids, Bi a metal.

Nature of Oxides and Group 14 Trends

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Oxides across a period: basic to acidic

OxideNatureWith water
Na2O\mathrm{Na_2O}Strongly basicNa2O+H2O→2NaOH\mathrm{Na_2O + H_2O \to 2NaOH}
MgO\mathrm{MgO}BasicForms Mg(OH)2\mathrm{Mg(OH)_2}, sparingly soluble
Al2O3\mathrm{Al_2O_3}AmphotericInsoluble; dissolves in both acids and alkalis
SiO2\mathrm{SiO_2}AcidicInsoluble; reacts with hot NaOH to give a silicate
P4O10\mathrm{P_4O_{10}}AcidicP4O10+6H2O→4H3PO4\mathrm{P_4O_{10} + 6H_2O \to 4H_3PO_4}
SO3\mathrm{SO_3}AcidicSO3+H2O→H2SO4\mathrm{SO_3 + H_2O \to H_2SO_4}
Cl2O7\mathrm{Cl_2O_7}Strongly acidicCl2O7+H2O→2HClO4\mathrm{Cl_2O_7 + H_2O \to 2HClO_4}
Period 3 oxides in their highest oxidation states, from sodium to chlorine.

Acidic, basic, amphoteric and neutral oxides

ElementLow oxidation state oxideHigh oxidation state oxide
NitrogenN2O\mathrm{N_2O}, NO: neutralN2O3\mathrm{N_2O_3}, NO2\mathrm{NO_2}, N2O5\mathrm{N_2O_5}: acidic
CarbonCO: neutralCO2\mathrm{CO_2}: acidic
VanadiumV2O3\mathrm{V_2O_3}: basicV2O5\mathrm{V_2O_5}: amphoteric
ChromiumCrO: basic; Cr2O3\mathrm{Cr_2O_3}: amphotericCrO3\mathrm{CrO_3}: acidic
ManganeseMnO: basicMn2O7\mathrm{Mn_2O_7}: acidic
SulphurSO2\mathrm{SO_2}: acidicSO3\mathrm{SO_3}: more strongly acidic
For one element, the higher the oxidation state, the more acidic the oxide.

Group 14: oxides, inert pair effect and bond strength

ElementClassOxidesElectronegativityMelting point (K)
CNon-metalCO neutral, CO2\mathrm{CO_2} acidic2.54373
SiMetalloidSiO2\mathrm{SiO_2} acidic1.81693
GeMetalloidGeO and GeO2\mathrm{GeO_2} acidic1.81218
SnMetalSnO and SnO2\mathrm{SnO_2} amphoteric1.8505
Tin has the lowest melting point in the group, below lead.
PbMetalPbO and PbO2\mathrm{PbO_2} amphoteric1.9600
Electronegativity does not fall steadily from Si to Pb: it stays at 1.8 and then rises to 1.9.

Common traps

CO is not acidic

CO2\mathrm{CO_2} is acidic, but CO is neutral: it forms no acid with water and does not react with alkalis. Do not carry the nature of one oxide of an element over to another.

Not every nitrogen oxide is acidic

N2O\mathrm{N_2O} and NO are neutral, while N2O3\mathrm{N_2O_3}, NO2\mathrm{NO_2} and N2O5\mathrm{N_2O_5} are acidic. In a counting question, sort the nitrogen oxides one by one.

NO is neutral, not amphoteric

Al2O3\mathrm{Al_2O_3} is amphoteric, but NO reacts with neither acids nor bases. A statement that calls both amphoteric is false.

GeO is not amphoteric

SnO and PbO are amphoteric, and it is tempting to extend that to GeO. Germanium's monoxide is distinctly acidic, like its dioxide.

Lowest melting point is tin, not lead

Lead is lower in the group, but tin melts at 505 K and lead at 600 K. The melting points fall from C to Sn and rise again at Pb.

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