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JEE Mains Chemistry · Formula sheet

Electrochemistry formulas

11 formulas, 5 reference tables and 33 common traps for JEE Mains Chemistry Electrochemistry, grouped by subtopic.

Full notes with worked examples

Galvanic Cells and Electrode Potentials

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Setting up a galvanic cell

Standard cell potential

Ecell∘=Ecathode∘−Eanode∘E^\circ_{cell}=E^\circ_{cathode}-E^\circ_{anode}
  • Ecathode∘E^\circ_{cathode}reduction potential of the couple that is reduced (higher)
  • Eanode∘E^\circ_{anode}reduction potential of the couple that is oxidised (lower)

The electrochemical series

CoupleE° at 298 K (V)What it tells you
Li+/Li\mathrm{Li^+/Li}−3.05-3.05Li is the strongest reducing agent in water
Na+/Na\mathrm{Na^+/Na}−2.71-2.71Na ionises more easily than Li, yet its E° is higher
Mg2+/Mg\mathrm{Mg^{2+}/Mg}−2.37-2.37Mg displaces almost every metal ion from water
Al3+/Al\mathrm{Al^{3+}/Al}−1.66-1.66Al is a strong reducing agent
Zn2+/Zn\mathrm{Zn^{2+}/Zn}−0.76-0.76Zn is the anode of the Daniell cell
Cr3+/Cr\mathrm{Cr^{3+}/Cr}−0.74-0.74Cr is a reducing agent close to Zn
Fe2+/Fe\mathrm{Fe^{2+}/Fe}−0.44-0.44Fe dissolves in dilute acid and gives H₂
H+/12H2\mathrm{H^+/\tfrac12 H_2}0.000.00The zero of the scale, by definition
Cu2+/Cu\mathrm{Cu^{2+}/Cu}+0.34+0.34Cu does not release H₂ from dilute acid
I2/I−\mathrm{I_2/I^-}+0.54+0.54I⁻ is a fairly good reducing agent
Fe3+/Fe2+\mathrm{Fe^{3+}/Fe^{2+}}+0.77+0.77Fe³⁺ oxidises I⁻ to I₂
Ag+/Ag\mathrm{Ag^+/Ag}+0.80+0.80Ag is oxidised by nitric acid
NO3−/NO\mathrm{NO_3^-/NO}+0.97+0.97Nitrate in acid oxidises Ag but not Au
Cr2O72−/Cr3+\mathrm{Cr_2O_7^{2-}/Cr^{3+}}+1.33+1.33Dichromate in acid oxidises Ag and Fe²⁺
Cl2/Cl−\mathrm{Cl_2/Cl^-}+1.36+1.36Cl₂ oxidises Br⁻ and I⁻
Au3+/Au\mathrm{Au^{3+}/Au}+1.40+1.40Au resists every common oxidant here
MnO4−/Mn2+\mathrm{MnO_4^-/Mn^{2+}}+1.51+1.51Permanganate in acid oxidises Cl⁻
F2/F−\mathrm{F_2/F^-}+2.87+2.87F₂ is the strongest oxidising agent
Read down the table for stronger oxidising agents (the left-hand species); read up for stronger reducing agents (the right-hand species).

Common traps

Picking the oxidised form as the reducing agent

From Co3+/Co2+\mathrm{Co^{3+}/Co^{2+}} the candidate reducing agent is Co2+\mathrm{Co^{2+}}, not Co3+\mathrm{Co^{3+}}. Always read the right-hand species of a reduction couple when ranking reducing agents.

Reading the sign backwards

A more negative E∘E^\circ means a STRONGER reducing agent, not a weaker one. Lithium, at −3.05-3.05 V, is the strongest of all.

Adding the two potentials

Ecell∘E^\circ_{cell} is a difference of two reduction potentials. Flipping the anode's sign and then adding gives the same number, but adding the two tabulated values does not.

Scaling E° with the equation

Balancing electrons may double a half-reaction. Its ΔG∘\Delta G^\circ doubles; its E∘E^\circ does not, because E∘E^\circ is intensive.

Nernst Equation and Concentration Effects

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Cell emf from the Nernst equation

Nernst equation at 298 K

Ecell=Ecell∘−0.059nlog⁡QE_{cell}=E^\circ_{cell}-\frac{0.059}{n}\log Q
  • QQreaction quotient: products over reactants, powers from the balanced equation
  • nnelectrons transferred in the balanced reaction

Solving the Nernst equation for an unknown

Nernst equation, rearranged

log⁡Q=n(Ecell∘−Ecell)0.059\log Q=\frac{n\left(E^\circ_{cell}-E_{cell}\right)}{0.059}

Electrodes that depend on pH

Hydrogen electrode

EH+/H2=−0.059 pH−0.0592log⁡pH2E_{H^+/H_2}=-0.059\,\mathrm{pH}-\frac{0.059}{2}\log p_{H_2}

Common traps

Dropping the powers in Q

In Zn+2Ag+\mathrm{Zn+2Ag^+}, the silver ion is squared in QQ. The same balancing that fixes nn fixes the powers, so do both from one balanced equation.

Q upside down

QQ is products over reactants. Writing it the other way flips the sign of the log term and moves the answer by twice the correction.

Losing the sign of the log

If the measured EE is ABOVE E∘E^\circ, log⁡Q\log Q must be negative. Check this before you take the antilog; a sign slip turns 0.01 M into 100 M.

Square root forgotten

When Q=1/x2Q=1/x^2, the log gives x2x^2. Take the square root at the end.

Electrode potential is not the cell emf

"Potential of the hydrogen electrode" means the single electrode's reduction potential, −0.059 pH-0.059\,\mathrm{pH}. It is not an EcellE_{cell}, and no second electrode is subtracted.

Forgetting the pressure term

A hydrogen electrode at 2 atm or 0.1 bar needs −0.0295log⁡pH2-0.0295\log p_{H_2} as well as the pH term.

Gibbs Energy, Equilibrium Constant and Combining Potentials

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Gibbs energy, K and work from E°

Gibbs energy and equilibrium constant

ΔG∘=−nFEcell∘,log⁡K=nEcell∘0.059\Delta G^\circ=-nFE^\circ_{cell},\qquad \log K=\frac{nE^\circ_{cell}}{0.059}

Combining electrode potentials

Combining two steps

n3E3∘=n1E1∘±n2E2∘n_3E^\circ_3=n_1E^\circ_1\pm n_2E^\circ_2

Common traps

Work as charge divided by potential

Electrical work is Q×EQ\times E, in joules. A statement that puts EE in the denominator is the incorrect one.

Joules against kilojoules

nFEnFE comes out in joules. A blank asking for kJ mol⁻¹ needs a division by 1000 first.

Subtracting potentials directly

E∘(Fe3+/Fe)−E∘(Fe2+/Fe)E^\circ(\mathrm{Fe^{3+}/Fe})-E^\circ(\mathrm{Fe^{2+}/Fe}) is not E∘(Fe3+/Fe2+)E^\circ(\mathrm{Fe^{3+}/Fe^{2+}}). Weight each potential by its electrons first.

Averaging a Latimer diagram

Two steps of 1 and 2 electrons are not averaged 50:50. Divide the electron-weighted sum by the TOTAL electrons.

Conductivity, Cell Constant and Molar Conductivity

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Cell constant, conductivity and molar conductivity

From resistance to molar conductivity

κ=G∗R,Λm=1000 κc\kappa=\frac{G^*}{R},\qquad \Lambda_m=\frac{1000\,\kappa}{c}
  • G∗G^*cell constant l/A (cm⁻¹)
  • ccconcentration in mol L⁻¹

What conductance depends on

Ionλ° at 298 K (S cm² mol⁻¹)Why
H+\mathrm{H^+}349.6349.6Proton hopping along hydrogen bonds
OH−\mathrm{OH^-}199.1199.1Proton hopping, in reverse
SO42−\mathrm{SO_4^{2-}}160.0160.0Double charge carries twice the current
Ca2+\mathrm{Ca^{2+}}119.0119.0Double charge
Mg2+\mathrm{Mg^{2+}}106.0106.0Double charge, but a smaller ion is more hydrated than Ca²⁺
Br−\mathrm{Br^-}78.178.1Large anion, lightly hydrated
Cl−\mathrm{Cl^-}76.376.3Close to K⁺, which is why KCl is the standard
K+\mathrm{K^+}73.573.5Least hydrated of Li⁺, Na⁺, K⁺
Na+\mathrm{Na^+}50.150.1More hydrated than K⁺
CH3COO−\mathrm{CH_3COO^-}40.940.9Large, bulky organic anion
Li+\mathrm{Li^+}38.738.7Smallest bare ion, largest hydrated ion
Values are per mole of the ion as written.

Common traps

Mixing unit systems

The factor 1000 belongs with S cm⁻¹ and mol L⁻¹. In SI, convert cc to mol m⁻³ (multiply mol L⁻¹ by 1000) and drop the factor.

Resistivity used as conductivity

A resistivity in Ω cm must be inverted to get κ\kappa before anything else.

Bare size against hydrated size

Li+\mathrm{Li^+} is the smallest bare ion but the slowest in water. What moves is the ion with its shell of water.

κ and Λm move opposite ways

"Conductivity always decreases on dilution" is true. "Molar conductivity decreases on dilution" is false.

Molar Conductivity, Dilution and Kohlrausch's Law

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Strong and weak electrolytes on dilution

Debye–Hückel–Onsager (strong electrolytes)

Λm=Λm∘−Ac\Lambda_m=\Lambda_m^\circ-A\sqrt c

Kohlrausch's law of independent migration

Kohlrausch's law

Λm∘=ν+λ+∘+ν−λ−∘\Lambda_m^\circ=\nu_+\lambda_+^\circ+\nu_-\lambda_-^\circ

Degree of dissociation, Ka and solubility

Degree of dissociation

α=ΛmΛm∘,Ka=cα21−α\alpha=\frac{\Lambda_m}{\Lambda_m^\circ},\qquad K_a=\frac{c\alpha^2}{1-\alpha}

Common traps

Extrapolating a weak electrolyte

Only a strong electrolyte gives a straight line to read Λm∘\Lambda_m^\circ from. For a weak one the curve is nearly vertical near zero, so there is no intercept to read.

Plotting against c instead of √c

The straight line is against c\sqrt c. Taking the slope from cc values gives the wrong AA.

Doubling a divalent salt

MgSO4\mathrm{MgSO_4} has one Mg2+\mathrm{Mg^{2+}} and one SO42−\mathrm{SO_4^{2-}}. Its Λm∘\Lambda_m^\circ is λ+∘+λ−∘\lambda_+^\circ+\lambda_-^\circ, not twice that.

Leaving an ion uncancelled

Write the ions of every salt you add and subtract. The ions left over must be exactly those of the target, with the right counts.

Dropping the 1000

With κ\kappa in S cm⁻¹ and cc in mol L⁻¹, the 1000 converts litres to cm³. Leave it out and every answer is off by a thousand.

The wrong Ksp expression

Ksp=s2K_{sp}=s^2 only for a 1:1 salt. For A2X3\mathrm{A_2X_3}, Ksp=(2s)2(3s)3=108s5K_{sp}=(2s)^2(3s)^3=108s^5.

Electrolysis and Faraday's Laws

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Faraday's laws of electrolysis

Faraday's first law

m=M I tn Fm=\frac{M\,I\,t}{n\,F}
  • MMmolar mass of the substance
  • nnelectrons needed per particle
  • FF96500 C per mole of electrons

Products of electrolysis

ElectrolyteElectrodesCathodeAnode
Molten NaClInertNaCl2\mathrm{Cl_2}
Aqueous NaCl (brine)InertH2\mathrm{H_2}, with OH−\mathrm{OH^-} left in solutionCl2\mathrm{Cl_2}
Aqueous AgNO3\mathrm{AgNO_3}PtAgO2\mathrm{O_2}
Aqueous AgNO3\mathrm{AgNO_3}AgAgAg dissolves as Ag+\mathrm{Ag^+}
Aqueous CuSO4\mathrm{CuSO_4}PtCuO2\mathrm{O_2}
Aqueous CuSO4\mathrm{CuSO_4}CuCuCu dissolves as Cu2+\mathrm{Cu^{2+}}
Dilute H2SO4\mathrm{H_2SO_4}PtH2\mathrm{H_2}O2\mathrm{O_2}
Concentrated H2SO4\mathrm{H_2SO_4}PtH2\mathrm{H_2}S2O82−\mathrm{S_2O_8^{2-}}
An active anode dissolves; an inert anode oxidises an anion or water.

Common traps

Four electrons for oxygen

2H2O→O2+4H++4e−\mathrm{2H_2O\to O_2+4H^++4e^-}. One mole of O2\mathrm{O_2} needs 4 F, not 2 F.

Minutes left as minutes

Charge is I×tI\times t with tt in seconds. Convert minutes and hours before multiplying.

The charge on a complex ion's metal

Gold in AuCl4−\mathrm{AuCl_4^-} is +3, so each Au atom needs 3 electrons. Read the metal's oxidation state, not the ion's charge.

Depositing sodium from water

Water is reduced long before Na+\mathrm{Na^+} or Mg2+\mathrm{Mg^{2+}}. From an aqueous solution the cathode gives H2\mathrm{H_2}, never the metal.

Forgetting an active anode

With silver or copper electrodes, the anode metal dissolves. An option that gives O2\mathrm{O_2} there is wrong.

Batteries, Fuel Cells and Corrosion

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Primary and secondary batteries

CellAnodeCathodeElectrolyteType and use
Dry (Leclanché) cellZn containerGraphite rod in MnO2\mathrm{MnO_2} and carbonPaste of NH4Cl\mathrm{NH_4Cl} and ZnCl2\mathrm{ZnCl_2}Primary; clocks, transistors, torches
Mercury cellZn–Hg amalgamPaste of HgO and carbonPaste of KOH and ZnOPrimary; hearing aids, watches; steady voltage
Lead storage batteryPbPbO2\mathrm{PbO_2} packed on a lead gridAbout 38% H2SO4\mathrm{H_2SO_4}Secondary; cars and inverters
Nickel–cadmium cellCdNi(OH)3\mathrm{Ni(OH)_3}KOHSecondary; long life, rechargeable devices
H2\mathrm{H_2}–O2\mathrm{O_2} fuel cellPorous carbon with H2\mathrm{H_2} fed inPorous carbon with O2\mathrm{O_2} fed inConcentrated aqueous NaOH or KOHContinuous feed; Apollo space programme
Primary: used once. Secondary: recharged. Fuel cell: reactants fed in continuously.

Fuel cells and corrosion

StatementVerdictReason
The H₂–O₂ fuel cell was used in the Apollo space programmeTrueIts water was drunk by the crew
The H₂–O₂ fuel cell is about 40% efficientFalseAbout 70%, far above a thermal power plant
Its electrodes use aluminium as a catalystFalseFinely divided Pt or Pd on porous carbon
Reactants are fed in at one goFalseThey are fed in continuously
A fuel cell is a galvanic cellTrueA spontaneous reaction gives electricity
In a methanol fuel cell, methanol is oxidised at the anodeTrueThe fuel is always the anode's reactant
Rusting is an electrochemical processTrueAnodic and cathodic spots on one piece of iron
Rusting is faster in alkaline water than in acidFalseH+\mathrm{H^+} drives the cathode reaction; above pH 9 to 10 rusting stops
A tin coat protects iron even after it peelsFalseIron is below tin in the series, so exposed iron corrodes faster
A scratched zinc coat still protects ironTrueZinc is oxidised first, as a sacrificial anode

Common traps

Renaming the plates on charging

When a lead battery is charged, NCERT still calls the Pb plate the anode and the PbO2\mathrm{PbO_2} plate the cathode. Keys follow that naming.

Why the mercury cell is steady

Its overall reaction has only solids on both sides. Nothing in solution changes, so the Nernst term never moves.

Oxygen at the anode

In a fuel cell O2\mathrm{O_2} is consumed at the cathode. It is neither formed nor consumed at the anode.

Tin protects like zinc

Tin is a barrier only. Once it breaks, iron is the anode of the tin–iron couple and rusts faster than bare iron.

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