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MHT-CET Chemistry · Formula sheet

Alcohols, Phenols and Ethers formulas

16 formulas, 3 reference tables and 19 common traps for MHT-CET Chemistry Alcohols, Phenols and Ethers, grouped by subtopic.

Full notes with worked examples

Classification of Alcohols and Phenols

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Allylic, Benzylic and Vinylic Alcohols, and 1°/2°/3°

Two labels on the OH carbon

degree: 1∘/2∘/3∘ by carbons attached;allylic: C=C next door; benzylic: ring next door; vinylic: OH on C=C\text{degree: } 1^\circ/2^\circ/3^\circ \text{ by carbons attached};\quad \text{allylic: C=C next door};\ \text{benzylic: ring next door};\ \text{vinylic: OH on C=C}

Molecular Formula and the Preparations of Alcohols

The two hydrations

RCH=CH2→B2H6; H2O2/OH−RCH2CH2OH;RCH=CH2→H2SO4; H2ORCH(OH)CH3\text{RCH=CH}_2 \xrightarrow{\text{B}_2\text{H}_6;\ \text{H}_2\text{O}_2/\text{OH}^-} \text{RCH}_2\text{CH}_2\text{OH};\qquad \text{RCH=CH}_2 \xrightarrow{\text{H}_2\text{SO}_4;\ \text{H}_2\text{O}} \text{RCH(OH)CH}_3

Monohydric, Dihydric, Trihydric: the Named Diols and Phenols

CompoundOH countClassNote
Crotonyl (crotyl) alcohol1Monohydric, allylicNot dihydric despite the C=C
Ethylene glycol2Dihydric alcoholIntramolecular H-bond
Catechol / resorcinol / quinol2Dihydric phenols1,2 / 1,3 / 1,4 — isomers of each other
Resorcinol is the isomer of catechol the paper keys.
Glycerol (propylene glycerol)3Trihydric alcoholPropane-1,2,3-triol
Pyrogallol / phloroglucinol3Trihydric phenols1,2,3 / 1,3,5
Phloroglucinol is NOT dihydric.
Ascorbic acid—Not a phenolNo OH on a benzene ring
Dihydric means two OH; the benzenediols are each other's isomers.

Common traps

Calling but-3-en-1-ol allylic

Count the bonds: OH carbon → CH₂ → CH=. Two carbons away is homoallylic, not allylic. Allylic means the OH carbon is bonded directly to a double-bond carbon.

Reading '-ol' endings as OH counts

Phloroglucinol ends like a diol but has three OH groups; pyrogallol too. Count from the structure or the IUPAC name (benzene-1,3,5-triol), never from the common name.

Putting the OH on the wrong carbon in hydroboration

Hydroboration is the ANTI-Markovnikov route: boron, then OH, goes to the less substituted carbon. But-1-ene gives butan-1-ol, not butan-2-ol — the acid route gives that.

IUPAC and Common Nomenclature of Alcohols, Phenols and Ethers

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Carbinol Names and the Butyl Alcohols

Carbinol rule

R1R2R3C-OH→(R1 R2 R3) carbinol, alphabetical\text{R}_1\text{R}_2\text{R}_3\text{C-OH} \to \text{(R}_1\text{ R}_2\text{ R}_3\text{) carbinol, alphabetical}

IUPAC Names From a Drawing: Ring Alcohols, Ring Ethers, Alkenols

Locant rules

OH carbon=C1→lowest locant SET for substituents→alphabetical tie-break\text{OH carbon} = \text{C1} \to \text{lowest locant SET for substituents} \to \text{alphabetical tie-break}

Isomer Pairs: Alcohol–Ether, Position, Metamers

Same formula, or no isomerism

C4H10O: butanols (alcohol)↔ethoxyethane / methoxypropane (ethers)\text{C}_4\text{H}_{10}\text{O}: \text{ butanols (alcohol)} \leftrightarrow \text{ethoxyethane / methoxypropane (ethers)}

The Named Phenols: Common Name ↔ IUPAC Name

Common nameIUPAC nameOH positions
CatecholBenzene-1,2-diolortho
ResorcinolBenzene-1,3-diolmeta
Quinol (hydroquinone)Benzene-1,4-diolpara
PyrogallolBenzene-1,2,3-trioladjacent three
1,2,3 — not 1,3,5.
PhloroglucinolBenzene-1,3,5-triolalternate three
o-Cresol2-MethylphenolOH + CH₃ ortho
The planted wrong pairing is 'o-cresol : benzene-1,2,3-triol'.
GlycerolPropane-1,2,3-triol—
Diols: cat-ortho, res-meta, quin-para. Triols: pyro-1,2,3, phloro-1,3,5.

Common traps

Naming isobutyl alcohol 'isobutyl carbinol'

The carbinol carbon is the CH₂OH; what hangs on it is an ISOPROPYL group. Isobutyl carbinol would be a five-carbon alcohol.

Swapping pyrogallol and phloroglucinol

Both are triols. Pyrogallol's three OH are ADJACENT (1,2,3); phloroglucinol's alternate (1,3,5). The two are always offered together.

Numbering the ring the short way

Going from C1 towards the methyl gives 2-methyl-5-ethyl — same locant set, wrong alphabetical order. The 2023 paper keyed 2-ethyl-3-methyl for a drawing with the groups on the same side and 2-ethyl-5-methyl for one with them on opposite sides; look at the drawing, not the option you remember.

Assuming any two ethers are metamers

Metamers must share a molecular formula. Methoxyethane (C₃) and ethoxyethane (C₄) differ by a CH₂ — homologues, not isomers of any kind.

Physical Properties of Alcohols, Phenols and Ethers

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Boiling Points: H-Bonding, Chain Length, Branching

Boiling-point levers

H-bonding↑, chain length↑⇒b.p.↑;branching↑⇒b.p.↓\text{H-bonding} \uparrow,\ \text{chain length} \uparrow \Rightarrow \text{b.p.} \uparrow;\qquad \text{branching} \uparrow \Rightarrow \text{b.p.} \downarrow

Solubility in Water and the Kinds of Hydrogen Bond

Solubility order

R-OH>R-NH2>R-H(H-bonding with water decides)\text{R-OH} > \text{R-NH}_2 > \text{R-H} \quad (\text{H-bonding with water decides})

p-Nitrophenol Melts Highest: Inter- Versus Intramolecular H-Bonds

Which H-bond

ortho: intramolecular⇒low m.p., volatile;para: intermolecular⇒high m.p.\text{ortho: intramolecular} \Rightarrow \text{low m.p., volatile};\qquad \text{para: intermolecular} \Rightarrow \text{high m.p.}

Common traps

Ranking iso-butyl above sec-butyl

The measured values put isobutyl (108 °C) above sec-butyl (100 °C), but the paper's keyed order is n > sec > iso > tert — 'branching lowers boiling point' counted by the position of the branch. Give the paper's order; the endpoints (n highest, tert lowest) are never in doubt.

Ranking the amine above the alcohol

N–H···O bonds are weaker than O–H···O. Amines dissolve, but less than alcohols of the same size. The alkane, with no H-bonding, is always last.

Picking o-nitrophenol for the highest melting point

Its hydrogen bond is INSIDE the molecule and does nothing to hold molecules together. p-Nitrophenol, whose OH must bond to a neighbour, melts almost 70 °C higher.

Chemical Reactions of Alcohols and Acidity

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Lucas Reagent and the HX Reactivity Order

Lucas test

R-OH→conc. HCl / ZnCl2R-Cl (turbid);3∘ instant>2∘ minutes>1∘ none\text{R-OH} \xrightarrow{\text{conc. HCl / ZnCl}_2} \text{R-Cl}\ (\text{turbid});\quad 3^\circ \text{ instant} > 2^\circ \text{ minutes} > 1^\circ \text{ none}

Dehydration (Saytzeff, With Rearrangement) and Oxidation

Dehydration

R2CH-CH(OH)R→conc. H2SO4, ΔR2C=CHR+H2O(Saytzeff, after any hydride shift)\text{R}_2\text{CH-CH(OH)R} \xrightarrow{\text{conc. H}_2\text{SO}_4,\ \Delta} \text{R}_2\text{C=CHR} + \text{H}_2\text{O} \quad (\text{Saytzeff, after any hydride shift})

Alcohols From Grignard Reagents; Acidity of Alcohols and Phenols

Grignard to alcohol

HCHO→1∘;RCHO→2∘;R2CO→3∘(then H3O+)\text{HCHO} \to 1^\circ;\quad \text{RCHO} \to 2^\circ;\quad \text{R}_2\text{CO} \to 3^\circ \quad (\text{then H}_3\text{O}^+)

Common traps

Marking esterification as C–O cleavage

In R–OH + R'COOH the alcohol keeps its oxygen (the ester is R'CO–O–R); it is the O–H bond that breaks. C–O breaks only when the whole OH leaves — HX, PX₃, SOCl₂, dehydration.

Eliminating from the carbon that carried the OH

The secondary cation rearranges before it loses a proton. Hex-3-ene from 2-methylhexan-3-ol is the drawing beside the right answer; the hydride shift moves the double bond to the branched carbon.

Counting the Grignard carbon into the wrong place

3-Methylpentan-3-ol has C3 bearing OH, methyl, ethyl, ethyl. One ethyl came from the Grignard, so the ketone had methyl + ethyl on the carbonyl: butanone, not propanone.

Phenols: Preparation and Reactions

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Making Phenol: Cumene and Dow

Cumene route

C6H5CH(CH3)2→O2C6H5C(CH3)2OOH→H+C6H5OH+(CH3)2CO\text{C}_6\text{H}_5\text{CH(CH}_3)_2 \xrightarrow{\text{O}_2} \text{C}_6\text{H}_5\text{C(CH}_3)_2\text{OOH} \xrightarrow{\text{H}^+} \text{C}_6\text{H}_5\text{OH} + (\text{CH}_3)_2\text{CO}

Nitration and Bromination of Phenol

How far the reaction goes

dil. HNO3→o/p-nitrophenol;HNO3/H2SO4→picric acid;Br2(aq)→2,4,6-tribromophenol\text{dil. HNO}_3 \to o/p\text{-nitrophenol};\quad \text{HNO}_3/\text{H}_2\text{SO}_4 \to \text{picric acid};\quad \text{Br}_2(\text{aq}) \to 2,4,6\text{-tribromophenol}

Kolbe, Reimer–Tiemann, Oxidation and Reduction of Phenol

Kolbe and Reimer–Tiemann

ArONa+CO2→o-HOC6H4COONa→salicylic acid;ArOH+CHCl3/NaOH→o-HOC6H4CHO\text{ArONa} + \text{CO}_2 \to o\text{-HOC}_6\text{H}_4\text{COONa} \to \text{salicylic acid};\qquad \text{ArOH} + \text{CHCl}_3/\text{NaOH} \to o\text{-HOC}_6\text{H}_4\text{CHO}

Phenols in Nature: Eugenol, Gallic Acid, Curcumin and the Polyols

PhenolSourceProperty / use
EugenolCloveAnalgesic and antimicrobial
Not 'antiseptic' alone — the paper keys the analgesic-and-antimicrobial pair.
Gallic acidIndian gooseberry (amla), gall nutsAntioxidant
CurcuminTurmericAntioxidant, anti-inflammatory
Methyl salicylateWintergreenLiniment
Ascorbic acidCitrus fruitsVitamin C — NOT a phenol
No OH on a benzene ring.
Source and use are asked in both directions.

Common traps

Stopping at cumene hydroperoxide

The hydroperoxide is the intermediate; the question asks for the products after dilute acid — phenol AND acetone, both of them, which is why the process pays.

Trinitrating with dilute acid

Dilute HNO₃ gives the mononitro mixture; 2,4,6-trinitrophenol needs the mixed acid. Bromine is the opposite case — WATER gives the tri-substituted product, the organic solvent the mono.

Starting Kolbe from phenol itself

The substrate is SODIUM PHENOXIDE — the phenoxide ion is what attacks CO₂. 'Phenol' is offered as option (a) and is wrong.

Confusing the 1,2,3 and 1,3,5 triol drawings

Phloroglucinol is the SYMMETRIC one — OH at alternate carbons. Three OH in a row is pyrogallol; the paper draws both and asks for one.

Ethers: Preparation and Reactions

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Williamson Synthesis: Alkoxide Plus Primary Halide

Williamson synthesis

R-O−Na++R’-X→SN2R-O-R’+NaX(R’X primary; never aryl)\text{R-O}^-\text{Na}^+ + \text{R'-X} \xrightarrow{\text{SN2}} \text{R-O-R'} + \text{NaX} \quad (\text{R'X primary; never aryl})

Reactions of Ethers: Oxonium Salts, HI Cleavage, Anisole

Cleavage by HI

Ar-O-R+HI→ΔAr-OH+R-I(aryl-O bond survives)\text{Ar-O-R} + \text{HI} \xrightarrow{\Delta} \text{Ar-OH} + \text{R-I} \quad (\text{aryl-O bond survives})

Common traps

Expecting isobutylene from methyl bromide and tert-butoxide

Elimination needs a β-hydrogen on the HALIDE; methyl bromide has none. The bulky base simply attacks the unhindered methyl carbon: MTBE forms.

Cleaving the aryl side with HI

The aryl–oxygen bond has partial double-bond character and does not break. Anisole gives phenol + CH₃I; 'iodobenzene + methanol' is the planted option.

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