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NDA Mathematics · Formula sheet

Properties of Triangle formulas

13 formulas and 12 common traps for NDA Mathematics Properties of Triangle, grouped by subtopic.

Full notes with worked examples

Sine & Cosine Rules — Solving Triangles

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Triangle Notation & Basic Relations

Angle sum & semi-perimeter

A+B+C=π,s=a+b+c2A + B + C = \pi, \qquad s = \dfrac{a+b+c}{2}

The Sine Rule

Sine rule

asin⁡A=bsin⁡B=csin⁡C=2R\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C} = 2R

The Cosine Rule

Cosine rule

cos⁡C=a2+b2−c22ab\cos C = \dfrac{a^2 + b^2 - c^2}{2ab}

Determining the Nature of a Triangle

Right-angle tests

c2=a2+b2  ⟺  C=90∘  ⟺  cos⁡2A+cos⁡2B+cos⁡2C=1c^2 = a^2 + b^2 \iff C = 90^\circ \iff \cos^2 A + \cos^2 B + \cos^2 C = 1

Area of a Triangle

Area formulas

Δ=12absin⁡C=s(s−a)(s−b)(s−c)=abc4R=rs\Delta = \tfrac12 ab\sin C = \sqrt{s(s-a)(s-b)(s-c)} = \dfrac{abc}{4R} = rs

Angle Ratios ↔ Side Ratios

Sides proportional to sines

a:b:c=sin⁡A:sin⁡B:sin⁡Ca : b : c = \sin A : \sin B : \sin C

Sine Rule in Geometric Configurations

Sine rule in a sub-triangle

ABsin⁡(∠ADB)=ADsin⁡(∠ABD)\dfrac{AB}{\sin(\angle ADB)} = \dfrac{AD}{\sin(\angle ABD)}

Common traps

Side over sine of its OWN opposite angle

The sine rule pairs each side with the angle facing it: asin⁡A\frac{a}{\sin A}, never asin⁡B\frac{a}{\sin B}. Pairing a side with the wrong angle is the classic slip.

The ratio is 2R2R, not RR

The common ratio asin⁡A\frac{a}{\sin A} equals the DIAMETER of the circumcircle, 2R2R — not the radius RR. So a=2Rsin⁡Aa = 2R\sin A; forgetting the factor 2 halves your circumradius.

The ambiguous SSA case can give TWO triangles

Given two sides and a non-included angle, the sine rule can yield a sine value that fits two angles (θ\theta and 180∘−θ180^\circ-\theta), producing two valid triangles. Don't assume the answer is unique without checking the angle sum.

Put the opposite side as the one being squared on the left

For angle CC, the formula has c2c^2 (the side opposite CC) isolated and −2abcos⁡C-2ab\cos C. Mixing up which side is opposite the angle flips the sign of the cosine and the verdict on acute/obtuse.

A negative cosine means an OBTUSE angle

When cos⁡C=a2+b2−c22ab\cos C = \frac{a^2+b^2-c^2}{2ab} comes out negative, the angle is obtuse (between 90∘90^\circ and 180∘180^\circ) — don't discard it as 'impossible'. It is acute only when the numerator a2+b2−c2>0a^2+b^2-c^2 > 0.

Test a2+b2=c2a^2+b^2 = c^2 on the LARGEST side only

The right-angle test a2+b2=c2a^2 + b^2 = c^2 must use the largest side as cc. Plugging a shorter side in for cc will fail even for a genuine right triangle — the right angle always faces the longest side.

Area uses sin⁡\sin of the angle, not cos⁡\cos

The two-sides-and-included-angle area is Δ=12absin⁡C\Delta = \tfrac12 ab\sin C. Writing 12abcos⁡C\tfrac12 ab\cos C is a classic slip — cos⁡\cos belongs to the cosine rule, not the area.

Heron's ss is the SEMI-perimeter

In Δ=s(s−a)(s−b)(s−c)\Delta = \sqrt{s(s-a)(s-b)(s-c)}, s=a+b+c2s = \frac{a+b+c}{2} — half the perimeter. Using the full perimeter a+b+ca+b+c gives a badly wrong area.

Triangle Identities — A+B+C = π, Half & Double Angle

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Consequences of A + B + C = π

Half-angle complement

sin⁡B+C2=cos⁡A2,sin⁡(B+C)=sin⁡A\sin\dfrac{B+C}{2} = \cos\dfrac{A}{2}, \qquad \sin(B+C) = \sin A

The tan-Sum = tan-Product Identity

tan sum = tan product

tan⁡A+tan⁡B+tan⁡C=tan⁡A tan⁡B tan⁡C\tan A + \tan B + \tan C = \tan A\,\tan B\,\tan C

cos 2A Sums & Right-Angle Detection

Right-angle signature

sin⁡2A+sin⁡2B+sin⁡2C=2  ⟺  right-angled\sin^2 A + \sin^2 B + \sin^2 C = 2 \iff \text{right-angled}

Half-Angle Formulas & Sum-to-Product

Half-angle tangent

tan⁡A2=rs−a=(s−b)(s−c)s(s−a)\tan\dfrac{A}{2} = \dfrac{r}{s-a} = \sqrt{\dfrac{(s-b)(s-c)}{s(s-a)}}

Common traps

sin⁡(B+C)=+sin⁡A\sin(B+C) = +\sin A, but cos⁡(B+C)=−cos⁡A\cos(B+C) = -\cos A

Both B+CB+C and AA sum to π\pi, so sin⁡(B+C)=sin⁡A\sin(B+C) = \sin A (same sign) but cos⁡(B+C)=−cos⁡A\cos(B+C) = -\cos A (opposite sign). Forgetting the minus on the cosine is the standard error.

The sum equals the PRODUCT, only in a triangle

tan⁡A+tan⁡B+tan⁡C=tan⁡Atan⁡Btan⁡C\tan A + \tan B + \tan C = \tan A\tan B\tan C holds because A+B+C=πA+B+C=\pi. It is NOT a general identity — don't apply it unless the three angles are a triangle's angles.

In-circle, Circumcircle & Regular Polygons

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Incircle, Circumcircle & the Central Angle

Inradius, circumradius, central angle

r=Δs,R=abc4Δ,∠BOC=2 ∠BACr = \dfrac{\Delta}{s}, \quad R = \dfrac{abc}{4\Delta}, \quad \angle BOC = 2\,\angle BAC

Regular Polygon Geometry

Regular n-gon inradius

r=s2cot⁡πn,interior angle=(n−2)180∘nr = \dfrac{s}{2}\cot\dfrac{\pi}{n}, \qquad \text{interior angle} = \dfrac{(n-2)180^\circ}{n}

Common traps

Inradius rr vs circumradius RR — different formulas

The INradius (inside, touching the sides) is r=Δsr = \frac{\Delta}{s}; the CIRCUMradius (through the vertices) is R=abc4ΔR = \frac{abc}{4\Delta}. Swapping the two — using Δs\frac{\Delta}{s} when the circle passes through the vertices — is the most common error here.

Central angle is TWICE the inscribed angle

An arc subtends ∠BOC=2 ∠BAC\angle BOC = 2\,\angle BAC at the centre — twice, not half, the inscribed angle. Halving it instead of doubling reverses the relation.

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