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Day 130: JEE Mains Chemistry

5 questions. Try each one first, then open its answer.

  1. Question 1

    The p-Block Elements. Asked once: 31 Jan 2023 (same type asked 5 times) See all 5 of this type

    130
    Given below are two statements: Statement I: Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green Statement II: The green colour observerd is due to the formation of copper(I) metaborate In the light of the above statements, choose the most appropriate answer from the options given below:

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  2. Question 2

    Solutions. Asked once: 2 Apr 2025 (same type asked 5 times) See all 5 of this type

    32
    A solution is made by mixing one mole of volatile liquid AA with 3 moles of volatile liquid BB. The vapour pressure of pure A is 200 mm Hg and that of the solution is 500 mm Hg . The vapour pressure of pure B and the least volatile component of the solution, respectively, are :

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  3. Question 3

    Biomolecules. Asked once: 2 Apr 2025 (same type asked 5 times) See all 5 of this type

    119
    A tetrapeptide " xx " on complete hydrolysis produced glycine (Gly), alanine (Ala), valine (Val), leucine (Leu) in equimolar proportion each. The number of tetrapeptides (sequences) possible involving each of these amino acids is.

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  4. Question 4

    Chemical Kinetics. Asked once: 1 Feb 2024 (same type asked 5 times) See all 5 of this type

    54
    The ratio of  14C 12C\frac{\ ^{14}C}{\ ^{12}C} in a piece of wood is 18\frac{1}{8} part that of atmosphere. If half life of  14C\ ^{14}C is 5730 years, the age of wood sample is.... years.

  5. Question 5

    Chemical Kinetics. Asked once: 30 Jan 2024 (same type asked 5 times) See all 5 of this type

    142
    NO2NO_{2} required for a reaction is produced by decomposition of N2O5N_{2}O_{5} in CCl4CCl_{4} as by equation 2 N2O5( g)→4NO2( g)+O2( g)2{\text{ }N}_{2}O_{5(\text{ }g)}\rightarrow 4NO_{2(\text{ }g)}+O_{2(\text{ }g)} The initial concentration of N2O5N_{2}O_{5} is 3 mol L−13\text{ }mol{\text{ }L}^{- 1} and it is 2.75 mol L−12.75\text{ }mol{\text{ }L}^{- 1} after 30 minutes. The rate of formation of NO2NO_{2} is x×10−3 mol L−1x \times10^{- 3}\text{ }mol{\text{ }L}^{- 1} min⁡−1\min^{- 1}, value of xx is _______