PYQ Vault
EbooksTutor

Day 183: JEE Mains Chemistry

5 questions. Try each one first, then open its answer.

  1. Question 1

    Hydrocarbons. Asked once: 29 Jun 2022 (same type asked 2 times) See all 2 of this type

    134
    The stable carbocation formed in the above reaction is :

    Tap an option to check your answer.

  2. Question 2

    Chemical Bonding and Molecular Structure. Asked once: 1 Feb 2024 (same type asked 2 times) See all 2 of this type

    122
    Given below are two statements: Statement (I): A π\pi bonding MO has lower electron density above and below the inter-nuclear axis. Statement (II): The π∗\pi^{*} antibonding MO has a node between the nuclei. In the light of the above statements, choose the most appropriate answer from the options given below:

    Tap an option to check your answer.

  3. Question 3

    Chemical Thermodynamics. Asked once: 14 Jun 2022 (same type asked 2 times) See all 2 of this type

    52
    2O3(g)⇌3O2(g)2O_{3}(g) \rightleftharpoons 3O_{2}(g)
    At 300 K300\text{ }K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm1\text{ }atm pressure is (−)000‾ J mol−1(-)\underline{\phantom{000}}\ J\ mol^{-1} (Nearest integer) [Given: ln⁡1.35=0.3\ln 1.35 = 0.3 and R=8.3 J K−1 mol−1R = 8.3\text{ }J\text{ }K^{-1}\text{ }mol^{-1}]

  4. Question 4

    Electrochemistry. Asked once: 25 Jul 2022 (same type asked 2 times) See all 2 of this type

    54
    The cell potential for Zn∣Zn2+(aq)∣∣Snx+∣SnZn\left| Zn^{2+}(aq) \right|\left| Sn^{x+} \right|Sn is 0.801 V0.801\text{ }V at 298 K298\text{ }K. The reaction quotient for the above reaction is 10−210^{-2}. The number of electrons involved in the given electrochemical cell reaction is ____. (Given EZn2+∣Zn0=−0.763 V,ESnx+∣Sn0=+0.008 VE_{Zn^{2+}\mid Zn}^{0}= -0.763\text{ }V, E_{Sn^{x+}\mid Sn}^{0}= +0.008\text{ }V and 2.303RTF=0.06 V\frac{2.303RT}{F}= 0.06\text{ }V)

  5. Question 5

    Solutions. Asked once: 9 Apr 2024 (same type asked 2 times) See all 2 of this type

    50
    0.05 M CuSO40.05\ M\ CuSO_{4} when treated with 0.01 M K2Cr2O70.01\ M\ K_{2}Cr_{2}O_{7} gives green colour solution of Cu2Cr2O7Cu_{2}Cr_{2}O_{7}. The two solutions are separated by a semipermeable membrane (SPM), K2Cr2O7K_{2}Cr_{2}O_{7} on the left and CuSO4CuSO_{4} on the right, as shown. Due to osmosis:

    Tap an option to check your answer.