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Day 362: JEE Mains Chemistry

5 questions. Try each one first, then open its answer.

  1. Question 1

    Some Basic Concepts of Chemistry. Asked once: 2021 Paper 22 (same type asked 9 times) See all 9 of this type

    52
    The molarity of the solution prepared by dissolving 6.3 g6.3\text{ }g of oxalic acid (H2C2O4⋅2H2O)\left( H_{2}C_{2}O_{4}\cdot 2H_{2}O \right) in 250 mL250\text{ }mL of water in molL−1molL^{- 1} is x×10−2x \times10^{- 2}. The value of xx is (Nearest integer) [Atomic mass: H:1.0,C:12.0,O:16.0H:1.0,C:12.0,O:16.0 ]

  2. Question 2

    Organic Chemistry - Some Basic Principles and Techniques. Asked once: 25 Jan 2023 (same type asked 8 times) See all 8 of this type

    130
    Match List I with List II
    LIST I (Isomeric pairs)LIST II (Type of isomers)
    A.Propanamine and N-MethylethanamineI.Metamers
    B.Hexan-2-one and Hexan-3-oneII.Positional isomers
    C.Ethanamide and HydroxyethanimineIII.Functional isomers
    D.o-nitrophenol and p-nitrophenolIV.Tautomers
    Choose the correct answer from the options given below:

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  3. Question 3

    Structure of Atom. Asked once: 24 Jan 2023 (same type asked 8 times) See all 8 of this type

    55
    If wavelength of the first line of the Paschen series of hydrogen atom is 20 nm20\text{ }nm, then the wavelength of the second line of this series is ____ nmnm. (Nearest integer)

  4. Question 4

    Some Basic Concepts of Chemistry. Asked once: 29 Jul 2022 (same type asked 8 times) See all 8 of this type

    121
    Consider the reaction
    4HNO3(l)+3KCl(s)→Cl2( g)+NOCl(g)+4HNO_{3}(l) + 3KCl(s) \rightarrow Cl_{2}(\text{ }g) + NOCl(g) +
    2H2O(g)+3KNO3( s)2H_{2}O(g) + 3KNO_{3}(\text{ }s)
    The amount of HNO3HNO_{3} required to produce 110.0 g110.0\text{ }g of KNO3KNO_{3} is: (Given: Atomic masses of H,O,NH,O,N and KK are 1, 16,14 and 39, respectively.)

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  5. Question 5

    Some Basic Concepts of Chemistry. Asked once: 2021 Paper 17 (same type asked 8 times) See all 8 of this type

    54
     10.0 mL\ 10.0\text{ }mL of 0.05MKMnO40.05MKMnO_{4} solution was consumed in a titration with 10.0 mL10.0\text{ }mL of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is ×10−2 g/L\times10^{- 2}\text{ }g/L. (Round off to the nearest integer)