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Day 308: JEE Mains Physics

5 questions. Try each one first, then open its answer.

  1. Question 1

    System of Particles and Rotational Motion. Asked once: 31 Jan 2023 (same type asked 3 times) See all 3 of this type

    119
    Two discs of same mass and different radii are made of different materials such that their thicknesses are 1 cm1\text{ }cm and 0.5 cm0.5\text{ }cm respectively. The densities of materials are in the ratio 3:5. The moment of inertia of these discs respectively about their diameters will be in the ratio of x6\frac{x}{6}. The value of xx is____

  2. Question 2

    Motion in a Plane. Asked once: 31 Jan 2023 (same type asked 3 times) See all 3 of this type

    26
    The speed of a swimmer is 4 km h−14\text{ }km{\text{ }h}^{- 1} in still water. If the swimmer makes his strokes normal to the flow of river of width 1 km1\text{ }km, he reaches a point 750 m750\text{ }m down the stream on the opposite bank. The speed of the river water is___ kmh−1kmh^{- 1}.

  3. Question 3

    System of Particles and Rotational Motion. Asked once: 28 Jun 2022 (same type asked 3 times) See all 3 of this type

    25
    The position vector of 1 kg1\text{ }kg object is r→=(3i^−j^)m\overrightarrow{r}= (3\widehat{i}-\widehat{j})m and its velocity v→=(3j^+k^)ms−1\overrightarrow{v}= (3\widehat{j}+\widehat{k})ms^{- 1}. The magnitude of its angular momentum is x kg m2s−1\sqrt{x}\ kg\ m^{2}s^{- 1} where xx is

  4. Question 4

    Thermal Properties of Matter. Asked once: 29 Jun 2022 (same type asked 3 times) See all 3 of this type

    92
    At what temperature a gold ring of diameter 6.230 cmcm be heated so that it can be fitted on a wooden bangle of diameter 6.241 cm6.241\text{ }cm ? Both the diameters have been measured at room temperature (27∘C)\left( 27^{\circ}C \right). (Given: coefficient of linear thermal expansion of gold αL=1.4×10−5 K−1\alpha_{L}= 1.4 \times10^{- 5}{\text{ }K}^{- 1} )

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  5. Question 5

    Electrostatics. Asked once: 29 Jan 2024 (same type asked 3 times) See all 3 of this type

    110
    An electric field is given by (6i^+5j^+3k^)N/C(6\widehat{i}+ 5\widehat{j}+ 3\widehat{k})N/C. The electric flux through a surface area 30i^m230\widehat{i}m^{2} lying in YZ-plane (in SI unit) is:

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