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Day 384: JEE Mains Physics

5 questions. Try each one first, then open its answer.

  1. Question 1

    Electromagnetic Induction. Asked once: 24 Jan 2023 (same type asked 6 times) See all 6 of this type

    104
    A metallic rod of length ' LL ' is rotated with an angular speed of ' ω\omega ' normal to a uniform magnetic field ' BB ' about an axis passing through one end of rod as shown in figure. The induced emf will be:

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  2. Question 2

    Kinetic Theory. Asked once: 2021 Paper 24 (same type asked 6 times) See all 6 of this type

    25
    The average translational kinetic energy of N2N_{2} gas molecules at ____\_\_\_\_ ∘C^{\circ}C becomes equal to the K.E. of an electron accelerated from rest through a potential difference of 0.1 volt. (Given kB=1.38×10−23 J/Kk_{B}= 1.38 \times10^{- 23}\text{ }J/K ) (Fill the nearest integer).

  3. Question 3

    Wave Optics. Asked once: 2021 Paper 23 (same type asked 6 times) See all 6 of this type

    25
    In a Young's double slit experiment, the slits are separated by 0.3 mm0.3\text{ }mm and the screen is 1.5 m1.5\text{ }m away from the plane of slits. Distance between fourth bright fringes on both sides of central bright is 2.4 cm2.4\text{ }cm. The frequency of light used is ____×1014 Hz\_\_\_\_ \times10^{14}\text{ }Hz.

  4. Question 4

    Work, Energy and Power. Asked once: 1 Feb 2023 (same type asked 6 times) See all 6 of this type

    117
    A force F=(5+3y2)F =\left( 5 + 3y^{2} \right) acts on a particle in the yy-direction, where FF is in newton and yy is in meter. The work done by the force during a displacement from y=2 my = 2\text{ }m to y=5 my = 5\text{ }m is ____J.

  5. Question 5

    Dual Nature of Radiation and Matter. Asked once: 2021 Paper 18 (same type asked 6 times) See all 6 of this type

    11
    In a photoelectric experiment, ultraviolet light of wavelength 280 nm280\text{ }nm is used with a lithium cathode of work function ϕ=2.5 eV\phi=2.5\,eV. If the wavelength of the incident light is switched to 400 nm400\text{ }nm, find the change in the stopping potential. (h=6.63×10−34 Jsh = 6.63\times10^{-34}\,Js, c=3×108 ms−1c = 3\times10^{8}\text{ }ms^{-1})

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