PYQ Vault

Day 30: MHT-CET Chemistry

5 questions. Try each one first, then open its answer.

  1. Question 1

    Solutions and Colligative Properties. This type asked 7 times: 9 May 2023 S1, 9 May 2024 S2, 11 May 2024 S2, 19 Apr 2025 S2, 26 Apr 2025 S2, 15 Apr 2026 S2, 17 Apr 2026 S2. This one: 17 Apr 2026 S2 See all 7 of this type

    23
    Calculate the cryoscopic constant of a solvent if depression in freezing point of 0.30.3 m solution of nonelectrolyte is 0.480.48 K

    Tap an option to check your answer.

  2. Question 2

    Introduction to Polymer Chemistry. This type asked 7 times: 3 May 2023 S1, 4 May 2023 S2, 9 May 2024 S1, 10 May 2024 S2, 11 May 2024 S1, 21 Apr 2025 S2, 17 Apr 2026 S1. This one: 17 Apr 2026 S1 See all 7 of this type

    49
    Which from following is a homopolymer ?

    Tap an option to check your answer.

  3. Question 3

    Some Basic Concepts of Chemistry. This type asked 7 times: 9 May 2023 S2, 14 May 2024 S1, 21 Apr 2025 S1, 21 Apr 2025 S2, 22 Apr 2025 S2, 23 Apr 2025 S1, 17 Apr 2026 S1. This one: 17 Apr 2026 S1 See all 7 of this type

    1
    Calculate the number of molecules present in 2.24 dm3\mathrm{dm^3} of carbon dioxide at STP ?

    Tap an option to check your answer.

  4. Question 4

    Coordination Compounds. This type asked 7 times: 16 May 2023 S2, 9 May 2024 S1, 12 May 2024 S1, 22 Apr 2025 S1, 22 Apr 2025 S2, 25 Apr 2025 S1, 13 Apr 2026 S1. This one: 13 Apr 2026 S1 See all 7 of this type

    36
    Among the given ligands, the negative ligand is

    Tap an option to check your answer.

  5. Question 5

    Solid State. This type asked 7 times: 2 May 2023 S1, 3 May 2023 S2, 9 May 2023 S1, 10 May 2023 S1, 13 May 2024 S2, 14 May 2024 S1, 11 Apr 2026 S1. This one: 11 Apr 2026 S1 See all 7 of this type

    17
    In a cubic unit cell of an ionic compound, the eight corners are occupied by anions and cations at the center of the cube. Calculate the volume of the unit cell if density of the unit cell is 4 g cm−34\ \mathrm{g\,cm^{-3}}. [Molar mass of compound =168.6 g mol−1= 168.6\ \mathrm{g\,mol^{-1}} and NA=6.022×1023N_A = 6.022 \times 10^{23}]

    Tap an option to check your answer.