Day 138: MHT-CET Maths

1. A.
   $\dfrac{1}{95}\begin{bmatrix} 7 & 3 \\ 3 & 4 \end{bmatrix}$
2. B.
   $\dfrac{1}{95}\begin{bmatrix} -7 & 3 \\ 3 & -4 \end{bmatrix}$
3. C.
   $\dfrac{1}{95}\begin{bmatrix} -7 & -3 \\ 3 & 4 \end{bmatrix}$
4. D.
   $\dfrac{1}{95}\begin{bmatrix} 4 & 3 \\ 3 & 7 \end{bmatrix}$

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1. A.
   $6R=t+2$
2. B.
   $R(t+2)=6$
3. C.
   $R=6(t+2)$
4. D.
   $6R=t$

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1. A.
   $\frac{y}{x}$
2. B.
   $-\frac{y}{x}$
3. C.
   $\frac{x}{y}$
4. D.
   $-\frac{x}{y}$

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1. A.
   $7:3$
2. B.
   $4:6$
3. C.
   $6:4$
4. D.
   $3:7$

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1. A.
   $\hat{u}=\frac{\hat{a}+\hat{b}}{|\hat{a}+\hat{b}|}$ and $M=(1+\hat{a}\cdot\hat{b})^{1/2}$
2. B.
   $\hat{u}=\frac{\hat{a}-\hat{b}}{|\hat{a}-\hat{b}|}$ and $M=(1+\hat{a}\cdot\hat{b})^{1/2}$
3. C.
   $\hat{u}=\frac{\hat{a}+\hat{b}}{|\hat{a}+\hat{b}|}$ and $M=(1+2\hat{a}\cdot\hat{b})^{1/2}$
4. D.
   $\hat{u}=\frac{\hat{a}-\hat{b}}{|\hat{a}-\hat{b}|}$ and $M=(1+2\hat{a}\cdot\hat{b})^{1/2}$

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