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Day 70: SSC CGL Tier II Quant

5 questions. Try each one first, then open its answer.

  1. Question 1

    Surds, Indices and Simplification. Asked once: 29 Jan 2022 Tier II (same type asked 4 times) See all 4 of this type

    17
    The value of (113÷267 of 535)×(625÷412 of 513)÷(34×223÷59 of 115)=k\left(1\frac{1}{3} \div 2\frac{6}{7} \text{ of } 5\frac{3}{5}\right) \times \left(6\frac{2}{5} \div 4\frac{1}{2} \text{ of } 5\frac{1}{3}\right) \div \left(\frac{3}{4} \times 2\frac{2}{3} \div \frac{5}{9} \text{ of } 1\frac{1}{5}\right) = k, where k lies between:

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  2. Question 2

    Trigonometric Ratios and Identities. Asked once: 29 Jan 2022 Tier II (same type asked 4 times) See all 4 of this type

    68
    Let 0∘<θ<90∘0^\circ < \theta < 90^\circ. (1+cot⁡2θ)(1+tan⁡2θ)×(sin⁡θ−cosec θ)(cos⁡θ−sec⁡θ)(1 + \cot^2\theta)(1 + \tan^2\theta) \times (\sin\theta - \text{cosec}\,\theta)(\cos\theta - \sec\theta) is equal to:

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  3. Question 3

    Trigonometric Ratios and Identities. Asked once: 15 Nov 2020 Tier II (same type asked 3 times) See all 3 of this type

    6
    The value of sec⁡2θ(2+tan⁡2θ+cot⁡2θ)÷(sin⁡2θ−tan⁡2θ)(cosec2θ+sec⁡2θ)(1+cot⁡2θ)2\frac{\sec^2\theta(2+\tan^2\theta+\cot^2\theta)\div(\sin^2\theta-\tan^2\theta)}{(\text{cosec}^2\theta+\sec^2\theta)(1+\cot^2\theta)^2} is:

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  4. Question 4

    Mensuration 3D. Asked once: 3 Feb 2022 Tier II (same type asked 3 times) See all 3 of this type

    29
    The circumference of the base of a cylindrical vessel is 264 cm and its height is 50 cm. The capacity (in litres) of the vessel is: (Take π=227\pi = \frac{22}{7})

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  5. Question 5

    Algebraic Identities and Simplification. Asked once: 15 Nov 2020 Tier II (same type asked 6 times) See all 6 of this type

    76
    Given that x8−34x4+1=0x^8 - 34x^4 + 1 = 0, x>0x > 0. What is the value of (x3+x−3)(x^3 + x^{-3})?

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