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Day 71: SSC CGL Tier II Quant

5 questions. Try each one first, then open its answer.

  1. Question 1

    Simple and Compound Interest. Asked once: 15 Nov 2020 Tier II (same type asked 6 times) See all 6 of this type

    44
    A certain sum amounts to ₹15,500 in 2 years at 12% p.a. simple interest. The same sum will amount to what in 1121\frac{1}{2} years at 10% p.a., if the interest is compounded half yearly (nearest to ₹1)?

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  2. Question 2

    Trigonometric Ratios and Identities. Asked once: 29 Jan 2022 Tier II (same type asked 6 times) See all 6 of this type

    94
    The value of 4tan⁡230∘+sin⁡230∘cos⁡245∘+sec⁡248∘−cot⁡242∘cos⁡37∘sin⁡53∘+sin⁡37∘cos⁡53∘+tan⁡18∘tan⁡72∘\frac{4\tan^2 30^\circ + \sin^2 30^\circ\cos^2 45^\circ + \sec^2 48^\circ - \cot^2 42^\circ}{\cos 37^\circ\sin 53^\circ + \sin 37^\circ\cos 53^\circ + \tan 18^\circ\tan 72^\circ} is:

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  3. Question 3

    Trigonometric Ratios and Identities. Asked once: 15 Nov 2020 Tier II (same type asked 5 times) See all 5 of this type

    49
    In Δ\Delta PQR, ∠Q=90∘\angle Q = 90^\circ. If cot R = 13\frac{1}{3}, then what is the value of sec⁡P(cos⁡R+sin⁡P)cosec R (sin⁡R−cosec P)\frac{\sec P(\cos R + \sin P)}{\text{cosec}\,R\,(\sin R - \text{cosec}\,P)}?

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  4. Question 4

    Surds, Indices and Simplification. Asked once: 29 Jan 2022 Tier II (same type asked 4 times) See all 4 of this type

    85
    Let x=534−37×1534+2235÷1112534÷514+535÷3415x = \frac{5\frac{3}{4} - \frac{3}{7} \times 15\frac{3}{4} + 2\frac{2}{35} \div 1\frac{11}{25}}{\frac{3}{4} \div 5\frac{1}{4} + 5\frac{3}{5} \div 3\frac{4}{15}}. When yy is added to xx, the result is 713\frac{7}{13}. What is the value of yy?

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  5. Question 5

    Trigonometric Ratios and Identities. Asked once: 15 Nov 2020 Tier II (same type asked 4 times) See all 4 of this type

    79
    cos⁡A(sec⁡A−cos⁡A)(cot⁡A+tan⁡A)=?\cos A(\sec A - \cos A)(\cot A + \tan A) = ?

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