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AFCAT Numerical Ability · Percentage

Percentage Change, and Comparing Two Quantities

Measure a change on the starting value, recover the value before a change, and compare two quantities by how much one is more or less than the other.

Why this matters

Three AFCAT past-year questions are on this page, from 2015 and 2018, and all three compare two quantities rather than track one. The marks go on the base: 'A is 60% more than B' and 'B is 60% less than A' are different statements, and the options always carry both readings.

Concept 1 of 5: Percentage change measured on the old value

A price that goes from ₹480 to ₹600 rises by ₹120. As a percentage it is 120 out of the ₹480 it started from, so 25%.

Definition

  • Percentage change =new−oldold×100= \dfrac{\text{new} - \text{old}}{\text{old}} \times 100. A negative answer is a decrease.
  • The old value is always the base, whether the change is a rise or a fall.
  • So a rise and the fall that undoes it have different percentages: 480 to 600 is +25%, and 600 back to 480 is −20%.
  • An improvement in rank from 60 to 51 is a fall of 9 on 60, which is 15%.

Percentage change

% change=new−oldold×100\%\text{ change} = \dfrac{\text{new} - \text{old}}{\text{old}} \times 100

Worked example

A price rises from ₹480 to ₹600. Find the percentage rise, and the percentage fall if it later goes back to ₹480.
Practice this conceptself-check · 3 quick reps

The same idea in a practice question:

Practice questionEasy

Example 1 · Percentage · Percentage Change and Comparison

A district falls from 2,50,0002,50,000 to 2,28,8002,28,800. What is the percentage decrease?

Divide by the starting value

From 40,000 to 37,400 is 2,600 on 40,000, which is 6.5%. Dividing by 37,400 gives about 6.95%, a common distractor.

Concept 2 of 5: The value before a percentage change

A 20% rise multiplies a number by 1.2. To get back the number before the rise, divide by 1.2. Taking 20% off the new number does not undo it.

Definition

  • After a rise of r%r\%: new == old ×(1+r100)\times \left(1 + \tfrac{r}{100}\right), so old == new ÷(1+r100)\div \left(1 + \tfrac{r}{100}\right).
  • After a fall of r%r\%: old == new ÷(1−r100)\div \left(1 - \tfrac{r}{100}\right).
  • Then answer what the question asks of the original: the number itself, or another percentage of it.
  • Given both 'up by x%x\% gives AA' and 'down by x%x\% gives BB': adding the two equations gives the number, N=A+B2N = \tfrac{A + B}{2}.

Undoing a change

old=new1±r100\text{old} = \dfrac{\text{new}}{1 \pm \tfrac{r}{100}}

Worked example

After a 20% rise, a salary is ₹27,000. What was it before the rise?
Practice this conceptself-check · 4 quick reps

The same idea in a practice question:

Practice questionEasy

Example 2 · Percentage · Percentage Change and Comparison

A number when increased by 1212% becomes 448448. What is 2525% of the original number?

Do not take the percentage off the new value

₹27,000 after a 20% rise came from ₹22,500. Taking 20% off ₹27,000 gives ₹21,600, which is wrong, because the 20% was of the old salary.

Concept 3 of 5: More than and less than: the base changes

If A is 60% more than B, take B as 100, so A is 160. B is 60 less than A, but as a share of A's 160 that is 37.5%, not 60%.

Definition

  • 'A is r%r\% more than B' uses B as the base. 'B is ?% less than A' uses A as the base.
  • If A is r%r\% more than B, then B is r100+r×100%\dfrac{r}{100 + r} \times 100\% less than A.
  • If A is r%r\% less than B, then B is r100−r×100%\dfrac{r}{100 - r} \times 100\% more than A.
  • The fastest check is to put the base at 100 and read the other number.

Swapping the base

more by r%  →  less by 100r100+r%,less by r%  →  more by 100r100−r%\text{more by } r\% \;\to\; \text{less by } \dfrac{100r}{100 + r}\%, \qquad \text{less by } r\% \;\to\; \text{more by } \dfrac{100r}{100 - r}\%

Worked example

A's income is 60% more than B's. By what percent is B's income less than A's?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

AFCAT · 2015 · AFCAT (II) 2015 — Numerical Ability · 03-211Easy

Example 3 · Percentage · Percentage Change and Comparison

AA's salary is 50% more than BB's. How much per cent is BB's salary less than AA's?

The two percentages are never equal

If A is 60% more than B, B is 37.5% less than A. The same gap is measured on a different base, so the percentages differ.

Concept 4 of 5: Two quantities measured against a third

When both numbers are described against a third one, set the third at 100. Both numbers then appear as plain values and can be compared directly.

Definition

  • 'Two numbers are 30% and 50% more than a third': with the third at 100 they are 130 and 150.
  • 'Less than a third by 35% and 61%' makes them 65 and 39.
  • A chain (A against B, B against C) works the same way: put the last one at 100 and walk back along the chain.
  • Then compare as in the last concept, on whichever base the question names.

Set the reference at 100

third=100  ⇒  first=100±a,second=100±b\text{third} = 100 \;\Rightarrow\; \text{first} = 100 \pm a, \quad \text{second} = 100 \pm b

Worked example

Two numbers are 30% and 50% more than a third number. What percent of the second number is the first?
Practice this conceptself-check · 3 quick reps

The same idea in a practice question:

Practice questionEasy

Example 4 · Percentage · Percentage Change and Comparison

The income of AA is 20% higher than that of BB. The income of BB is 25% less than that of CC. What per cent less is AA's income than CC's income?

Percentages along a chain multiply

30% less than 60% more is 0.7×1.6=1.120.7 \times 1.6 = 1.12, so 12% more. Subtracting the percentages gives 30%, which is wrong.

Concept 5 of 5: When x% of one equals y% of another

40% of A being equal to 25% of B means B must be the bigger number. The equation 0.4A=0.25B0.4A = 0.25B is a ratio in disguise: A:B=25:40A : B = 25 : 40.

Definition

  • x%x\% of A=y%A = y\% of BB gives A:B=y:xA : B = y : x (the percentages cross over).
  • B as a percentage of A is then xy×100\dfrac{x}{y} \times 100.
  • With a sum or a difference of A and B, split it in that ratio.
  • If the percentages are of sums and differences, a%a\% of (P+Q)=b%(P + Q) = b\% of (P−Q)(P - Q), expand and collect P and Q.

Equal percentages

x100A=y100B  ⇒  A:B=y:x\dfrac{x}{100}A = \dfrac{y}{100}B \;\Rightarrow\; A : B = y : x

Worked example

40% of A equals 25% of B. Find A : B, and B as a percentage of A.
Practice this conceptself-check · 3 quick reps

The same idea in a real exam question:

AFCAT · 2018 · AFCAT (II) 2018 — Numerical Ability · 03-206Moderate

Example 5 · Percentage · Percentage Change and Comparison

The difference of two numbers is 1660. If 6126\frac{1}{2}% of one number is 8128\frac{1}{2}% of the other number, the smaller number is

The ratio crosses over

40% of A = 25% of B gives A:B=25:40A : B = 25 : 40, not 40:2540 : 25. The number with the smaller percentage is the larger number.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (5)

  • Percentage change measured on the old value

    Percentage change

    % change=new−oldold×100\%\text{ change} = \dfrac{\text{new} - \text{old}}{\text{old}} \times 100
  • The value before a percentage change

    Undoing a change

    old=new1±r100\text{old} = \dfrac{\text{new}}{1 \pm \tfrac{r}{100}}
  • More than and less than: the base changes

    Swapping the base

    more by r%  →  less by 100r100+r%,less by r%  →  more by 100r100−r%\text{more by } r\% \;\to\; \text{less by } \dfrac{100r}{100 + r}\%, \qquad \text{less by } r\% \;\to\; \text{more by } \dfrac{100r}{100 - r}\%
  • Two quantities measured against a third

    Set the reference at 100

    third=100  ⇒  first=100±a,second=100±b\text{third} = 100 \;\Rightarrow\; \text{first} = 100 \pm a, \quad \text{second} = 100 \pm b
  • When x% of one equals y% of another

    Equal percentages

    x100A=y100B  ⇒  A:B=y:x\dfrac{x}{100}A = \dfrac{y}{100}B \;\Rightarrow\; A : B = y : x

Watch out for (5)

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