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IMAT Chemistry · Acids, Bases and pH

Weak Acids and Bases: Ka, pKa and Kb

A weak acid ionises only partly, so its strength is measured by an equilibrium constant, Ka, and its pH needs a square root rather than a straight logarithm.

Why this matters

The ministry papers asked for the pH of a weak acid from its Ka (2025) and for the weak diprotic acid among drawn structures (2023); an older paper asked which of three acids are weak. Kb and pKa have not been asked directly, but they are on the syllabus.

Concept 1 of 4: Common weak acids and bases, and how many protons they give

Most acids you meet, including all the organic acids, are weak: only a small fraction of their molecules give up a proton at any moment. Only hydrogen atoms bonded to a strongly electronegative atom, usually oxygen, are acidic. That is why ethanoic acid has four hydrogens but gives only one proton.

Definition

  • A weak acid ionises only partly; the equation uses ⇌\rightleftharpoons, and most molecules stay whole.
  • Monoprotic, diprotic and triprotic acids can give 1, 2 or 3 protons per molecule.
  • Only an H on O (or on another very electronegative atom) is acidic. The H atoms on carbon in CH3COOH\mathrm{CH_3COOH} are not.
  • A polyprotic acid gives its protons one at a time, each step weaker than the last, because a negative ion holds its next proton more tightly.
  • Ammonia and the amines are the common weak bases: they accept a proton with their nitrogen lone pair.
NameFormulaStrengthAcidic protons
Ethanoic (acetic) acidCH3COOH\mathrm{CH_3COOH}Weak acid1 (only the COOH hydrogen)
Methanoic (formic) acidHCOOH\mathrm{HCOOH}Weak acid1
Carbonic acidH2CO3\mathrm{H_2CO_3}Weak acid2
Ethanedioic (oxalic) acidHOOC−COOH\mathrm{HOOC{-}COOH}Weak acid2 (one per COOH group)
Phosphoric acidH3PO4\mathrm{H_3PO_4}Weak acid3
Hydrofluoric acidHF\mathrm{HF}Weak acid1
AmmoniaNH3\mathrm{NH_3}Weak baseAccepts 1 to form NH4+\mathrm{NH_4^+}
Compare: sulfuric acid is a STRONG diprotic acid. An alcohol OH (ethanol, ethane-1,2-diol) is far too weak to count as an acid in water.
Practice this conceptself-check · 3 quick reps

Counting every H atom gives the wrong number of protons

Ethanoic acid, CH3COOH\mathrm{CH_3COOH}, has four hydrogen atoms but only one is acidic: the one on the oxygen of the COOH group. A molecule with two COOH groups is diprotic. A compound with OH groups only on carbon chains (an alcohol or a diol) is not an acid in water at all.

Concept 2 of 4: Ka and pKa: measuring the strength of a weak acid

A weak acid sets up an equilibrium between whole molecules and ions. The equilibrium constant, Ka, says how far the acid has gone towards ions. A bigger Ka means more ionisation and a stronger acid. Because Ka values are tiny powers of ten, chemists use pKa, which works like pH: a smaller pKa means a stronger acid.

Definition

  • For HA⇌H++A−\mathrm{HA \rightleftharpoons H^+ + A^-}, the acid dissociation constant is Ka=[H+][A−]/[HA]K_a = [\mathrm{H^+}][\mathrm{A^-}]/[\mathrm{HA}].
  • pKa=−log⁡Ka\text{p}K_a = -\log K_a. Larger Ka, smaller pKa, stronger acid.
  • Ka depends on temperature only, not on concentration.
  • Rough values at 25 °C: ethanoic acid Ka≈1.8×10−5K_a \approx 1.8 \times 10^{-5} (pKa about 4.7); methanoic acid about 1.8×10−41.8 \times 10^{-4} (pKa about 3.7); the ammonium ion about 5.6×10−105.6 \times 10^{-10} (pKa about 9.3).

Acid dissociation constant

Ka=[H+][A−][HA]pKa=−log⁡10KaK_a = \frac{[\mathrm{H^+}][\mathrm{A^-}]}{[\mathrm{HA}]} \qquad \text{p}K_a = -\log_{10} K_a
  • [HA][\mathrm{HA}]concentration of the un-ionised acid at equilibrium
  • [A−][\mathrm{A^-}]concentration of the conjugate base at equilibrium

Worked example

Three acids are described as: X has pKa 3.2, Y has Ka=1.0×10−5K_a = 1.0 \times 10^{-5}, Z has pKa 6.4. Put them in order from strongest to weakest.
Practice this conceptself-check · 3 quick reps

A larger pKa is a weaker acid

pKa runs the opposite way to Ka, just as pH runs the opposite way to [H+][\mathrm{H^+}]. The acid with the biggest Ka, or the smallest pKa, is the strongest. When options mix Ka and pKa values, convert them all to one form before comparing.

Concept 3 of 4: pH of a weak acid solution

A weak acid releases only a little H+\mathrm{H^+}, so the amount ionised is small next to the amount dissolved. Each ionised molecule gives one H+\mathrm{H^+} and one A−\mathrm{A^-}, so Ka≈[H+]2/cK_a \approx [\mathrm{H^+}]^2 / c. That gives [H+][\mathrm{H^+}] as a square root, and in pH terms it means halving.

Definition

  • Assume [H+]=[A−][\mathrm{H^+}] = [\mathrm{A^-}] and that [HA][\mathrm{HA}] stays about equal to the starting concentration cc.
  • Then [H+]≈Ka c[\mathrm{H^+}] \approx \sqrt{K_a\,c}, or pH≈12(pKa−log⁡c)\text{pH} \approx \tfrac{1}{2}(\text{p}K_a - \log c).
  • The approximation works when the acid is only a few per cent ionised, which is true for typical IMAT numbers.
  • Degree of ionisation: [H+]/c[\mathrm{H^+}]/c. It rises as the acid is diluted.
  • Diluting a weak acid 100 times raises its pH by only 1, not 2, because of the square root.

Weak acid

[H+]≈Ka cpH≈12(pKa−log⁡10c)[\mathrm{H^+}] \approx \sqrt{K_a\,c} \qquad \text{pH} \approx \tfrac{1}{2}\left(\text{p}K_a - \log_{10} c\right)
  • KaK_aacid dissociation constant
  • ccconcentration of acid dissolved, in mol/L

Worked example

Find the pH of a 0.040 mol/L solution of a weak acid with Ka=4.0×10−6K_a = 4.0 \times 10^{-6}. Take log⁡4=0.60\log 4 = 0.60.
Practice this conceptself-check · 3 quick reps

A weak acid's pH is not minus log of its concentration

−log⁡c-\log c gives the pH only for a strong acid. For a weak acid of the same concentration the pH is higher, because only a small fraction ionises. Treating a weak acid as strong is the most common wrong option in these questions.

Concept 4 of 4: Weak bases, Kb, and Ka × Kb = Kw for a conjugate pair

A weak base pulls a proton off water and leaves OH−\mathrm{OH^-} behind, setting up its own equilibrium with its own constant, Kb. An acid and its conjugate base are linked: if the acid holds its proton loosely, the conjugate base has little pull on protons. Multiplying their constants gives Kw exactly.

Definition

  • For B+H2O⇌BH++OH−\mathrm{B + H_2O \rightleftharpoons BH^+ + OH^-}: Kb=[BH+][OH−]/[B]K_b = [\mathrm{BH^+}][\mathrm{OH^-}]/[\mathrm{B}], and pKb=−log⁡Kb\text{p}K_b = -\log K_b.
  • For a weak base, [OH−]≈Kb c[\mathrm{OH^-}] \approx \sqrt{K_b\,c}; then find pOH and pH.
  • For a conjugate pair: Ka×Kb=KwK_a \times K_b = K_w, so pKa+pKb=14\text{p}K_a + \text{p}K_b = 14 at 25 °C.
  • The stronger the acid, the weaker its conjugate base. The conjugate base of a strong acid (Cl−\mathrm{Cl^-}, NO3−\mathrm{NO_3^-}) has no measurable basic strength in water.

Conjugate pair at 25 °C

Ka×Kb=Kw=1.0×10−14pKa+pKb=14K_a \times K_b = K_w = 1.0 \times 10^{-14} \qquad \text{p}K_a + \text{p}K_b = 14
  • KaK_aconstant for the acid of the pair
  • KbK_bconstant for its conjugate base

Worked example

A weak base has Kb=1.0×10−4K_b = 1.0 \times 10^{-4}. Find the pH of its 0.010 mol/L solution at 25 °C, and the Ka of its conjugate acid.
Practice this conceptself-check · 3 quick reps

A strong acid has a weak conjugate base

Strength runs in opposite directions within a pair. A strong acid such as HCl has a conjugate base (Cl−\mathrm{Cl^-}) too weak to take protons from water. A very weak acid such as HCN has a fairly strong conjugate base. An option saying a strong acid has a strong conjugate base is wrong.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (3)

  • Ka and pKa: measuring the strength of a weak acid

    Acid dissociation constant

    Ka=[H+][A−][HA]pKa=−log⁡10KaK_a = \frac{[\mathrm{H^+}][\mathrm{A^-}]}{[\mathrm{HA}]} \qquad \text{p}K_a = -\log_{10} K_a
  • pH of a weak acid solution

    Weak acid

    [H+]≈Ka cpH≈12(pKa−log⁡10c)[\mathrm{H^+}] \approx \sqrt{K_a\,c} \qquad \text{pH} \approx \tfrac{1}{2}\left(\text{p}K_a - \log_{10} c\right)
  • Weak bases, Kb, and Ka × Kb = Kw for a conjugate pair

    Conjugate pair at 25 °C

    Ka×Kb=Kw=1.0×10−14pKa+pKb=14K_a \times K_b = K_w = 1.0 \times 10^{-14} \qquad \text{p}K_a + \text{p}K_b = 14

Reference tables (1)

Common weak acids and bases, and how many protons they give7 rows
NameFormulaStrengthAcidic protons
Ethanoic (acetic) acidCH3COOH\mathrm{CH_3COOH}Weak acid1 (only the COOH hydrogen)
Methanoic (formic) acidHCOOH\mathrm{HCOOH}Weak acid1
Carbonic acidH2CO3\mathrm{H_2CO_3}Weak acid2
Ethanedioic (oxalic) acidHOOC−COOH\mathrm{HOOC{-}COOH}Weak acid2 (one per COOH group)
Phosphoric acidH3PO4\mathrm{H_3PO_4}Weak acid3
Hydrofluoric acidHF\mathrm{HF}Weak acid1
AmmoniaNH3\mathrm{NH_3}Weak baseAccepts 1 to form NH4+\mathrm{NH_4^+}
Compare: sulfuric acid is a STRONG diprotic acid. An alcohol OH (ethanol, ethane-1,2-diol) is far too weak to count as an acid in water.

Watch out for (4)

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