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IMAT Chemistry · Equilibrium, Kinetics and Energetics

Le Chatelier's Principle: Concentration, Pressure, Temperature and Catalysts

When the conditions of an equilibrium are changed, its position shifts to oppose the change; only a change in temperature alters the value of K.

Why this matters

This is the most asked page of the chapter. The 2015, 2016, 2020, 2022, 2023 and 2025 papers asked which way an equilibrium moves when a substance is added or removed or the temperature changes, and how temperature changes Kc, usually as a which of these statements question with a catalyst among the distractors.

Concept 1 of 4: Changing a concentration shifts the equilibrium to oppose it

An equilibrium behaves as if it resists being pushed. Add more of a substance and the reaction that uses it up speeds up until a new balance is reached; take a substance away and the reaction that makes it takes over. Kc itself does not change: the concentrations rearrange until the ratio is back to the same value.

Definition

Le Chatelier's principle: if a system at equilibrium is disturbed, the position of equilibrium shifts in the direction that opposes the change.

  • Adding a reactant, or removing a product, shifts the equilibrium to the right.
  • Adding a product, or removing a reactant, shifts it to the left.
  • A species can be removed indirectly by adding something that reacts with it: an acid removes OH−\mathrm{OH^-}, an alkali removes H+\mathrm{H^+}.
  • Adding or removing a pure solid or liquid has no effect, since it is not in Kc.
  • A concentration change does not change Kc.
ChangeShiftReason
Add a reactantTo the rightThe forward reaction uses up the extra reactant
Remove a productTo the rightThe forward reaction replaces it
Add a productTo the leftThe reverse reaction uses up the extra product
Add a substance that reacts with a productTo the rightThat product is being removed
Add more of a pure solidNo shiftA solid is not in Kc
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Adding a solid does not shift an equilibrium

In an equilibrium with a solid on one side, adding or removing some of that solid changes nothing, because a solid does not appear in Kc. Only the gases and dissolved species can be used to push the equilibrium.

A reagent that removes a product shifts the equilibrium right

You do not have to add a reactant to drive an equilibrium forward. Adding a substance that reacts with one of the products (an alkali removing H+\mathrm{H^+}, for example) also shifts it to the right. Adding a substance that supplies a product shifts it to the left.

Concept 2 of 4: Changing the pressure: count the moles of gas

Gas pressure comes from the number of gas molecules. If you squeeze an equilibrium mixture, it can partly undo the squeeze by turning into fewer molecules. If you lower the pressure, it makes more molecules. When both sides have the same number of gas moles, pressure has nothing to work with.

Definition

  • Increasing the pressure (by compressing) shifts the equilibrium towards the side with fewer moles of gas. Decreasing it shifts towards more moles of gas.
  • Count only gases; ignore solids, liquids and dissolved species.
  • Equal moles of gas on both sides: no shift.
  • Adding an unreactive gas at constant volume changes no partial pressures: no shift.
  • A pressure change does not change Kc. It also speeds up a gas reaction, so equilibrium is reached sooner.
EquilibriumMoles of gas, left : rightHigher pressure shifts
N2+3H2⇌2NH3\mathrm{N_2 + 3H_2 \rightleftharpoons 2NH_3}4 : 2To the right
N2O4⇌2NO2\mathrm{N_2O_4 \rightleftharpoons 2NO_2}1 : 2To the left
H2+I2⇌2HI\mathrm{H_2 + I_2 \rightleftharpoons 2HI}2 : 2No shift
CaCO3(s)⇌CaO(s)+CO2(g)\mathrm{CaCO_3(s) \rightleftharpoons CaO(s) + CO_2(g)}0 : 1To the left
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Count gas moles only

In an equilibrium with solids or liquids, only the gases decide the effect of pressure. For C(s)+CO2(g)⇌2CO(g)\mathrm{C(s) + CO_2(g) \rightleftharpoons 2CO(g)} the count is 1 : 2, not 2 : 2.

Concept 3 of 4: Changing the temperature: the only change that alters K

Treat heat as if it were a reactant or a product. In an exothermic reaction heat is a product, so heating the mixture is like adding product: the equilibrium shifts left. Cooling removes heat and shifts it right. Because this changes the ratio of products to reactants at the new temperature, K itself changes.

Definition

  • Raising the temperature shifts the equilibrium in the endothermic direction; lowering it shifts it in the exothermic direction.
  • Forward reaction exothermic (ΔH<0\Delta H < 0): heating decreases K; cooling increases K.
  • Forward reaction endothermic (ΔH>0\Delta H > 0): heating increases K.
  • Temperature is the only factor that changes K. Concentration, pressure and catalysts leave it unchanged.
  • Example: the self-ionisation of water, H2O⇌H++OH−\mathrm{H_2O \rightleftharpoons H^+ + OH^-}, is endothermic. On heating, KwK_w rises (about 5.5×10−145.5 \times 10^{-14} at 50 °C) and the pH of pure water falls to about 6.6, but the water stays neutral because [H+]=[OH−][\mathrm{H^+}] = [\mathrm{OH^-}].
Forward reactionRaise the temperatureLower the temperature
Exothermic (ΔH negative)Shifts left; K decreasesShifts right; K increases
Endothermic (ΔH positive)Shifts right; K increasesShifts left; K decreases
Self-ionisation of water (endothermic)Kw increases; pH falls below 7; still neutralKw decreases; pH rises above 7; still neutral
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Heating an exothermic equilibrium lowers K

For an exothermic forward reaction, raising the temperature shifts the equilibrium left and decreases K; lowering the temperature increases K. Options pairing an exothermic reaction with a K that rises on heating are wrong.

Pure water is neutral at every temperature

Neutral means [H+]=[OH−][\mathrm{H^+}] = [\mathrm{OH^-}], not pH 7. Hot pure water has a pH below 7 because more of it ionises, but the two ion concentrations stay equal, so it is still neutral.

Concept 4 of 4: Putting the factors together: the compromise in ammonia synthesis

Industry wants both a high yield and a fast rate, and for an exothermic reaction these pull in opposite directions: low temperature favours the yield but makes the reaction slow. The conditions chosen are a compromise, with a catalyst added to win back speed without touching the yield.

Definition

The Haber process: N2(g)+3H2(g)⇌2NH3(g)\mathrm{N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)}, ΔH=−92 kJ/mol\Delta H = -92\ \text{kJ/mol}.

  • High pressure (about 200 atm) favours the side with fewer gas moles and raises the rate; higher still would cost too much in equipment and safety.
  • Moderate temperature (about 450 °C): lower would give a higher yield but too slow a rate.
  • Iron catalyst: faster, with no change in yield.
  • Ammonia is condensed and removed, and unreacted gases are recycled.

The Contact process (2SO2+O2⇌2SO3\mathrm{2SO_2 + O_2 \rightleftharpoons 2SO_3}, exothermic) uses the same reasoning with a vanadium(V) oxide catalyst at about 450 °C and low pressure, because the conversion is already high.

ConditionEffect on equilibrium yieldEffect on rateChoice in the Haber process
Higher pressureIncreasesIncreasesAbout 200 atm
Lower temperatureIncreasesDecreasesA compromise near 450 °C
CatalystNo effectIncreasesIron
Removing ammoniaIncreases the conversionKeeps the forward reaction goingAmmonia condensed out
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Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Reference tables (4)

Changing a concentration shifts the equilibrium to oppose it5 rows
ChangeShiftReason
Add a reactantTo the rightThe forward reaction uses up the extra reactant
Remove a productTo the rightThe forward reaction replaces it
Add a productTo the leftThe reverse reaction uses up the extra product
Add a substance that reacts with a productTo the rightThat product is being removed
Add more of a pure solidNo shiftA solid is not in Kc
Changing the pressure: count the moles of gas4 rows
EquilibriumMoles of gas, left : rightHigher pressure shifts
N2+3H2⇌2NH3\mathrm{N_2 + 3H_2 \rightleftharpoons 2NH_3}4 : 2To the right
N2O4⇌2NO2\mathrm{N_2O_4 \rightleftharpoons 2NO_2}1 : 2To the left
H2+I2⇌2HI\mathrm{H_2 + I_2 \rightleftharpoons 2HI}2 : 2No shift
CaCO3(s)⇌CaO(s)+CO2(g)\mathrm{CaCO_3(s) \rightleftharpoons CaO(s) + CO_2(g)}0 : 1To the left
Changing the temperature: the only change that alters K3 rows
Forward reactionRaise the temperatureLower the temperature
Exothermic (ΔH negative)Shifts left; K decreasesShifts right; K increases
Endothermic (ΔH positive)Shifts right; K increasesShifts left; K decreases
Self-ionisation of water (endothermic)Kw increases; pH falls below 7; still neutralKw decreases; pH rises above 7; still neutral
Putting the factors together: the compromise in ammonia synthesis4 rows
ConditionEffect on equilibrium yieldEffect on rateChoice in the Haber process
Higher pressureIncreasesIncreasesAbout 200 atm
Lower temperatureIncreasesDecreasesA compromise near 450 °C
CatalystNo effectIncreasesIron
Removing ammoniaIncreases the conversionKeeps the forward reaction goingAmmonia condensed out

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