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JEE Mains Chemistry · Amines

Carbylamine and Hinsberg Tests

The carbylamine test picks out primary amines by the smell of an isocyanide, and Hinsberg's reagent sorts primary, secondary and tertiary amines by whether a sulphonamide forms and dissolves in alkali.

Why this matters

Twenty-one PYQs, three numerical, four from 2026. Five test the carbylamine reaction and the isocyanide it gives; eleven test Hinsberg's reagent, often by counting how many amines in a list react or give an alkali-soluble product; five combine several tests to identify an amine from its formula.

Concept 1 of 3: Carbylamine (isocyanide) test for primary amines

Chloroform and alcoholic KOH make dichlorocarbene, which attacks the amine nitrogen. Only a nitrogen with two hydrogens can lose both and end up as R–N≡C, an isocyanide with a very unpleasant smell. Secondary and tertiary amines cannot, so the smell marks a primary amine.

Definition

  • Heat the amine with CHCl3\mathrm{CHCl_3} and alcoholic KOH. A foul smell means a primary amine.
  • Works for primary aliphatic and primary aromatic amines alike. Secondary and tertiary amines give no isocyanide.
  • The isocyanide can be hydrolysed back by dilute acid: RNC+2H2O→H+RNH2+HCOOH\mathrm{RNC + 2H_2O \xrightarrow{H^+} RNH_2 + HCOOH}.
  • Isocyanides also form from alkyl halides and AgCN (covalent: nitrogen attacks), while KCN (ionic: carbon attacks) gives nitriles.
  • The test distinguishes ethylamine from diethylamine; it does not tell aliphatic from aromatic primary amines.

Carbylamine reaction

RNH2+CHCl3+3KOH→ΔR−N≡C+3KCl+3H2O\mathrm{RNH_2 + CHCl_3 + 3KOH \xrightarrow{\Delta} R{-}N{\equiv}C + 3KCl + 3H_2O}

Worked example

Which of these give the carbylamine test: 4-methylaniline, N-methylaniline, cyclohexylamine and triethylamine?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2021 · Paper 11 · Q37Moderate

Example 1 · Amines · Carbylamine and Hinsberg Tests

Organic compound A with CHCl3/KOHCHCl_{3}/KOH gives product BB which can be decomposed by H+/H2OH^{+}/H_{2}O ?

The carbylamine test covers aromatic amines too

Aniline gives phenyl isocyanide just as ethanamine gives ethyl isocyanide. The test separates primary from secondary and tertiary amines, not aliphatic from aromatic.

Isocyanide from a halide needs AgCN

KCN with an alkyl halide gives a nitrile, R–C≡N. AgCN gives the isocyanide, R–N≡C. An aryl halide gives neither under ordinary conditions.

Concept 2 of 3: Hinsberg test: benzenesulphonyl chloride with primary, secondary and tertiary amines

Benzenesulphonyl chloride reacts with any amine that still has an N–H, giving a sulphonamide. What happens next depends on whether an N–H is left. The sulphonyl group makes a remaining N–H acidic, so a primary amine's sulphonamide dissolves in alkali. A secondary amine's sulphonamide has no N–H and stays as a solid. A tertiary amine does not react at all.

Definition

  • Hinsberg's reagent is benzenesulphonyl chloride, C6H5SO2Cl\mathrm{C_6H_5SO_2Cl}; p-toluenesulphonyl chloride works the same way.
  • Primary: RNH2→C6H5SO2NHR\mathrm{RNH_2 \to C_6H_5SO_2NHR}, soluble in KOH or NaOH because the N–H is acidic.
  • Secondary: R2NH→C6H5SO2NR2\mathrm{R_2NH \to C_6H_5SO_2NR_2}, a solid insoluble in alkali.
  • Tertiary: no reaction; no N–H to replace.
  • The same rules hold for aryl amines: aniline, N-methylaniline and diphenylamine all react; N,N-dimethylaniline and triphenylamine do not.
  • The test is used both to tell the three classes apart and to separate a mixture of them.
Amine classExampleProduct with the reagentBehaviour in alkali
Primary aliphaticC2H5NH2\mathrm{C_2H_5NH_2}C6H5SO2NHC2H5\mathrm{C_6H_5SO_2NHC_2H_5}Dissolves: the N–H is acidic
Primary aromaticC6H5NH2\mathrm{C_6H_5NH_2}C6H5SO2NHC6H5\mathrm{C_6H_5SO_2NHC_6H_5}Dissolves: the N–H is acidic
Secondary aliphatic(C2H5)2NH\mathrm{(C_2H_5)_2NH}C6H5SO2N(C2H5)2\mathrm{C_6H_5SO_2N(C_2H_5)_2}Insoluble solid: no N–H left
Secondary aromaticC6H5NHCH3\mathrm{C_6H_5NHCH_3}C6H5SO2N(CH3)C6H5\mathrm{C_6H_5SO_2N(CH_3)C_6H_5}Insoluble solid: no N–H left
Tertiary(C2H5)3N\mathrm{(C_2H_5)_3N} or C6H5N(CH3)2\mathrm{C_6H_5N(CH_3)_2}No reactionThe amine is unchanged
Reacts and dissolves: primary. Reacts and stays solid: secondary. No reaction: tertiary.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2022 · 26 June 2022 · Q137Moderate

Example 2 · Amines · Carbylamine and Hinsberg Tests

Which statement is NOT correct for p-toluenesulphonyl chloride?

A secondary amine's product does not dissolve in alkali

The sulphonamide from a secondary amine has no hydrogen on nitrogen, so alkali has nothing to remove. It stays as an insoluble solid. Only a primary amine's product dissolves.

A clear solution means a primary amine

When a primary amine reacts with the reagent in alkali, the sulphonamide dissolves as its salt and the solution stays clear. A precipitate means a secondary amine; an unchanged amine means a tertiary one.

Concept 3 of 3: Identifying an amine from its test results

Most identification questions give a formula and three or four observations. Each observation removes a class: the carbylamine smell means primary, an alkali-soluble Hinsberg product means primary, nitrogen gas with nitrous acid means primary aliphatic, and a coloured dye after diazotisation means primary aromatic. Read every clue against the table before drawing structures.

Definition

  • Every amine dissolves in dilute mineral acid as its salt; this confirms a base but not its class.
  • A primary aliphatic amine gives N2\mathrm{N_2} with nitrous acid in the cold; a primary aromatic amine gives a diazonium salt that couples with β-naphthol to an orange-red dye.
  • A secondary amine with nitrous acid gives an N-nitrosamine, a yellow oil.
  • A tertiary aromatic amine such as N,N-dimethylaniline is nitrosated on the ring, para to nitrogen.
  • Optical activity points to a stereocentre: among C4H11N\mathrm{C_4H_{11}N} primary amines only butan-2-amine is chiral.
TestPrimary aliphaticPrimary aromaticSecondaryTertiary
CHCl3\mathrm{CHCl_3} + alcoholic KOH, heatFoul-smelling isocyanideFoul-smelling isocyanideNo isocyanideNo isocyanide
Hinsberg's reagent, then alkaliSulphonamide, dissolvesSulphonamide, dissolvesSulphonamide, insoluble solidNo reaction
NaNO2\mathrm{NaNO_2} + HCl, coldN2\mathrm{N_2} gas and an alcoholDiazonium salt, no gas at 273–278 KN-Nitrosamine, yellow oilAliphatic: soluble salt; aromatic: p-nitroso compound
Diazotise, then β-naphthol in NaOHNo dyeOrange-red azo dyeNo dyeNo dye
Dilute HClDissolves as a saltDissolves as a saltDissolves as a saltDissolves as a salt
The dye test is the one that separates primary aromatic from primary aliphatic amines.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2026 · 23 Jan 2026 Shift 2 · Q45Moderate

Example 3 · Amines · Carbylamine and Hinsberg Tests

A student has been given a compound " x " of molecular formula C6H7NC_{6}H_{7}N. ' x ' is sparingly soluble in water. However, on addition of dilute mineral acid , ' x ' becomes soluble in water. ' x ' when treated with CHCl3CHCl_{3} and KOH (alc.) ' y ' is produced. ' y ' has a specific unpleasant smell. On treatment with benzenesulphonyl chloride, ' x ' gives a compound ' z ' which is soluble in alkali. The number of different "H" atoms present in ' zz ' is:-

Dissolving in acid does not identify the class

Primary, secondary and tertiary amines all dissolve in dilute mineral acid as salts. Solubility in acid shows only that the compound is a base.

Benzylamine behaves as an aliphatic amine in the tests

Benzylamine gives the carbylamine test and an alkali-soluble Hinsberg product, but with nitrous acid it gives nitrogen gas and benzyl alcohol, not a stable diazonium salt, so it gives no azo dye.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (1)

Reference tables (2)

Hinsberg test: benzenesulphonyl chloride with primary, secondary and tertiary amines5 rows
Amine classExampleProduct with the reagentBehaviour in alkali
Primary aliphaticC2H5NH2\mathrm{C_2H_5NH_2}C6H5SO2NHC2H5\mathrm{C_6H_5SO_2NHC_2H_5}Dissolves: the N–H is acidic
Primary aromaticC6H5NH2\mathrm{C_6H_5NH_2}C6H5SO2NHC6H5\mathrm{C_6H_5SO_2NHC_6H_5}Dissolves: the N–H is acidic
Secondary aliphatic(C2H5)2NH\mathrm{(C_2H_5)_2NH}C6H5SO2N(C2H5)2\mathrm{C_6H_5SO_2N(C_2H_5)_2}Insoluble solid: no N–H left
Secondary aromaticC6H5NHCH3\mathrm{C_6H_5NHCH_3}C6H5SO2N(CH3)C6H5\mathrm{C_6H_5SO_2N(CH_3)C_6H_5}Insoluble solid: no N–H left
Tertiary(C2H5)3N\mathrm{(C_2H_5)_3N} or C6H5N(CH3)2\mathrm{C_6H_5N(CH_3)_2}No reactionThe amine is unchanged
Reacts and dissolves: primary. Reacts and stays solid: secondary. No reaction: tertiary.
Identifying an amine from its test results5 rows
TestPrimary aliphaticPrimary aromaticSecondaryTertiary
CHCl3\mathrm{CHCl_3} + alcoholic KOH, heatFoul-smelling isocyanideFoul-smelling isocyanideNo isocyanideNo isocyanide
Hinsberg's reagent, then alkaliSulphonamide, dissolvesSulphonamide, dissolvesSulphonamide, insoluble solidNo reaction
NaNO2\mathrm{NaNO_2} + HCl, coldN2\mathrm{N_2} gas and an alcoholDiazonium salt, no gas at 273–278 KN-Nitrosamine, yellow oilAliphatic: soluble salt; aromatic: p-nitroso compound
Diazotise, then β-naphthol in NaOHNo dyeOrange-red azo dyeNo dyeNo dye
Dilute HClDissolves as a saltDissolves as a saltDissolves as a saltDissolves as a salt
The dye test is the one that separates primary aromatic from primary aliphatic amines.

Watch out for (6)

Test yourself on Amines

20 past JEE Mains questions from this chapter, timed at 48 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.