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JEE Mains Chemistry · Chemical Bonding and Molecular Structure

Shapes of Molecules and Ions

The shape of a molecule is named from its atoms only: fix the arrangement from the total electron pairs, then remove the lone pairs, so AX₃E is pyramidal and AX₂E₂ is bent.

Why this matters

Twenty-seven PYQs, nineteen of them multiple choice, and four from 2026. Seventeen match molecules and ions to their shapes or ask which species share a shape; ten count how many species in a list are linear, bent, pyramidal, square planar or some other shape. Two ideas cover the page.

Concept 1 of 2: Shapes from the AXE formula

Write the central atom as A, its bonded atoms as X and its lone pairs as E. The total X + E fixes how the pairs are arranged in space. The shape you name is what the atoms alone trace out, so the same arrangement gives different shapes as lone pairs replace atoms.

Definition

  • Find X (atoms bonded to the centre) and E (lone pairs on it); a double bond still counts as one X.
  • X + E = 2, 3, 4, 5, 6 gives a linear, trigonal planar, tetrahedral, trigonal bipyramidal or octahedral arrangement of pairs.
  • Isostructural species share a shape, whatever their formulas: SO42−\mathrm{SO_4^{2-}} and CrO42−\mathrm{CrO_4^{2-}} (tetrahedral); SiCl4\mathrm{SiCl_4} and TiCl4\mathrm{TiCl_4}; SF4\mathrm{SF_4}, IF4+\mathrm{IF_4^+} and XeO2F2\mathrm{XeO_2F_2} (see-saw).
  • CH4\mathrm{CH_4}, NH4+\mathrm{NH_4^+} and BH4−\mathrm{BH_4^-} are isoelectronic (10 electrons) and all tetrahedral.
  • Four-coordinate complexes: [PtCl4]2−\mathrm{[PtCl_4]^{2-}}, [Ni(CN)4]2−\mathrm{[Ni(CN)_4]^{2-}} and [Cu(NH3)4]2+\mathrm{[Cu(NH_3)_4]^{2+}} are square planar; [NiCl4]2−\mathrm{[NiCl_4]^{2-}}, [FeCl4]2−\mathrm{[FeCl_4]^{2-}} and Ni(CO)4\mathrm{Ni(CO)_4} are tetrahedral.
  • Aluminium dissolves in NaOH as the tetrahedral [Al(OH)4]−\mathrm{[Al(OH)_4]^-} ion.
TypePairs (X + E)ShapeExamples
AX₂2LinearBeCl2\mathrm{BeCl_2}, CO2\mathrm{CO_2}, NO2+\mathrm{NO_2^+}, N3−\mathrm{N_3^-}, HC≡C−\mathrm{HC{\equiv}C^-}
AX₃3Trigonal planarBF3\mathrm{BF_3}, SO3\mathrm{SO_3}, NO3−\mathrm{NO_3^-}, CO32−\mathrm{CO_3^{2-}}
AX₂E3BentSO2\mathrm{SO_2}, O3\mathrm{O_3}, NO2−\mathrm{NO_2^-}
AX₄4TetrahedralCH4\mathrm{CH_4}, NH4+\mathrm{NH_4^+}, SO42−\mathrm{SO_4^{2-}}, SO2Cl2\mathrm{SO_2Cl_2}
AX₃E4Trigonal pyramidalNH3\mathrm{NH_3}, H3O+\mathrm{H_3O^+}, SO32−\mathrm{SO_3^{2-}}, ClO3−\mathrm{ClO_3^-}, BrO3−\mathrm{BrO_3^-}, XeO3\mathrm{XeO_3}
AX₂E₂4BentH2O\mathrm{H_2O}, OF2\mathrm{OF_2}, ClO2−\mathrm{ClO_2^-}, BrF2+\mathrm{BrF_2^+}
AX₅5Trigonal bipyramidalPCl5\mathrm{PCl_5}, PF5\mathrm{PF_5}, Fe(CO)5\mathrm{Fe(CO)_5}
AX₄E5See-sawSF4\mathrm{SF_4}, SeF4\mathrm{SeF_4}, IF4+\mathrm{IF_4^+}, XeO2F2\mathrm{XeO_2F_2}
AX₃E₂5T-shapedClF3\mathrm{ClF_3}, BrF3\mathrm{BrF_3}, IF3\mathrm{IF_3}
AX₂E₃5LinearXeF2\mathrm{XeF_2}, I3−\mathrm{I_3^-}, IBr2−\mathrm{IBr_2^-}
AX₆6OctahedralSF6\mathrm{SF_6}, [CrF6]3−\mathrm{[CrF_6]^{3-}}
AX₅E6Square pyramidalBrF5\mathrm{BrF_5}, IF5\mathrm{IF_5}, XeOF4\mathrm{XeOF_4}
AX₄E₂6Square planarXeF4\mathrm{XeF_4}, ICl4−\mathrm{ICl_4^-}, BrF4−\mathrm{BrF_4^-}
AX₇7Pentagonal bipyramidalIF7\mathrm{IF_7}
AX₆E7Distorted octahedralXeF6\mathrm{XeF_6}
Same total of pairs, same arrangement; the lone pairs decide the name of the shape.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2026 · 28 Jan 2026 Shift 2 · Q37Moderate

Example 1 · Chemical Bonding and Molecular Structure · Shapes of Molecules and Ions

Match List-I with List-II according to shape. List-I List-II (A) XeO3{XeO}_{3} (I) BrF5{BrF}_{5} (B) XeF2{XeF}_{2} (II) NH3{NH}_{3} (C) XeO2 F2{XeO}_{2}{\text{ }F}_{2} (III) [I3]−\left\lbrack I_{3} \right\rbrack^{-} (D) XeOF4{XeOF}_{4} (IV)  SF4\ {SF}_{4} Choose the correct answer from the options given below:

Name the shape from the atoms, not the pairs

NH3\mathrm{NH_3} has a tetrahedral arrangement of pairs, but its shape is trigonal pyramidal. XeF4\mathrm{XeF_4} has an octahedral arrangement, but it is square planar. Options often offer the arrangement as a decoy.

Same formula type, different shape

SF4\mathrm{SF_4} (see-saw) and XeF4\mathrm{XeF_4} (square planar) are both AF₄, and PCl5\mathrm{PCl_5} (trigonal bipyramidal) and BrF5\mathrm{BrF_5} (square pyramidal) are both AX₅ formulas. Count the lone pairs before naming the shape.

Concept 2 of 2: Counting species of one shape in a list

A list question is the AXE table used many times. Work through the list one species at a time, write X and E for each, and tick only those that match. Do not guess from the formula: the charge and the lone pairs change everything.

Definition

  • For each species: count the atoms bonded to the centre (X), find the lone pairs (E) from the steric number, name the shape.
  • Linear: AX₂ (BeCl2\mathrm{BeCl_2}, CO2\mathrm{CO_2}, C3O2\mathrm{C_3O_2}, N3−\mathrm{N_3^-}, NO2+\mathrm{NO_2^+}) or AX₂E₃ (XeF2\mathrm{XeF_2}, I3−\mathrm{I_3^-}). Not linear: I3+\mathrm{I_3^+} (AX₂E₂), BCl2−\mathrm{BCl_2^-} (AX₂E), SO2\mathrm{SO_2}, O3\mathrm{O_3}, NO2\mathrm{NO_2}, F2O\mathrm{F_2O}.
  • Planar species: any three-atom species, AX₃, AX₃E₂ (T-shaped) and AX₄E₂ (square planar). Pyramidal, tetrahedral, see-saw and bigger shapes are non-planar. H2O2\mathrm{H_2O_2} is not planar: its two O–H bonds lie in different planes.
  • Trigonal bipyramidal needs AX₅ with no lone pair: PF5\mathrm{PF_5}, PCl5\mathrm{PCl_5}, Fe(CO)5\mathrm{Fe(CO)_5}, not BrF5\mathrm{BrF_5}.

Worked example

How many of these are pyramidal: NH3\mathrm{NH_3}, BF3\mathrm{BF_3}, SO32−\mathrm{SO_3^{2-}}, ClO3−\mathrm{ClO_3^-}, NO3−\mathrm{NO_3^-}, PCl3\mathrm{PCl_3}, XeO3\mathrm{XeO_3}, SO3\mathrm{SO_3}?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2025 · 22 Jan 2025 · Q48Moderate

Example 2 · Chemical Bonding and Molecular Structure · Shapes of Molecules and Ions

The number of molecules/ions that show linear geometry among the following is _____\_\_\_\_\_ .
SO2,BeCl2,CO2, N3−,NO2, F2O,XeF2,NO2+,I3−,O3SO_{2},BeCl_{2},CO_{2},{\text{ }N}_{3}^{-},NO_{2},{\text{ }F}_{2}O,XeF_{2},NO_{2}^{+},I_{3}^{-},O_{3}

Charge changes the shape

I3−\mathrm{I_3^-} is linear (three lone pairs) but I3+\mathrm{I_3^+} is bent (two lone pairs). NO2+\mathrm{NO_2^+} is linear but NO2−\mathrm{NO_2^-} is bent. Always put the charge into the steric number.

Two nickel complexes, two shapes

Strong-field CN−\mathrm{CN^-} pairs up nickel's d electrons, so [Ni(CN)4]2−\mathrm{[Ni(CN)_4]^{2-}} is dsp2dsp^2 and square planar. Weak-field Cl−\mathrm{Cl^-} does not, so [NiCl4]2−\mathrm{[NiCl_4]^{2-}} is sp3sp^3 and tetrahedral.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Reference tables (1)

Shapes from the AXE formula15 rows
TypePairs (X + E)ShapeExamples
AX₂2LinearBeCl2\mathrm{BeCl_2}, CO2\mathrm{CO_2}, NO2+\mathrm{NO_2^+}, N3−\mathrm{N_3^-}, HC≡C−\mathrm{HC{\equiv}C^-}
AX₃3Trigonal planarBF3\mathrm{BF_3}, SO3\mathrm{SO_3}, NO3−\mathrm{NO_3^-}, CO32−\mathrm{CO_3^{2-}}
AX₂E3BentSO2\mathrm{SO_2}, O3\mathrm{O_3}, NO2−\mathrm{NO_2^-}
AX₄4TetrahedralCH4\mathrm{CH_4}, NH4+\mathrm{NH_4^+}, SO42−\mathrm{SO_4^{2-}}, SO2Cl2\mathrm{SO_2Cl_2}
AX₃E4Trigonal pyramidalNH3\mathrm{NH_3}, H3O+\mathrm{H_3O^+}, SO32−\mathrm{SO_3^{2-}}, ClO3−\mathrm{ClO_3^-}, BrO3−\mathrm{BrO_3^-}, XeO3\mathrm{XeO_3}
AX₂E₂4BentH2O\mathrm{H_2O}, OF2\mathrm{OF_2}, ClO2−\mathrm{ClO_2^-}, BrF2+\mathrm{BrF_2^+}
AX₅5Trigonal bipyramidalPCl5\mathrm{PCl_5}, PF5\mathrm{PF_5}, Fe(CO)5\mathrm{Fe(CO)_5}
AX₄E5See-sawSF4\mathrm{SF_4}, SeF4\mathrm{SeF_4}, IF4+\mathrm{IF_4^+}, XeO2F2\mathrm{XeO_2F_2}
AX₃E₂5T-shapedClF3\mathrm{ClF_3}, BrF3\mathrm{BrF_3}, IF3\mathrm{IF_3}
AX₂E₃5LinearXeF2\mathrm{XeF_2}, I3−\mathrm{I_3^-}, IBr2−\mathrm{IBr_2^-}
AX₆6OctahedralSF6\mathrm{SF_6}, [CrF6]3−\mathrm{[CrF_6]^{3-}}
AX₅E6Square pyramidalBrF5\mathrm{BrF_5}, IF5\mathrm{IF_5}, XeOF4\mathrm{XeOF_4}
AX₄E₂6Square planarXeF4\mathrm{XeF_4}, ICl4−\mathrm{ICl_4^-}, BrF4−\mathrm{BrF_4^-}
AX₇7Pentagonal bipyramidalIF7\mathrm{IF_7}
AX₆E7Distorted octahedralXeF6\mathrm{XeF_6}
Same total of pairs, same arrangement; the lone pairs decide the name of the shape.

Watch out for (4)

Test yourself on Chemical Bonding and Molecular Structure

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