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JEE Mains Chemistry · Coordination Compounds

Isomerism in Coordination Compounds

Structural isomers differ in which atoms are bonded to the metal; stereoisomers have the same bonds arranged differently in space, as cis–trans or fac–mer geometrical isomers and as non-superimposable mirror-image optical isomers.

Why this matters

Twenty-three PYQs, fifteen of them multiple choice, and two from 2026. Four name a type of structural isomerism; ten count geometrical isomers or pick the complex that shows cis–trans or fac–mer isomerism; nine count optical isomers or total stereoisomers, usually of an octahedral complex with bidentate ligands.

Concept 1 of 3: Types of structural isomerism in complexes

Structural isomers have the same formula but different bonds. Either a ligand bonds through a different atom (linkage), or a ligand and a counter-ion swap places (ionisation), or ligands swap between a complex cation and a complex anion (coordination), or water moves between the inner sphere and the crystal (solvate). A simple test tells ionisation isomers apart: each gives a different free ion in water.

Definition

  • Linkage: an ambidentate ligand bonds through a different atom: [Co(NH3)5(NO2)]2+\mathrm{[Co(NH_3)_5(NO_2)]^{2+}} (nitro, N-bonded, yellow) and [Co(NH3)5(ONO)]2+\mathrm{[Co(NH_3)_5(ONO)]^{2+}} (nitrito, O-bonded, red).
  • Ionisation: a ligand inside and an ion outside the bracket exchange: [Co(NH3)5SO4]Br\mathrm{[Co(NH_3)_5SO_4]Br} (gives AgBr with AgNO3\mathrm{AgNO_3}) and [Co(NH3)5Br]SO4\mathrm{[Co(NH_3)_5Br]SO_4} (gives BaSO4\mathrm{BaSO_4} with BaCl2\mathrm{BaCl_2}).
  • Coordination (NCERT definition): ligands exchange between the cationic and the anionic complex of DIFFERENT metal ions: [Co(NH3)6][Cr(CN)6]\mathrm{[Co(NH_3)_6][Cr(CN)_6]} and [Cr(NH3)6][Co(CN)6]\mathrm{[Cr(NH_3)_6][Co(CN)_6]}.
  • Solvate (hydrate): water inside versus outside the sphere: [Cr(H2O)6]Cl3\mathrm{[Cr(H_2O)_6]Cl_3} (violet), [Cr(H2O)5Cl]Cl2⋅H2O\mathrm{[Cr(H_2O)_5Cl]Cl_2\cdot H_2O}, [Cr(H2O)4Cl2]Cl⋅2H2O\mathrm{[Cr(H_2O)_4Cl_2]Cl\cdot 2H_2O}.
TypeWhat changesExample pair or memberHow to tell
LinkageDonor atom of an ambidentate ligand[Co(NH3)5(NO2)]Cl2\mathrm{[Co(NH_3)_5(NO_2)]Cl_2} and [Co(NH3)5(ONO)]Cl2\mathrm{[Co(NH_3)_5(ONO)]Cl_2}Colour and infrared spectrum differ
IonisationWhich anion is inside the bracket[Co(NH3)5SO4]Br\mathrm{[Co(NH_3)_5SO_4]Br} and [Co(NH3)5Br]SO4\mathrm{[Co(NH_3)_5Br]SO_4}AgNO3\mathrm{AgNO_3} test for the halide, BaCl2\mathrm{BaCl_2} test for sulphate
CoordinationWhich metal holds which ligands[Co(NH3)6][Cr(CN)6]\mathrm{[Co(NH_3)_6][Cr(CN)_6]} and [Cr(NH3)6][Co(CN)6]\mathrm{[Cr(NH_3)_6][Co(CN)_6]}Needs a complex cation AND a complex anion of different metals
Solvate (hydrate)Water inside or outside the sphere[Cr(H2O)6]Cl3\mathrm{[Cr(H_2O)_6]Cl_3} and [Cr(H2O)5Cl]Cl2⋅H2O\mathrm{[Cr(H_2O)_5Cl]Cl_2\cdot H_2O}Number of chlorides precipitated by AgNO3\mathrm{AgNO_3} (3 and 2)
Ionisation and hydrate isomers are told apart by what precipitates; linkage isomers need an ambidentate ligand.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2025 · 7 Apr 2025 · Q44Moderate

Example 1 · Coordination Compounds · Isomerism

An octahedral complex having molecular composition Co.5NH3.Cl2.SO4Co.5NH_{3}.Cl_{2}.SO_{4} has two isomers A and B . The solution of A gives a white precipitate with AgNO3AgNO_{3} solution and the solution of B gives white precipitate with BaCl2BaCl_{2} solution. The type of isomerism exhibited by the complex is,

Coordination isomerism needs two different metals

NCERT defines coordination isomerism as an exchange of ligands between the cationic and anionic complexes of DIFFERENT metal ions. By that definition [Co(NH3)6][Co(CN)6]\mathrm{[Co(NH_3)_6][Co(CN)_6]}, with cobalt in both ions, is not counted. A 2026 key follows this definition.

Ionisation isomers give different ions, not different amounts

[Co(NH3)5SO4]Cl\mathrm{[Co(NH_3)_5SO_4]Cl} gives chloride and [Co(NH3)5Cl]SO4\mathrm{[Co(NH_3)_5Cl]SO_4} gives sulphate. If one isomer precipitates with AgNO3\mathrm{AgNO_3} and the other with BaCl2\mathrm{BaCl_2}, the isomerism is ionisation, not linkage or coordination.

Concept 2 of 3: Geometrical isomers of square planar and octahedral complexes

Geometrical isomers differ in which ligands are next to each other (cis, 90° apart) and which are opposite (trans, 180°). A tetrahedron has every corner next to every other, so it never has cis–trans isomers. In an octahedron, three identical ligands can sit on one face (fac) or along a meridian through the metal (mer).

Definition

  • Tetrahedral (sp³) complexes: no geometrical isomers, whatever the ligands.
  • Square planar MA2B2\mathrm{MA_2B_2} and MA2BC\mathrm{MA_2BC}: cis and trans, 2 isomers. MABCD\mathrm{MABCD}: 3 isomers (fix A; B, C or D can be trans to it).
  • Octahedral MA4B2\mathrm{MA_4B_2} and M(AA)2B2\mathrm{M(AA)_2B_2}: cis and trans, 2 isomers.
  • Octahedral MA3B3\mathrm{MA_3B_3}: fac (all B–M–B angles 90°) and mer (B–M–B angles 90° and 180°), 2 isomers.
  • MA6\mathrm{MA_6}, MA5B\mathrm{MA_5B} and M(AA)3\mathrm{M(AA)_3}: no geometrical isomers.
TypeExampleGeometrical isomersNames
Tetrahedral MABCD\mathrm{MABCD}An sp³ complex MABXL0All corners equivalent
Square planar MA2B2\mathrm{MA_2B_2}[Pt(NH3)2Cl2]\mathrm{[Pt(NH_3)_2Cl_2]}2cis and trans (cisplatin is the cis form)
Square planar MABCD\mathrm{MABCD}[Pt(py)(NH3)BrCl]\mathrm{[Pt(py)(NH_3)BrCl]}3Each of B, C, D trans to A in turn
Octahedral MA4B2\mathrm{MA_4B_2}[Co(NH3)4Cl2]+\mathrm{[Co(NH_3)_4Cl_2]^+}2cis and trans
Octahedral MA3B3\mathrm{MA_3B_3}[Co(NH3)3Cl3]\mathrm{[Co(NH_3)_3Cl_3]}2fac and mer
Octahedral M(AA)2B2\mathrm{M(AA)_2B_2}[Co(en)2Cl2]+\mathrm{[Co(en)_2Cl_2]^+}2cis and trans (cis is also chiral)
Octahedral M(AA)3\mathrm{M(AA)_3}[Co(en)3]3+\mathrm{[Co(en)_3]^{3+}}0Only optical isomers
Octahedral MA5B\mathrm{MA_5B}[Co(CN)5(NC)]3−\mathrm{[Co(CN)_5(NC)]^{3-}}0One odd ligand has only one kind of position
Count geometrical isomers from the formula type; the metal and the ligands' names do not matter.
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The same idea in a real exam question:

JEE Mains · 2023 · 11 April 2023 · Q45Moderate

Example 2 · Coordination Compounds · Isomerism

Which of the following complex has a possibility to exist as meridional isomer?

Tetrahedral complexes have no cis–trans isomers

Every pair of corners of a tetrahedron is adjacent, so no ligand can be trans to another. An sp³ complex MABXL has 0 geometrical isomers, even with four different ligands.

Do not count the cis enantiomers as geometrical isomers

[Co(en)2Cl2]+\mathrm{[Co(en)_2Cl_2]^+} has 2 geometrical isomers, cis and trans. The cis form also has a mirror image, which makes 3 stereoisomers, but the extra one is an optical isomer.

Changing Ni²⁺ to Pt²⁺ changes the geometry

[NiCl2Br2]2−\mathrm{[NiCl_2Br_2]^{2-}} is tetrahedral and paramagnetic with no geometrical isomers. [PtCl2Br2]2−\mathrm{[PtCl_2Br_2]^{2-}} is square planar, diamagnetic and has cis and trans forms.

Concept 3 of 3: Optical isomers and total stereoisomers of octahedral complexes

A complex is optically active when it has no mirror plane and no centre of symmetry, so its mirror image cannot be laid on it. Chelate rings wrapped around an octahedron like a propeller do this: the cis forms of M(AA)2B2\mathrm{M(AA)_2B_2} and every M(AA)3\mathrm{M(AA)_3} come as left- and right-handed pairs. To count stereoisomers, list the geometrical isomers first, then double each one that is chiral.

Definition

  • M(AA)3\mathrm{M(AA)_3}, such as [Co(en)3]3+\mathrm{[Co(en)_3]^{3+}} or [Cr(C2O4)3]3−\mathrm{[Cr(C_2O_4)_3]^{3-}}: one geometrical form, chiral, so 2 stereoisomers (d and l).
  • M(AA)2B2\mathrm{M(AA)_2B_2} and M(AA)2BC\mathrm{M(AA)_2BC}: trans is achiral (a mirror plane holds both rings); cis is chiral. Total 3 stereoisomers.
  • MA3B3\mathrm{MA_3B_3}: fac and mer are both achiral, so 2 stereoisomers.
  • Square planar complexes are flat and always have a mirror plane: never optically active.

Counting stereoisomers

Nstereo=Nachiral geometrical+2 Nchiral geometricalN_{\text{stereo}} = N_{\text{achiral geometrical}} + 2\,N_{\text{chiral geometrical}}

Worked example

How many stereoisomers does [Co(en)2Cl2]+\mathrm{[Co(en)_2Cl_2]^+} have, and how many of them are optically active?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2023 · 13 April 2023 · Q125Moderate

Example 3 · Coordination Compounds · Isomerism

The total number of stereoisomers for the complex [Cr(ox)2ClBr]3−(\left\lbrack Cr(ox)_{2}ClBr \right\rbrack^{3 -}( where ox == oxalate )) is:

A stereoisomer count includes the optical isomers

[CrCl2(ox)2]3−\mathrm{[CrCl_2(ox)_2]^{3-}} has 2 geometrical isomers but 3 stereoisomers, because its cis form is chiral. [CrCl3(py)3]\mathrm{[CrCl_3(py)_3]} has 2 stereoisomers, since fac and mer are both achiral.

Look for the mirror plane, not for four different groups

The carbon rule of four different groups does not apply to complexes. cis-[PtCl2(en)2]2+\mathrm{[PtCl_2(en)_2]^{2+}}, with only two kinds of ligand, is chiral; trans-[Co(NH3)4Cl2]+\mathrm{[Co(NH_3)_4Cl_2]^+} is not.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (1)

Reference tables (2)

Types of structural isomerism in complexes4 rows
TypeWhat changesExample pair or memberHow to tell
LinkageDonor atom of an ambidentate ligand[Co(NH3)5(NO2)]Cl2\mathrm{[Co(NH_3)_5(NO_2)]Cl_2} and [Co(NH3)5(ONO)]Cl2\mathrm{[Co(NH_3)_5(ONO)]Cl_2}Colour and infrared spectrum differ
IonisationWhich anion is inside the bracket[Co(NH3)5SO4]Br\mathrm{[Co(NH_3)_5SO_4]Br} and [Co(NH3)5Br]SO4\mathrm{[Co(NH_3)_5Br]SO_4}AgNO3\mathrm{AgNO_3} test for the halide, BaCl2\mathrm{BaCl_2} test for sulphate
CoordinationWhich metal holds which ligands[Co(NH3)6][Cr(CN)6]\mathrm{[Co(NH_3)_6][Cr(CN)_6]} and [Cr(NH3)6][Co(CN)6]\mathrm{[Cr(NH_3)_6][Co(CN)_6]}Needs a complex cation AND a complex anion of different metals
Solvate (hydrate)Water inside or outside the sphere[Cr(H2O)6]Cl3\mathrm{[Cr(H_2O)_6]Cl_3} and [Cr(H2O)5Cl]Cl2⋅H2O\mathrm{[Cr(H_2O)_5Cl]Cl_2\cdot H_2O}Number of chlorides precipitated by AgNO3\mathrm{AgNO_3} (3 and 2)
Ionisation and hydrate isomers are told apart by what precipitates; linkage isomers need an ambidentate ligand.
Geometrical isomers of square planar and octahedral complexes8 rows
TypeExampleGeometrical isomersNames
Tetrahedral MABCD\mathrm{MABCD}An sp³ complex MABXL0All corners equivalent
Square planar MA2B2\mathrm{MA_2B_2}[Pt(NH3)2Cl2]\mathrm{[Pt(NH_3)_2Cl_2]}2cis and trans (cisplatin is the cis form)
Square planar MABCD\mathrm{MABCD}[Pt(py)(NH3)BrCl]\mathrm{[Pt(py)(NH_3)BrCl]}3Each of B, C, D trans to A in turn
Octahedral MA4B2\mathrm{MA_4B_2}[Co(NH3)4Cl2]+\mathrm{[Co(NH_3)_4Cl_2]^+}2cis and trans
Octahedral MA3B3\mathrm{MA_3B_3}[Co(NH3)3Cl3]\mathrm{[Co(NH_3)_3Cl_3]}2fac and mer
Octahedral M(AA)2B2\mathrm{M(AA)_2B_2}[Co(en)2Cl2]+\mathrm{[Co(en)_2Cl_2]^+}2cis and trans (cis is also chiral)
Octahedral M(AA)3\mathrm{M(AA)_3}[Co(en)3]3+\mathrm{[Co(en)_3]^{3+}}0Only optical isomers
Octahedral MA5B\mathrm{MA_5B}[Co(CN)5(NC)]3−\mathrm{[Co(CN)_5(NC)]^{3-}}0One odd ligand has only one kind of position
Count geometrical isomers from the formula type; the metal and the ligands' names do not matter.

Watch out for (7)

Test yourself on Coordination Compounds

20 past JEE Mains questions from this chapter, timed at 48 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.