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JEE Mains Chemistry · Hydrocarbons

Electrophilic Substitution: Reactivity and Directing Effects

Benzene keeps its aromatic ring by swapping an H for an electrophile made by an acid or a Lewis acid; a group already on the ring speeds or slows that swap and sends the new group ortho and para or meta.

Why this matters

Nineteen PYQs, fifteen of them multiple choice, and three from 2026. Five are about the electrophile itself: how HNO₃ and H₂SO₄ make NO₂⁺, what the Lewis acid does, and which rings cannot undergo Friedel–Crafts reactions. Seven classify groups as activating or deactivating and as ortho-para or meta directing. Seven put substituted benzenes in order of reactivity. Four of the nineteen ask for a number.

Concept 1 of 3: Making the electrophile, and when Friedel–Crafts fails

Benzene's π cloud is only weakly nucleophilic, so every aromatic substitution first builds a strong, positive electrophile. A proton acid or a Lewis acid does this. The electrophile then adds to the ring to give a carbocation (the arenium ion or σ-complex), and loss of H⁺ restores the aromatic ring. A Friedel–Crafts reaction fails when the ring is too electron-poor, or when a basic nitrogen on the ring grabs the Lewis acid.

Definition

  • Nitration: HNO3+2H2SO4⇌NO2++H3O++2HSO4−\mathrm{HNO_3 + 2H_2SO_4 \rightleftharpoons NO_2^+ + H_3O^+ + 2HSO_4^-}. H₂SO₄ is the acid; HNO₃ accepts a proton, acting as a base.
  • Halogenation: Cl2+AlCl3→Cl++AlCl4−\mathrm{Cl_2 + AlCl_3 \rightarrow Cl^+ + AlCl_4^-} (or FeCl₃, FeBr₃).
  • Sulphonation: SO₃ from conc. H₂SO₄ or oleum.
  • Friedel–Crafts: RCl+AlCl3→R++AlCl4−\mathrm{RCl + AlCl_3 \rightarrow R^+ + AlCl_4^-}; RCOCl+AlCl3→RCO++AlCl4−\mathrm{RCOCl + AlCl_3 \rightarrow RCO^+ + AlCl_4^-}. The catalyst is a Lewis ACID.
  • Friedel–Crafts fails with strongly deactivated rings (–NO₂, –CN, –COR, –SO₃H on the ring) and with –NH₂, –NHR, –NR₂ (the N lone pair binds AlCl₃ and the ring becomes positively charged).
ReactionReagentsElectrophileProduct from benzene
NitrationConc. HNO₃ + conc. H₂SO₄NO2+\mathrm{NO_2^+} (nitronium)Nitrobenzene
ChlorinationCl₂ with anhydrous AlCl₃ or FeCl₃Cl+\mathrm{Cl^+}Chlorobenzene
SulphonationFuming H₂SO₄ (oleum)SO3\mathrm{SO_3}Benzenesulphonic acid
Friedel–Crafts alkylationCH₃Cl with anhydrous AlCl₃CH3+\mathrm{CH_3^+}Toluene
Friedel–Crafts acylationCH₃COCl with anhydrous AlCl₃CH3CO+\mathrm{CH_3CO^+} (acylium)Acetophenone
Every electrophile is made by an acid or a Lewis acid; the ring then loses H⁺ to stay aromatic.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2024 · 9 April 2024 · Q148Moderate

Example 1 · Hydrocarbons · Electrophilic Substitution: Reactivity and Directing Effects

Number of compounds from the following which cannot undergo Friedel-Crafts reactions is :______toluene, nitrobenzene, xylene, cumene, aniline, chlorobenzene, m-nitroaniline, m-dinitrobenzene

AlCl₃ is a Lewis acid, not a Lewis base

AlCl₃ has an empty orbital and accepts Cl⁻. A statement calling the Friedel–Crafts catalyst a Lewis base is wrong.

Chlorobenzene still reacts

A halogen deactivates the ring only weakly, so chlorobenzene does undergo Friedel–Crafts reactions (para mainly). Only strongly deactivated rings and rings bearing an amino N fail.

Concept 2 of 3: Activating, deactivating, ortho-para and meta directors

A group that pushes electrons into the ring (by a lone pair, +R, or by alkyl groups, +I and hyperconjugation) makes the ring richer and the reaction faster, and the extra density sits at the ortho and para positions. A group that pulls electrons out (–R, –I) slows the reaction and leaves the meta position the least starved. Halogens are the one mixed case: they pull by –I, so they deactivate, but their lone pairs still send the electrophile ortho and para.

Definition

  • Activating, ortho-para: –NH₂, –NHR, –NR₂, –OH, –OCH₃, –NHCOCH₃, –CH₃ and other alkyl groups.
  • Deactivating, ortho-para: –F, –Cl, –Br, –I.
  • Deactivating, meta: –NO₂, –CN, –CHO, –COR, –COOH, –COOR, –SO₃H, –CF₃, –NR₃⁺.
  • With two groups, the stronger activator decides where the next group goes; nothing enters between two meta groups easily.
  • –NO₂ deactivates the ring to ELECTROPHILES but activates it (at ortho and para) to NUCLEOPHILIC substitution.
GroupMain electronic effectRate compared with benzeneDirects to
–NH₂, –NR₂+R (strong)Much fasterortho and para
–OH, –OCH₃+R (strong)Much fasterortho and para
–NHCOCH₃+R (moderate; the lone pair is shared with C=O)Fasterortho and para
–CH₃, –C₂H₅+I and hyperconjugationSlightly fasterortho and para
–Cl, –Br–I stronger than +RSlightly slowerortho and para
–CHO, –COR, –COOH, –COOR–R and –ISlowermeta
–CN, –SO₃H, –CF₃–R and –I (–CF₃ by –I only)Much slowermeta
–NO₂–R and –I (strongest)Much slowermeta
Every activator directs ortho and para; every meta director deactivates; halogens deactivate yet direct ortho and para.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2025 · 24 Jan 2025 · Q114Moderate

Example 2 · Hydrocarbons · Electrophilic Substitution: Reactivity and Directing Effects

Identify correct statement/s : (A) −OCH3-OCH_{3} and −NHCOCH3-NHCOCH_{3} are activating group (B) -CN and -OH are meta directing group (C) -CN and −SO3H-SO_{3}H are meta directing group (D) Activating groups act as ortho - and para directing groups (E) Halides are activating groups Choose the correct answer from the options given below :

Halogens deactivate but direct ortho and para

A halogen is neither an activator nor a meta director. It slows the reaction (–I) but its lone pair steers the electrophile ortho and para.

–OH and –OCH₃ are never meta directors

Any group with a lone pair on the atom attached to the ring is ortho-para directing. –NHCOCH₃ is weaker than –NH₂ but is still activating.

Nitro activates for the other kind of substitution

–NO₂ makes the ring electron-poor. That hinders electrophiles but helps a nucleophile replace a halogen ortho or para to it.

Concept 3 of 3: Ranking rings by rate of electrophilic substitution

The electron-richer the ring, the faster an electrophile attacks it. So rank each ring by its strongest group, then by how many groups it carries. Strong +R donors (–NR₂, –OH, –OR) come first, alkyl groups next (more alkyls, faster), plain benzene in the middle, halogens just below it, carbonyl groups lower, and nitro last.

Definition

  • Order of the groups, fastest first: –NR₂ > –NH₂ > –OH > –OCH₃ > –NHCOCH₃ > –CH₃ > –H > –Cl, –Br > –CHO, –COR > –CN > –NO₂.
  • More alkyl groups add up: 1,3,5-trimethylbenzene > xylene > toluene > benzene.
  • Two strong withdrawing groups (m-dinitrobenzene) make the ring slower still.
CompoundGroupEffect on the ringPlace in rate order
N,N-Dimethylaniline–N(CH₃)₂Strong +RFastest of this list
Anisole–OCH₃Strong +RSecond
Toluene–CH₃+I and hyperconjugationThird
Benzene–HReferenceFourth
Chlorobenzene–Cl–I beats +RFifth
Benzaldehyde–CHO–R and –ISixth
Benzonitrile–CN–R and –ISeventh
Nitrobenzene–NO₂Strongest –R and –ISlowest of this list
Rank by the strongest group on each ring; alkyl groups add up, and each extra withdrawing group slows the ring further.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2022 · 28 July 2022 · Q133Moderate

Example 3 · Hydrocarbons · Electrophilic Substitution: Reactivity and Directing Effects

Arrange the following in increasing order of reactivity towards nitration A. p-xylene B. bromobenzene C. mesitylene DD, nitrobenzene E. benzene Choose the correct answer from the options given below

Halogenobenzenes are slower than benzene

It is tempting to put chlorobenzene or bromobenzene above benzene because halogens direct ortho and para. They are still deactivating, so they come just below benzene.

Count the alkyl groups

Each methyl adds electron density, so a trimethylbenzene beats a dimethylbenzene, which beats toluene.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Reference tables (3)

Making the electrophile, and when Friedel–Crafts fails5 rows
ReactionReagentsElectrophileProduct from benzene
NitrationConc. HNO₃ + conc. H₂SO₄NO2+\mathrm{NO_2^+} (nitronium)Nitrobenzene
ChlorinationCl₂ with anhydrous AlCl₃ or FeCl₃Cl+\mathrm{Cl^+}Chlorobenzene
SulphonationFuming H₂SO₄ (oleum)SO3\mathrm{SO_3}Benzenesulphonic acid
Friedel–Crafts alkylationCH₃Cl with anhydrous AlCl₃CH3+\mathrm{CH_3^+}Toluene
Friedel–Crafts acylationCH₃COCl with anhydrous AlCl₃CH3CO+\mathrm{CH_3CO^+} (acylium)Acetophenone
Every electrophile is made by an acid or a Lewis acid; the ring then loses H⁺ to stay aromatic.
Activating, deactivating, ortho-para and meta directors8 rows
GroupMain electronic effectRate compared with benzeneDirects to
–NH₂, –NR₂+R (strong)Much fasterortho and para
–OH, –OCH₃+R (strong)Much fasterortho and para
–NHCOCH₃+R (moderate; the lone pair is shared with C=O)Fasterortho and para
–CH₃, –C₂H₅+I and hyperconjugationSlightly fasterortho and para
–Cl, –Br–I stronger than +RSlightly slowerortho and para
–CHO, –COR, –COOH, –COOR–R and –ISlowermeta
–CN, –SO₃H, –CF₃–R and –I (–CF₃ by –I only)Much slowermeta
–NO₂–R and –I (strongest)Much slowermeta
Every activator directs ortho and para; every meta director deactivates; halogens deactivate yet direct ortho and para.
Ranking rings by rate of electrophilic substitution8 rows
CompoundGroupEffect on the ringPlace in rate order
N,N-Dimethylaniline–N(CH₃)₂Strong +RFastest of this list
Anisole–OCH₃Strong +RSecond
Toluene–CH₃+I and hyperconjugationThird
Benzene–HReferenceFourth
Chlorobenzene–Cl–I beats +RFifth
Benzaldehyde–CHO–R and –ISixth
Benzonitrile–CN–R and –ISeventh
Nitrobenzene–NO₂Strongest –R and –ISlowest of this list
Rank by the strongest group on each ring; alkyl groups add up, and each extra withdrawing group slows the ring further.

Watch out for (7)

Test yourself on Hydrocarbons

20 past JEE Mains questions from this chapter, timed at 48 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.