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JEE Mains Chemistry · Some Basic Concepts of Chemistry

Gas Laws and Gas Volumes

PV = nRT and its special cases, gas volumes in reactions, and Dalton's law of partial pressures.

Why this matters

Thirty PYQs, twenty-one of them numerical and two from 2026. Sixteen use the ideal gas equation or one of its special cases, a few of them on real gases and molecular speeds. Seven turn a reaction into a volume of gas, and seven split a total pressure into partial pressures. Units decide most of the wrong answers here.

Concept 1 of 3: The ideal gas equation and its special cases

PV=nRTPV=nRT contains every gas law. Hold two of PP, VV, TT and nn fixed and the other two are in direct or inverse proportion. Put n=mMn=\frac{m}{M} and it gives the molar mass from a mass or a density.

Definition

  • PV=nRTPV=nRT, with R=0.0821R=0.0821 L atm K−1^{-1} mol−1^{-1} =0.083=0.083 L bar K−1^{-1} mol−1^{-1} =8.314=8.314 J K−1^{-1} mol−1^{-1}.
  • Units: TT in kelvin; 1 atm =760=760 torr =760=760 mmHg; 1 bar =105=10^{5} Pa; 1 dm3=1^3=1 L.
  • Boyle: P1V1=P2V2P_1V_1=P_2V_2. Charles: V1T1=V2T2\frac{V_1}{T_1}=\frac{V_2}{T_2}. A rigid tank: P1T1=P2T2\frac{P_1}{T_1}=\frac{P_2}{T_2}.
  • M=dRTPM=\frac{dRT}{P}. At fixed TT, a plot of PP against dd is a straight line through the origin, and PVPV against PP is flat.
  • Real gas: Z=PVnRTZ=\frac{PV}{nRT}; at high pressure Z=1+PbRTZ=1+\frac{Pb}{RT}. Units: aa in atm dm6^6 mol−2^{-2}, bb in dm3^3 mol−1^{-1}.
  • Speeds: urms=3RTMu_{rms}=\sqrt{\frac{3RT}{M}}, ump=2RTMu_{mp}=\sqrt{\frac{2RT}{M}}, uavg=8RTπMu_{avg}=\sqrt{\frac{8RT}{\pi M}}.

Ideal gas equation

PV=nRT=mMRT⇒M=dRTPPV=nRT=\frac{m}{M}RT\quad\Rightarrow\quad M=\frac{dRT}{P}

Worked example

1.61.6 g of a gas fills a 1.01.0 L flask at 1.231.23 atm and 300 K. Find its molar mass (R=0.082R=0.082 L atm K−1^{-1} mol−1^{-1}).
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2022 · 26 June 2022 · Q32Moderate

Example 1 · Some Basic Concepts of Chemistry · Gas Laws and Gas Volumes

An evacuated glass vessel weighs 40.0 g40.0\text{ }g when empty, 135.0 g135.0\text{ }g when filled with a liquid of density 0.95 g mL−10.95\text{ }g{\text{ }mL}^{- 1} and 40.5 g40.5\text{ }g when filled with an ideal gas at 0.82 atm0.82\text{ }atm at 250 K250\text{ }K. The molar mass of the gas in gmol−1gmol^{- 1} is: (Given: R=0.082 L atm K−1 mol−1R = 0.082\text{ }L\text{ }atm{\text{ }K}^{- 1}{\text{ }mol}^{- 1} )

Celsius in the gas equation

Every TT in PV=nRTPV=nRT and in the gas laws is in kelvin. Using 27 for 27 °C instead of 300 changes the answer by a factor of about eleven.

Match R to the units

0.082 goes with atm and litres, 0.083 with bar and litres, 8.314 with pascals and cubic metres. Mixing them is off by a factor of 1000 or more.

Concept 2 of 3: Gas volumes in reactions

At one temperature and pressure, equal volumes hold equal moles. So the coefficients of a gas reaction are also its volume ratios, and the moles of a metal turn straight into litres of hydrogen.

Definition

  • Gay-Lussac: gases react in volumes in the ratio of their coefficients, measured at the same TT and PP.
  • Mg+2HCl→MgCl2+H2\mathrm{Mg+2HCl\rightarrow MgCl_2+H_2}: 1 mol of H2\mathrm{H_2} per mol of Mg. 2Al+6HCl→2AlCl3+3H2\mathrm{2Al+6HCl\rightarrow2AlCl_3+3H_2}: 1.51.5 mol of H2\mathrm{H_2} per mol of Al.
  • V=n×VmV=n\times V_m, with VmV_m as the stem states: 22.4 or 22.7 L.
  • Fixed volume and temperature: pressures follow the moles. For A(g)→2B(g)+12C(g)\mathrm{A(g)\rightarrow2B(g)+\tfrac12C(g)}, a fraction α\alpha reacted gives P=P0(1+32α)P=P_0\left(1+\tfrac32\alpha\right).

Volume from moles

Vgas=n Vm,VAVB=νAνBV_{\text{gas}}=n\,V_m,\qquad\frac{V_A}{V_B}=\frac{\nu_A}{\nu_B}

Worked example

What volume of H2\mathrm{H_2} at STP (22.4 L mol−1^{-1}) forms when 5.45.4 g of Al reacts with excess HCl?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2023 · 31 January 2023 · Q55Moderate

Example 2 · Some Basic Concepts of Chemistry · Gas Laws and Gas Volumes

Zinc reacts with hydrochloric acid to give hydrogen and zinc chloride. The volume of hydrogen gas produced at STP from the reaction of 11.5 g11.5\text{ }g of zinc with excess HClHCl is LL (Nearest integer)
 (Given : Molar mass of Zn is 65.4 g mol−1 and Molar volume of H2 at STP=22.7 L )\text{~(Given : Molar mass of~}Zn\text{~is~}65.4\text{ }g{\text{ }mol}^{- 1}\text{~and Molar volume of~}H_{2}\text{~at~}STP = 22.7\text{ }L\text{~)}

Only gases count

Coefficients are volume ratios only for gases at one temperature and pressure. A solid, or water that has condensed, adds no gas volume.

Concept 3 of 3: Partial pressures and gas mixtures

Each gas in a mixture pushes as if it were alone in the vessel. Its share of the total pressure is its share of the moles, so change masses to moles before you split the pressure.

Definition

  • pi=xiPp_i=x_iP, with xi=ni∑nx_i=\frac{n_i}{\sum n}; and P=∑piP=\sum p_i.
  • From a mass percentage: take 100 g, convert each gas to moles, then find xx.
  • Bulbs joined at one temperature: P=∑PiVi∑ViP=\frac{\sum P_iV_i}{\sum V_i}.
  • Moist gas: only the dry gas obeys Boyle's law. While liquid water remains, the water vapour pressure stays the same.

Dalton's law

pi=xiP=nintotal Pp_i=x_iP=\frac{n_i}{n_{\text{total}}}\,P

Worked example

A mixture of 1616 g of O2\mathrm{O_2} and 77 g of N2\mathrm{N_2} has a total pressure of 1.51.5 atm. Find the partial pressure of O2\mathrm{O_2}.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2023 · 31 January 2023 · Q58Moderate

Example 3 · Some Basic Concepts of Chemistry · Gas Laws and Gas Volumes

The total pressure of a mixture of non-reacting gases X(0.6 g)X(0.6\text{ }g) and Y(0.45 g)Y(0.45\text{ }g) in a vessel is 740 mm740\text{ }mm of HgHg. The partial pressure of the gas XX is mmmm of HgHg. (Nearest Integer) (Given: molar mass X=20X = 20 and Y=45 g mol−1Y = 45\text{ }g{\text{ }mol}^{- 1} )

Mass fraction is not mole fraction

A mixture that is 40%40\% hydrogen by mass is over 90%90\% hydrogen by moles, because H2\mathrm{H_2} is so light. Convert to moles first.

Moist gas: only the dry part changes

When the volume changes, the water vapour pressure stays fixed as long as liquid remains. Apply Boyle's law to the dry gas, then add the vapour pressure back.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (3)

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